Technical Question Technical Question

Slides:



Advertisements
Similar presentations
Example 1 Matrix Solution of Linear Systems Chapter 7.2 Use matrix row operations to solve the system of equations  2009 PBLPathways.
Advertisements

Solving Equations = 4x – 5(6x – 10) -132 = 4x – 30x = -26x = -26x 7 = x.
6.8 –Systems of Inequalities. Just like systems of equations, but do the inequality part!
1. What is the difference between a solution for an equation and a solution for an inequality? (complete sentences please)
Substitute 0 for y. Write original equation. To find the x- intercept, substitute 0 for y and solve for x. SOLUTION Find the x- intercept and the y- intercept.
Substitute 0 for y. Write original equation. To find the x- intercept, substitute 0 for y and solve for x. SOLUTION Find the x- intercept and the y- intercept.
3x – 5y = 11 x = 3y + 1 Do Now. Homework Solutions 2)2x – 2y = – 6 y = – 2x 2x – 2(– 2x) = – 6 2x + 4x = – 6 6x = – 6 x = – 1y = – 2x y = – 2(– 1) y =
Elimination Day 2. When the two equations don’t have an opposite, what do you have to do? 1.
3.5 – Solving Systems of Equations in Three Variables.
Solving Quadratic Equations by Factoring. Solution by factoring Example 1 Find the roots of each quadratic by factoring. factoring a) x² − 3x + 2 b) x².
Learning Task/Big Idea: Students will learn how to find roots(x-intercepts) of a quadratic function and use the roots to graph the parabola.
3.6 Solving Absolute Value Equations and Inequalities
Solving Open Sentences Involving Absolute Value
Solving Quadratic Equations – Quadratic Formula The following shows how to solve quadratic equations using the Quadratic Formula. A quadratic equation.
Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination.
Section 5.3 Solving Systems of Equations Using the Elimination Method There are two methods to solve systems of equations: The Substitution Method The.
Solving a Trigonometric Equation Find the general solution of the equation.
Solving Linear Systems by Substitution
Notes Over 5.6 Quadratic Formula
Notes Over 7.6 Solving a Simple Radical Equation Solve the equation. Check your solution.
Chapter 8 Systems of Linear Equations in Two Variables Section 8.3.
Solving multi step equations. 12X + 3 = 4X X 12X + 3 = 3X X 9X + 3 = X = X =
Solving equations with variable on both sides Part 1.
2( ) 8x + 14y = 4 -12x – 14y = x = x = 4 8x + 14y = 4 8(4) + 14y = y = y = -28 ___ ___ y = -2 The solution is (4, -2)
Bell Ringer Solve each for x.
3.3 – Solving Systems of Inequalities by Graphing
Solving Quadratic Equations by the Complete the Square Method
BACK SOLUTION:
Notes Over 9.6 An Equation with One Solution
3-2: Solving Systems of Equations using Substitution
Solving Equations by Factoring and Problem Solving
Solve: 1. 4<
Solve a system of linear equation in two variables
6-3 Solving Systems Using Elimination
3-2: Solving Systems of Equations using Substitution
Solving Systems of Equations using Substitution
Use power series to solve the differential equation. {image}
Do Now 1) t + 3 = – 2 2) 18 – 4v = 42.
What is an equation? An equation is a mathematical statement that two expressions are equal. For example, = 7 is an equation. Note: An equation.
Equation Review Given in class 10/4/13.
3-2: Solving Systems of Equations using Substitution
Solving equations Mrs. Hall.
Solving Systems of Equation by Substitution
Solving Cubic Equations
SIMULTANEOUS EQUATIONS 1
Algebra 2 Ch.3 Notes Page 15 P Solving Systems Algebraically.
Solving a Radical Equation
5.1 Solving Systems of Equations by Graphing
Solving Equations 3x+7 –7 13 –7 =.
Solving Equations with Variables on Both Sides
Solving Equations with Variables on Both Sides
Solve the equation: 6 x - 2 = 7 x + 7 Select the correct answer.
Systems of Equations Solve by Graphing.
MATH 1310 Section 2.8.
POWER CHALLENGES Several Ways To Solve 7 CHALLENGES.
Equation Review.
3-2: Solving Systems of Equations using Substitution
Jeopardy Final Jeopardy Solving Equations Solving Inequalities
MATH 1310 Section 2.8.
MATH 1310 Section 2.8.
Solving Systems of Equations by Elimination Part 2
3-2: Solving Systems of Equations using Substitution
3-2: Solving Systems of Equations using Substitution
MATH 1310 Section 2.8.
3-2: Solving Systems of Equations using Substitution
Solving a System of Linear Equations
Solving By Substitution
11-5 Solving Rational Equations
Balanced scales and equations
Presentation transcript:

Technical Question Technical Question Please solve the following equation: Please solve the following equation: 92 × 2 - 4 82 - 12 × 3 Technical Question Technical Question Please solve the following equation: Please solve the following equation: 75 - 11 × 4 + 5 7 × 5 + 33 × 3 -2 Technical Question Technical Question Please solve the following equation: Please solve the following equation: 9 × 3 - 11 + 9 × 2 92 × 1 + 5 - 15 Technical Question Technical Question Please solve the following equation: Please solve the following equation: 23 × 3 - 10 + 3 38 × 2 + 4 × 2

Technical Question Technical Question Solution: Solution: 92 × 2 – 4 = 180 82 - 12 × 3 = 46 Technical Question Technical Question Solution: Solution: 75 - 11 × 4 + 5 = 36 7 × 5 + 33 × 3 – 2 = 132 Technical Question Technical Question Solution: Solution: 9 × 3 - 11 + 9 × 2 = 34 92 × 1 + 5 – 15 = 82 Technical Question Technical Question Solution: Solution: 23 × 3 - 10 + 3 = 62 38 × 2 + 4 × 2 = 84

Technical Question Technical Question Please solve the following equation: Please solve the following equation: 19 × 2 - 8 + 5 3 + 5 - 2 × 4 + 30 Technical Question Technical Question Please solve the following equation: Please solve the following equation: 47 × 2 × 2 + 44 7 + 4 × 8 + 21 Technical Question Technical Question Please solve the following equation: Please solve the following equation: 3 + 23 × 2 - 9 9 × 2 - 3 + 2 × 5 Technical Question Technical Question Please solve the following equation: Please solve the following equation: 42 × 2 + 21 + 6 / 2 8 + 3 × 6 - 2 + 9

Technical Question Technical Question Solution: Solution: 19 × 2 - 8 + 5 = 35 3 + 5 - 2 × 4 + 30 = 30 Technical Question Technical Question Solution: Solution: 7 + 4 × 8 + 21 = 60 47 × 2 × 2 + 44 = 232 Technical Question Technical Question Solution: Solution: 3 + 23 × 2 – 9 = 40 9 × 2 - 3 + 2 × 5 = 25 Technical Question Technical Question Solution: Solution: 42 × 2 + 21 + 6 / 2 = 108 8 + 3 × 6 - 2 + 9 = 33