Lecture 9: Operational Amplifiers

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Presentation transcript:

Lecture 9: Operational Amplifiers Today, we will introduce our first integrated circuit element: the operational amplifier. The operational amplifier, or op-amp, has three terminals*: V+ is called the non-inverting input terminal. V- is called the inverting input terminal. VO is called the output terminal. * There are actually more connections to the device that are not shown. The device connects to a power supply, which is needed for proper operation, as well as ground. +  V+ V V0

I-V Relationship The I-V relationship for the op-amp is complicated, since it has multiple terminals. The op-amp can be modeled using the following circuit: You can simply replace the op-amp symbol with the above circuit for analysis. However, the above model is only valid when VO is within a certain range. +  V0 AV1 V1 Ri Circuit Model in linear region Ro

Rails and Saturation The output VO must lie within a range determined by the supply voltages, which are not shown. It will limit or “clip” if VO attempts to exceed the boundaries. We call the limits of the output the “rails”. In the linear region, the op-amp output voltage VO is equal to the gain A times the voltage across the input terminals. You can “blindly” use the linear region model, and check if the output exceeds a rail. If so, the output is equal to that rail voltage. V0 lower rail upper rail Slope is A

Example: Voltage Follower Find the output voltage. Assume the rails are not exceeded. V0 +  VIN +  V0 AV1 - V1 Ri Ro VIN

Ideal Op-Amp Assumptions While we can always use our circuit model for the linear region, it is complicated. Ri is usually very large. RO is usually very small. A is usually very large (like 103 to 106). Thus, we can make the following ideal assumptions for easier, but still pretty accurate, analysis: Assume A = ∞. Assume Ri = ∞. Assume Ro = 0 W +  V0 AV1 V1 Ri Circuit Model Ro

Ideal Op-Amp Model Our idealized op-amp follows these rules within the linear region: Rule 1: V+ - V- = 0. Why? If the output voltage is limited by rails, and the gain A is very large, then V+ - V- must be very small. Rule 2: No current goes in/out of the input terminals. Why? V+ - V- is very small and Ri is very large. Remember current can go into/out the output terminal. Why? There are connections not shown, and the current comes from those connections. +  V0 AV1 V1 Ri Ro +  V+ V V0

Example: Voltage Follower Find the output voltage. Assume the rails are not exceeded. V0 +  VIN VO = VIN

Utility of Voltage Follower Suppose I have a voltage coming out of a digital circuit. I want to apply the voltage to “turn on” some device that requires high power (the device “drains” a substantial amount of current). Digital circuits usually cannot provide much current; they are designed for low power consumption. If we put a voltage follower between the digital circuit and the load, the voltage follower replicates the desired voltage, and can also provide current through its power supply. +  Digital Circuit

Op-Amp Circuits Op-Amp circuits usually take some input voltage and perform some “operation” on it, yielding an output voltage. Some tips on how to find the output, given the input: Step 1: KVL around input loop (involves Vin and op-amp inputs) Use Rule 1: V+-V- = 0 Step 2: Find the current in the feedback path Use Rule 2: No current into/out of op-amp inputs Step 3: KVL around output loop (involves Vo and feedback path) Remember current can flow in/out op-amp output

Example: Inverting Amplifier Feedback Path VIN R1 R2 Input Loop  V0 + Output Loop

Example: Inverting Summing Amplifier +  V3 V2 RF R1 R2 R3

Non-inverting Amplifier Vo

Important Points The amplifier output voltage does not depend on the “load” (what is attached to the output). The “form” of the output voltage (the signs of the scaling factors on the input voltages, for example) depends on the amplifier circuit layout. To change the values (magnitudes) of scaling factors, adjust resistor values. Input voltages which are attached to the + (non-inverting) amplifier terminal get positive scaling factors. Inputs attached to the – (inverting) terminal get negative scaling factors. You can use these principles to design amplifiers which perform a particular function on the input voltages.

Example: Voltage Divider Suppose I want to use the following circuit to supply a certain fraction of VIN to whatever I attach. What is VO if nothing is attached? What is VO if a 1 kW resistor is attached? This circuit clearly does not supply the same voltage to any attached load. What could I add to the circuit so that it will supply the same fraction of VIN to any attached device?

Example Design a circuit whose output is the sum of two input voltages.

Example Design a circuit whose output is the average of two input voltages.