5 5.1 © 2012 Pearson Education, Inc. Eigenvalues and Eigenvectors EIGENVECTORS AND EIGENVALUES.

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5 5.1 © 2012 Pearson Education, Inc. Eigenvalues and Eigenvectors EIGENVECTORS AND EIGENVALUES

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  Definition: An eigenvector of an matrix A is a nonzero vector x such that for some scalar λ. A scalar λ is called an eigenvalue of A if there is a nontrivial solution x of ; such an x is called an eigenvector corresponding to λ.

EIGENVECTORS AND EIGENVALUES Slide © 2012 Pearson Education, Inc.  λ is an eigenvalue of an matrix A if and only if the equation ----(1) has a nontrivial solution.  The set of all solutions of (1) is just the null space of the matrix.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  So this set is a subspace of and is called the eigenspace of A corresponding to λ.  The eigenspace consists of the zero vector and all the eigenvectors corresponding to λ.  Example 1: Show that 7 is an eigenvalue of matrix and find the corresponding eigenvectors.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  Solution: The scalar 7 is an eigenvalue of A if and only if the equation ----(2) has a nontrivial solution.  But (2) is equivalent to, or ----(3)  To solve this homogeneous equation, form the matrix

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  The columns of are obviously linearly dependent, so (3) has nontrivial solutions.  To find the corresponding eigenvectors, use row operations:  The general solution has the form.  Each vector of this form with is an eigenvector corresponding to.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  Example 2: Let. An eigenvalue of A is 2. Find a basis for the corresponding eigenspace.  Solution: Form and row reduce the augmented matrix for.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  At this point, it is clear that 2 is indeed an eigenvalue of A because the equation has free variables.  The general solution is, x 2 and x 3 free.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  The eigenspace, shown in the following figure, is a two-dimensional subspace of.  A basis is

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  Theorem 1: The eigenvalues of a triangular matrix are the entries on its main diagonal.  Proof: For simplicity, consider the case.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND EIGENVALUES  Theorem 2: If v 1, …, v r are eigenvectors that correspond to distinct eigenvalues λ 1, …, λ r of an matrix A, then the set {v 1, …, v r } is linearly independent.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND DIFFERENCE EQUATIONS  If A is an matrix, then ----(7) is a recursive description of a sequence {x k } in.  A solution of (7) is an explicit description of {x k } whose formula for each x k does not depend directly on A or on the preceding terms in the sequence other than the initial term x 0.

Slide © 2012 Pearson Education, Inc. EIGENVECTORS AND DIFFERENCE EQUATIONS  The simplest way to build a solution of (7) is to take an eigenvector x 0 and its corresponding eigenvalue λ and let ----(8)  This sequence is a solution because