Slide 1EE100 Summer 2008Bharathwaj Muthuswamy EE100Su08 Lecture #13 (July 25 th 2008) Outline –MultiSim licenses: postponed to Monday, July 28 th 2008.

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Slide 1EE100 Summer 2008Bharathwaj Muthuswamy EE100Su08 Lecture #13 (July 25 th 2008) Outline –MultiSim licenses: postponed to Monday, July 28 th 2008 Apparently our license number is not working! Thanks for coming to lecture today! –HW #2: regrade deadline: Monday, 07/28, 5:00 pm PST. –Midterm #1 regrades: I will finish em by office hours today. –QUESTIONS? –Strain Gauge and Project: Lab Lecture WARNING: BE REALLY CAREFUL AROUND THE STRAIN GAUGE SINCE THE APPARATUS “STICKS OUT” OF THE TABLE! –Frequency Response and Bode plots –Nonlinear circuits Reading –Chapter 9 from your book (skip 9.10, 9.11 (duh)), Appendix E* (skip second-order resonance bode plots) –Chapter 1 from your reader (skip second-order resonance bode plots)

Slide 2EE100 Summer 2008Bharathwaj Muthuswamy

Slide 3EE100 Summer 2008Bharathwaj Muthuswamy

Slide 4EE100 Summer 2008Bharathwaj Muthuswamy

Slide 5EE100 Summer 2008Bharathwaj Muthuswamy

Slide 6EE100 Summer 2008Bharathwaj Muthuswamy

Slide 7EE100 Summer 2008Bharathwaj Muthuswamy Example Circuit  + AV T R2R2 R1R1 + VTVT + V OUT C V IN + A = 100 R 1 = 100,000 Ohms R 2 = 1000 Ohms C = 10 uF

Slide 8EE100 Summer 2008Bharathwaj Muthuswamy Example Circuit  + AV T R2R2 R1R1 + VTVT + V OUT C V IN + A = 100 R 1 = 100,000 Ohms R 2 = 1000 Ohms C = 10 uF

Slide 9EE100 Summer 2008Bharathwaj Muthuswamy Example Circuit  + AV T R2R2 R1R1 + VTVT + V OUT C V IN + A = 100 R 1 = 100,000 Ohms R 2 = 1000 Ohms C = 10 uF

Slide 10EE100 Summer 2008Bharathwaj Muthuswamy Break Point Values When dealing with resonant circuits it is convenient to refer to the frequency difference between points at which the power from the circuit is half that at the peak of resonance. Such frequencies are known as “half-power frequencies”, and the power output there referred to the peak power (at the resonant frequency) is 10log 10 (P half-power /P resonance ) = 10log 10 (1/2) = -3 dB.

Slide 11EE100 Summer 2008Bharathwaj Muthuswamy Example: Circuit in Slide #2 Magnitude Radian Frequency A = 100 R 2 = 1000 Ohms C = 10 uF w p = 1/(R 2 C) = 100 A Magnitude Actual value =

Slide 12EE100 Summer 2008Bharathwaj Muthuswamy Bode Plot: Label as dB Radian Frequency A = 100 R 2 = 1000 Ohms C = 100 uF w p = 1/(R 2 C) = 100 A Magnitude in dB Note: Magnitude in dB = 20 log 10 (V OUT /V IN )