Geometry Bisector of Triangles CONFIDENTIAL
Warm up Determine whether each point is on the perpendicular bisector of the segment with endpoints S(0,8) and T(4,0). 1) X(0,3) 2) Y(-4,1) 3) Z(-8,-2) yes no CONFIDENTIAL
Bisector of Triangles Since a triangle has three sides, it has three perpendicular bisector. When you construct the perpendicular bisectors, you find that they have an interesting property. CONFIDENTIAL
Draw a large scalene acute triangle ABC on a piece of patty paper. 1 2 3 B A B P C A C A C Draw a large scalene acute triangle ABC on a piece of patty paper. Fold the perpendicular bisector of each side. Label the point where the three perpendicular bisectors intersect as P. CONFIDENTIAL
When three or more lines intersect at one point, the lines are said to be concurrent. The point of concurrency is the point where they intersect. In the construction, you saw that the three perpendicular bisectors of a triangle are concurrent. This point of concurrency is the circumcenter of the triangle. CONFIDENTIAL
Circumcenter Theorem Theorem 2.1 B The circumcenter of a triangle is equidistant from the vertices of the triangle. PA = PB = PC P A B C CONFIDENTIAL
The circumcenter can be inside the triangle, Out the triangle, or on the triangle. P Acute triangle Obtuse triangle Right triangle CONFIDENTIAL
The circumcenter of ∆ABC is the center of its circumscribed circle The circumcenter of ∆ABC is the center of its circumscribed circle. A circle that contains all the vertices of a polygon is circumscribed about the polygon. B P A C CONFIDENTIAL
Circumcenter Theorem A l n P B C m CONFIDENTIAL
Using Properties of Perpendicular Bisector H J G K L 19.9 Z M 18.6 14.5 9.5 Z is the circumcenter of ∆GHJ. By the Circumcenter Theorem, Z is equidistant from the vertices of ∆GHJ. HZ = GZ Circumcenter Thm. HZ = 19.9 Substitute 19.9 for GZ. CONFIDENTIAL
Use the diagram. Find each length. Now you try! Use the diagram. Find each length. a) GM b) GK c) JZ H J G K L 19.9 Z M 18.6 14.5 9.5 1a) 14.5 1b) 18.6 1c) 19.9 CONFIDENTIAL
Finding the Circumcenter of a Triangle. Finding the circumcenter of ∆RSO with vertices R(-6,0), S(0,4), and O (0,0). Step 1 Graph the triangle. y X = -4 S Y = 2 (-3,2) x R 4 O Next page: CONFIDENTIAL
Step 2 Find equation for two perpendicular bisectors. Since Two sides of the triangle lie along the axes, use the graph to find the perpendicular bisectors of these two sides. The perpendicular bisector of RO is x = -3, and the perpendicular bisector of OS is y =2. y X = -4 S Y = 2 (-3,2) x R 4 O Next page: CONFIDENTIAL
Step 3 Find the intersection of the two equations. The lines x = -3 and y = z intersect at (-3,2), the circumcenter of ∆RSO. y X = -4 S Y = 2 (-3,2) x R 4 O CONFIDENTIAL
2) Find the circumcenter of ∆GOH with vertices Now you try! 2) Find the circumcenter of ∆GOH with vertices G(0,-9), O(0,0), and H(8,0). 2) 29 CONFIDENTIAL
Theorem 2.2 Incenter Theorem The incenter of a triangle is equidistant from the sides of the triangle. PX = PY = PZ B Z Y P C A X CONFIDENTIAL
Unlike the circumcenter, the incenter is always inside the triangle. P P P Acute triangle Obtuse triangle Right triangle CONFIDENTIAL
The incenter is the center of the triangle’s inscribed circle The incenter is the center of the triangle’s inscribed circle. A circle inscribed in a polygon intersects each line that contains a side of the polygon at exactly one point. P A B C CONFIDENTIAL
Using Properties of Angle Bisectors K A) The distance from V to KL 7.3 V is the incenter of ∆JKL. By the Incenter Theorem, V is equidistant from the sides of ∆JKL. The distance from V to JK is 7.3. So the distance from V to KL is also 7.3 W V 106˚ J L 19˚ Next page: CONFIDENTIAL
JV is the bisector of m/ kJL. Substitute 19˚ for m / VJL. ∆ sum Thm. K B) m/ Vkl JV is the bisector of m/ kJL. Substitute 19˚ for m / VJL. ∆ sum Thm. K m/ kJL = 2m / VJL m/ kJL = 2(19˚) = 38˚ m/ kJL + m/ JLK + m/ JKL = 180˚ 38 + 106 + m/ JKL = 180˚ m/ JKL = 36˚ m/ Vkl = ½ m/ JKL m/ Vkl = ½ (36˚) = 18˚ Substitute the given values. Subtract 144˚ from both sides. 7.3 W KV is the bisector of m/ JKL V Substitute 36˚ for m/ JKL. 106˚ L 19˚ CONFIDENTIAL
Now you try! 3) QX and RX are angle bisectors ∆PQR. Find each measure. The distance from X to PQ m/ PQX Q X 3a) 14.5 3b) 18.6 R P 12˚ Y 19.2 CONFIDENTIAL
Community Application The city of Odessa will host a fireworks display for the next Fourth of July celebration. Draw a sketch to show where the display should be positioned so that it is the same distance from all three viewing location A, B, and C on the map. Justify your sketch. A Let the three viewing locations be vertices of a triangle. By the Circumcenter Theorem, the circumcenter of the triangle is equidistant from the vertices. C B Next page: CONFIDENTIAL
Trace the map. Draw the triangle formed by the viewing locations Trace the map. Draw the triangle formed by the viewing locations. To find the circumcenter, find the perpendicular bisectors of each side. The position of the display is the circumcenter, F. A B C F CONFIDENTIAL
Now you try! 4) A City plans to build a firefighters’ monument in the park between three streets. Draw a sketch to show where the city should place the monument so that it is the same distance from all three streets. Justify your sketch. Centerville Anverue King Boulevard Third Street CONFIDENTIAL
Now some practice problems for you! CONFIDENTIAL
Assessment SN, TN, and VN are the perpendicular bisectors of ∆PQR. Find each length. 1) NR 2) RV 3) TR 4) QN Q 3.95 S N T 5.64 4.03 P R 5.47 V CONFIDENTIAL
Find the circumcenter of a triangle with the given vertices. 5) O(0,0), K(0, 12), L(4,0) 6) A(-7,0), O(0,0),B(0,-10) CONFIDENTIAL
CF and EF are angle bisectors of ∆CDE. Find each measure. 7) The distance from F to CD 8) m/ FED C D E G F 42.1 54˚ 17˚ CONFIDENTIAL
9) The designer of the Newtown High School pennant wants the circle around the bear emblem to be as large as possible. Draw a sketch to show where the center of the circle should be located. Justify your sketch. BEARS CONFIDENTIAL
Let’s review Bisector of Triangles Since a triangle has three sides, it has three perpendicular bisector. When you construct the perpendicular bisectors, you find that they have an interesting property. CONFIDENTIAL
Draw a large scalene acute triangle ABC on a piece of patty paper. 1 2 3 B A B P C A C A C Draw a large scalene acute triangle ABC on a piece of patty paper. Fold the perpendicular bisector of each side. Label the point where the three perpendicular bisectors intersect as P. CONFIDENTIAL
When three or more lines intersect at one point, the lines are said to be concurrent. The point of concurrency is the point where they intersect. In the construction, you saw that the three perpendicular bisectors of a triangle are concurrent. This point of concurrency is the circumcenter of the triangle. CONFIDENTIAL
Theorem 2.1 Circumcenter Theorem B The circumcenter of a triangle is equidistant from the vertices of the triangle. PA = PB = PC P C A CONFIDENTIAL
The circumcenter can be inside the triangle, Out the triangle, or on the triangle. P P P Acute triangle Obtuse triangle Right triangle CONFIDENTIAL
The circumcenter of ∆ABC is the center of its circumscribed circle The circumcenter of ∆ABC is the center of its circumscribed circle. A circle that contains all the vertices of a polygon is circumscribed about the polygon. B P A C CONFIDENTIAL
Circumcenter Theorem A l n P B C m CONFIDENTIAL
Using Properties of Perpendicular Bisector H 18.6 Z is the circumcenter of ∆GHJ. By the Circumcenter Theorem, Z is equidistant from the vertices of ∆GHJ. HZ = GZ Circumcenter Thm. HZ = 19.9 Substitute 19.9 for GZ. Z L K 9.5 19.9 G J M 14.5 CONFIDENTIAL
Finding the Circumcenter of a Triangle. Finding the circumcenter of ∆RSO with vertices R(-6,0), S(0,4), and O (0,0). Step 1 Graph the triangle. y X = -4 S Y = 2 (-3,2) x R 4 O Next page: CONFIDENTIAL
Step 2 Find equation for two perpendicular bisectors. Since Two sides of the triangle lie along the axes, use the graph to find the perpendicular bisectors of these two sides. The perpendicular bisector of RO is x = -3, and the perpendicular bisector of OS is y =2. y X = -4 S Y = 2 (-3,2) x R 4 O Next page: CONFIDENTIAL
Step 3 Find the intersection of the two equations. The lines x = -3 and y = z intersect at (-3,2), the circumcenter of ∆RSO. y X = -4 S Y = 2 (-3,2) x R 4 O CONFIDENTIAL
Theorem 2.2 Incenter Theorem The incenter of a triangle is equidistant from the sides of the triangle. PX = PY = PZ B Z Y P C A X CONFIDENTIAL
Unlike the circumcenter, the incenter is always inside the triangle. P P P Acute triangle Obtuse triangle Right triangle CONFIDENTIAL
The incenter is the center of the triangle’s inscribed circle The incenter is the center of the triangle’s inscribed circle. A circle inscribed in a polygon intersects each line that contains a side of the polygon at exactly one point. B P A C CONFIDENTIAL
Using Properties of Angle Bisectors K A) The distance from V to KL 7.3 V is the incenter of ∆JKL. By the Incenter Theorem, V is equidistant from the sides of ∆JKL. The distance from V to JK is 7.3. So the distance from V to KL is also 7.3 W V 106˚ J L 19˚ Next page: CONFIDENTIAL
JV is the bisector of m/ kJL. Substitute 19˚ for m / VJL. ∆ sum Thm. K B) m/ Vkl JV is the bisector of m/ kJL. Substitute 19˚ for m / VJL. ∆ sum Thm. K m/ kJL = 2m / VJL m/ kJL = 2(19˚) = 38˚ m/ kJL + m/ JLK + m/ JKL = 180˚ 38 + 106 + m/ JKL = 180˚ m/ JKL = 36˚ m/ Vkl = ½ m/ JKL m/ Vkl = ½ (36˚) = 18˚ Substitute the given values. Subtract 144˚ from both sides. 7.3 W KV is the bisector of m/ JKL V Substitute 36˚ for m/ JKL. 106˚ L 19˚ CONFIDENTIAL
Community Application The city of Odessa will host a fireworks display for the next Fourth of July celebration. Draw a sketch to show where the display should be positioned so that it is the same distance from all three viewing location A, B, and C on the map. Justify your sketch. A Let the three viewing locations be vertices of a triangle. By the Circumcenter Theorem, the circumcenter of the triangle is equidistant from the vertices. C B Next page: CONFIDENTIAL
Trace the map. Draw the triangle formed by the viewing locations Trace the map. Draw the triangle formed by the viewing locations. To find the circumcenter, find the perpendicular bisectors of each side. The position of the display is the circumcenter, F. A C F B CONFIDENTIAL
You did a great job today! CONFIDENTIAL