Volumes of Pyramids & Cones Objectives: 1) Find the volume of a right Pyramid. 2) Find the volume of right Cone.

Slides:



Advertisements
Similar presentations
Volumes of Pyramids & Cones
Advertisements

Volume of Cones and Pyramids
 A cylinder has two identical flat ends that are circular and one curved side.  Volume is the amount of space inside a shape, measured in cubic units.
12 – 3 Cylinders and Cones.
MFM1P Minds On Determine the volume of: a) This square based pyramid b) This triangular based pyramid.
What is Volume? Next V = 1/3 πr 2 V = 4/3πr 3.
6.3: Surface Areas of Pyramids and Cones
Surface Area and Volume of Prisms & Cylinders Surface Area and Volume of Prisms & Cylinders Objectives: 1) To find the surface area of a prism. 2) To find.
Surface Area of Pyramids and Cones Section 12.3 Goal – to find the surface area of a pyramid and the surface area of a cone.
Surface Area and Volume
Surface Area of 10-5 Pyramids and Cones Warm Up Lesson Presentation
Geometry Volume of Pyramids and Cones. August 21, 2015 Goals Find the volume of pyramids and cones. Solve problems using volume. Skip Intro.
Geometry 11-3 Surface Areas of Pyramids and Cones.
1-7 Three Dimensional Figures
Warm Ups Preview 10-1 Perimeter 10-2 Circles and Circumference
Volume of Prisms & Cylinders Look at the three shapes I have and tell me what they have in common when one is trying to calculate the volume of these figures.
Perimeter, Area, Surface Area, and Volume Examples
Geometry Jeopardy! Ch 1-6 Formulas & Definitions SA of Prisms & Cylinders SA of Cones & Pryamids Volume of Prisms & Cylinders Volume of Cones & Pyramids.
12.1 Prisms. Prisms are specific kinds of _____________ The word polyhedra is the plural form of polyhedron.
Chapter 10: Surface Area and Volume
MATH 3190 Surface Area and andVolume. Measurement Rectangular Prism Rectangular Prism Surface Area: sum of the areas of all of the faces Surface Area:
11.3 and 11.5: Pyramids and Cones. Pyramids Pyramid – A 3-D figure with one face (the base) that is any polygon and the other faces (the lateral faces)
11.3 Surface Areas of Pyramids and Cones A pyramid is a polyhedron in which one face (the base) can be any polygon and the other faces (the lateral faces)
11 – 5 Volumes of Pyramids & Cones
11.5 Volume of Pyramids and Cones. Finding Volumes of Pyramids and Cones In 11.4, you learned that the volume of a prism is equal to Bh, where B is the.
The Cone A Cone is a three dimensional solid with a circular base and a curved surface that gradually narrows to a vertex. Volume of a Cone = ++=
Surface Area of Pyramids and Cones SWBAT: Define Pyramid, Vertex of a pyramid, slant height, Regular Pyramid, Cone, and Right cone. Find the area.
10.6: Volumes of Pyramids and Cones Objective: To find the volume of pyramids and cones.
Section 12.3 Surface Area of Pyramids and Cones. Pyramid: polyhedron with one base lateral faces- triangles Slant Height: altitude of any lateral face.
Bell Work: Find the Volume: V =  r 2 h =  (24 2 )(8) = 4608  in 3 4 ft 8 in.
Holt CA Course Three-Dimensional Figures Warm Up Warm Up Lesson Presentation Lesson Presentation California Standards California StandardsPreview.
Volume of Cylinders, Pyramids, Cones and Spheres
Perimeter, Area, and Volume Geometry and andMeasurement.
GEOMETRY 10.5 Surface Area of Pyramids and Cones.
PRE-ALGEBRA. Surface Area: Pyramids, Cones, and Spheres (10-6) How can you find the surface area of a pyramid using a formula? Surface Area (S.A.) of.
Surface Area/Volume SF, SA & Volume Formula Identification Vocabulary Terms VolumeSurface.
Holt CA Course Three-Dimensional Figures Warm Up Warm Up Lesson Presentation California Standards Preview.
Surface area & volume UNIT 4. Prisms SECTION 1  Prism: three dimensional shape with two parallel sides  Bases: sides parallel to each other  Lateral.
1 Cylinders and Cones. 2 Surface Area (SA) = ph + 2B = 2πrh + 2πr 2 Cylinders are right prisms with circular bases. Therefore, the formulas for prisms.
8 th Grade Math Chart Brisa Alcorta 2 nd Period. Pi The ratio of the circumference of a circle to its diameter. Approximate value: 3.14.
Surface Areas of Pyramids Section Find the Surface Area… Find the surface area of a cylinder with a diameter of 10cm and a height of 15cm.
Vertex Regular Pyramid – Slant Height - Altitude 1) Base is a regular polygon 2) Faces are congruent isosceles triangles 3) Altitude meets the base at.
Surface Area of Pyramids and Cones Pyramid Cones Has a square base and comes to a point Has a circle base and comes to a point.
AREA / VOLUME UNIT FORMULAS.
Unit 2 Volume. Warm-Up Solve 1.4p = 9p (2p+5) = 2(8p + 4) Solve for p.
 A cylinder has two identical flat ends that are circular and one curved side.  Volume is the amount of space inside a shape, measured in cubic units.
 A cylinder has two identical flat ends that are circular and one curved side.  Volume is the amount of space inside a shape, measured in cubic units.
Perimeter, Circumference and Area. Perimeter and Circumference Perimeter : The distance around a geometric figure. Circumference: The distance around.
Geometry Practice Test Prisms Find the (1) lateral area and (2) total area and (3) volume of the right prism (1) LA = pH LA.
Opener. UNIT EQ: HOW DO YOU CALCULATE THE SURFACE AREA AND VOLUME OF A 3-DIMENSIONAL FIGURE Surface Area & Volume.
Lateral Surface Area Lateral Surface Area is the surface area of the solid’s lateral faces without the base(s).
Unit 9: Solids. A polyhedron is a solid that is bounded by polygons called faces, that enclose a region of space. An edge of a polyhedron is a line segment.
Volume of Pyramids and Cones Section 9.5. Objectives: Find the volumes of pyramids and cones.
11 – 5 Volumes of Pyramids & Cones
Preview Warm Up California Standards Lesson Presentation.
11 – 5 Volumes of Pyramids & Cones
You need to learn this on your OWN to be ready for the next class.
Definitions A cylinder has two identical flat ends that are circular and one curved side. Volume is the amount of space inside a shape, measured in cubic.
11.3 Surface Areas of Pyramids and Cones
11.6 Surface Area and Volume of Pyramids and Cones
10 – 5 Volumes of Pyramids & Cones
11-3 Surface Area of Pyramids and Cones
The Cone + + = Volume of a Cone =
5.6 Surface Area of 3D Figures
Surface Area and Volume of Pyramids
Surface Area of Prisms & Cylinders
Chapter 10 Extension Objective: To find missing dimensions
Given that they are equivalent, what is the diameter of the sphere?
Objective - To identify solid figures.
Presentation transcript:

Volumes of Pyramids & Cones Objectives: 1) Find the volume of a right Pyramid. 2) Find the volume of right Cone.

I. Volume of a Pyramid Pyramid – Is a polyhedron in which one face can be any polygon & the other faces are triangles. Pyramid – Is a polyhedron in which one face can be any polygon & the other faces are triangles. h V p = ⅓Bh Area of the Base A = lw A = ½bh Height of the pyramid, not to be confused with the slant height (l)

Ex.1: Volume of a right Pyramid Find the volume of a square pyramid with base edges of 15cm & a height of 22cm. Find the volume of a square pyramid with base edges of 15cm & a height of 22cm. 22cm 15cm V = (⅓)Bh = (⅓)lwh = (⅓) = (⅓)4950 = 1650cm 3 Square

II. Volume of a Cone Cone – Is “pointed” like a pyramid, but its base is a circle. Cone – Is “pointed” like a pyramid, but its base is a circle. h r V c = ⅓Bh Area of the Base A =  r 2 Height of the cone, not to be confused with the slant height (l)

Ex.3: Find the volume of the following right cone w/ a diameter of 6in. 11in V = ⅓Bh = (⅓)  r 2 h = (⅓)  (3) 2 (11) = (⅓)99  = 33  = 103.7in 3 Circle 3in

Ex.5: Solve for the missing variable. The following cone has a volume of 110 . What is its radius. The following cone has a volume of 110 . What is its radius. 10cm r V = ⅓Bh V = ⅓(  r 2 )h 110  = (⅓)  r 2 (10) 110 = (⅓)r 2 (10) 11 = (⅓)r 2 33 = r 2 r = √ (33) = 5.7cm

Ex.4: Volume of a Composite Figure 8cm 10cm 4cm Volume of Cone first! V c = ⅓Bh = (⅓)  r 2 h = (⅓)(8) 2  (10) = (⅓)(640)  =  = 670.2cm 3 Volume of Cylinder NEXT! V c = Bh =  r 2 h =  (8) 2 (4) = 256  = 804.2cm 3 V T = V c + V c V T = 670cm cm 3 V T = cm 3