ConcepTest 2.1a Electric Potential Energy I

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Presentation transcript:

ConcepTest 2.1a Electric Potential Energy I A proton and an electron are in a constant electric field created by oppositely charged plates. You release the proton from the positive side and the electron from the negative side. Which feels the larger electric force? a) proton b) electron c) both feel the same force d) neither – there is no force e) they feel the same magnitude force but opposite direction electron proton + -

ConcepTest 2.1a Electric Potential Energy I A proton and an electron are in a constant electric field created by oppositely charged plates. You release the proton from the positive side and the electron from the negative side. Which feels the larger electric force? a) proton b) electron c) both feel the same force d) neither – there is no force e) they feel the same magnitude force but opposite direction Since F = qE and the proton and electron have the same charge in magnitude, they both experience the same force. However, the forces point in opposite directions because the proton and electron are oppositely charged. electron proton + -

ConcepTest 2.1b Electric Potential Energy II A proton and an electron are in a constant electric field created by oppositely charged plates. You release the proton from the positive side and the electron from the negative side. Which has the larger acceleration? a) proton b) electron c) both feel the same acceleration d) neither – there is no acceleration e) they feel the same magnitude acceleration but opposite direction electron proton + -

ConcepTest 2.1b Electric Potential Energy II A proton and an electron are in a constant electric field created by oppositely charged plates. You release the proton from the positive side and the electron from the negative side. Which has the larger acceleration? a) proton b) electron c) both feel the same acceleration d) neither – there is no acceleration e) they feel the same magnitude acceleration but opposite direction electron proton + - Since F = ma and the electron is much less massive than the proton, then the electron experiences the larger acceleration.

ConcepTest 2.1c Electric Potential Energy III A proton and an electron are in a constant electric field created by oppositely charged plates. You release the proton from the positive side and the electron from the negative side. When it strikes the opposite plate, which one has more KE? a) proton b) electron c) both acquire the same KE d) neither – there is no change of KE e) they both acquire the same KE but with opposite signs electron proton + -

ConcepTest 2.1c Electric Potential Energy III A proton and an electron are in a constant electric field created by oppositely charged plates. You release the proton from the positive side and the electron from the negative side. When it strikes the opposite plate, which one has more KE? a) proton b) electron c) both acquire the same KE d) neither – there is no change of KE e) they both acquire the same KE but with opposite signs electron proton + - Since PE = qV and the proton and electron have the same charge in magnitude, they both have the same electric potential energy initially. Because energy is conserved, they both must have the same kinetic energy after they reach the opposite plate.

ConcepTest 2.2 Work and Potential Energy Which group of charges took more work to bring together from a very large initial distance apart? 2 +1 d +1 +2 d 1 3 Both took the same amount of work

ConcepTest 2.2 Work and Potential Energy Which group of charges took more work to bring together from a very large initial distance apart? 2 +1 d +1 +2 d 1 3 Both took the same amount of work For case 1: only 1 pair The work needed to assemble a collection of charges is the same as the total PE of those charges: For case 2: there are 3 pairs added over all pairs

ConcepTest 2.3a Electric Potential I a) V > 0 b) V = 0 c) V < 0 What is the electric potential at point A? A B

ConcepTest 2.3a Electric Potential I a) V > 0 b) V = 0 c) V < 0 What is the electric potential at point A? A B Since Q2 (which is positive) is closer to point A than Q1 (which is negative) and since the total potential is equal to V1 + V2, then the total potential is positive.

ConcepTest 2.3b Electric Potential II a) V > 0 b) V = 0 c) V < 0 What is the electric potential at point B? A B

ConcepTest 2.3b Electric Potential II a) V > 0 b) V = 0 c) V < 0 What is the electric potential at point B? A B Since Q2 and Q1 are equidistant from point B, and since they have equal and opposite charges, then the total potential is zero. Follow-up: What is the potential at the origin of the x-y axes?

ConcepTest 2.4 Hollywood Square a) E = 0 V = 0 b) E = 0 V  0 c) E  0 V  0 d) E  0 V = 0 e) E = V regardless of the value Four point charges are arranged at the corners of a square. Find the electric field E and the potential V at the center of the square. -Q +Q

ConcepTest 2.4 Hollywood Square a) E = 0 V = 0 b) E = 0 V  0 c) E  0 V  0 d) E  0 V = 0 e) E = V regardless of the value Four point charges are arranged at the corners of a square. Find the electric field E and the potential V at the center of the square. The potential is zero: the scalar contributions from the two positive charges cancel the two minus charges. However, the contributions from the electric field add up as vectors, and they do not cancel (so it is non-zero). -Q +Q Follow-up: What is the direction of the electric field at the center?

ConcepTest 2.5a Equipotential Surfaces I 1 3 2 4 +Q –Q At which point does V = 0? e) all of them

ConcepTest 2.5a Equipotential Surfaces I 1 3 2 4 +Q –Q At which point does V = 0? e) all of them All of the points are equidistant from both charges. Since the charges are equal and opposite, their contributions to the potential cancel out everywhere along the mid-plane between the charges.

ConcepTest 2.5b Equipotential Surfaces II Which of these configurations gives V = 0 at all points on the x-axis? a) x +2mC -2mC +1mC -1mC b) c) d) all of the above e) none of the above

ConcepTest 2.5b Equipotential Surfaces II Which of these configurations gives V = 0 at all points on the x-axis? a) x +2mC -2mC +1mC -1mC b) c) d) all of the above e) none of the above Only in case (a), where opposite charges lie directly across the x-axis from each other, do the potentials from the two charges above the x-axis cancel the ones below the x-axis.

ConcepTest 2.5c Equipotential Surfaces III Which of these configurations gives V = 0 at all points on the y-axis? a) x +2mC -2mC +1mC -1mC b) c) d) all of the above e) none of the above

ConcepTest 2.5c Equipotential Surfaces III Which of these configurations gives V = 0 at all points on the y-axis? a) x +2mC -2mC +1mC -1mC b) c) d) all of the above e) none of the above Only in case (c), where opposite charges lie directly across the y-axis from each other, do the potentials from the two charges above the y-axis cancel the ones below the y-axis.

ConcepTest 2.6 Equipotential of Point Charge a) A and C b) B and E c) B and D d) C and E e) no pair Which two points have the same potential? A C B D E Q

ConcepTest 2.6 Equipotential of Point Charge a) A and C b) B and E c) B and D d) C and E e) no pair Which two points have the same potential? Since the potential of a point charge is: only points that are at the same distance from charge Q are at the same potential. This is true for points C and E. They lie on an Equipotential Surface. A C B D E Q Follow-up: Which point has the smallest potential?

ConcepTest 2.7a Work and Electric Potential I a) P  1 b) P  2 c) P  3 d) P  4 e) all require the same amount of work Which requires the most work, to move a positive charge from P to points 1, 2, 3 or 4 ? All points are the same distance from P. P 1 2 3 4

ConcepTest 2.7a Work and Electric Potential I a) P  1 b) P  2 c) P  3 d) P  4 e) all require the same amount of work Which requires the most work, to move a positive charge from P to points 1, 2, 3 or 4 ? All points are the same distance from P. P 1 2 3 4 For path #1, you have to push the positive charge against the E field, which is hard to do. By contrast, path #4 is the easiest, since the field does all the work.

ConcepTest 2.7b Work and Electric Potential II a) P  1 b) P  2 c) P  3 d) P  4 e) all require the same amount of work Which requires zero work, to move a positive charge from P to points 1, 2, 3 or 4 ? All points are the same distance from P. P 1 2 3 4

ConcepTest 2.7b Work and Electric Potential II a) P  1 b) P  2 c) P  3 d) P  4 e) all require the same amount of work Which requires zero work, to move a positive charge from P to points 1, 2, 3 or 4 ? All points are the same distance from P. For path #3, you are moving in a direction perpendicular to the field lines. This means you are moving along an equipotential, which requires no work (by definition). P 1 2 3 4