Advanced Higher Unit 3 Elemental microanalysis. Elemental Microanalysis Elemental microanalysis (or combustion analysis) is used to determine the masses.

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Presentation transcript:

Advanced Higher Unit 3 Elemental microanalysis

Elemental Microanalysis Elemental microanalysis (or combustion analysis) is used to determine the masses of the elements in a sample of an organic compound in order to calculate its empirical formula. The carbon, hydrogen and nitrogen contents are measured using an instrument known as a CHN analyser.

The Process Step 1 -An accurate mass of sample (~2 mg) is weighed out. Step 2 -Sample is then placed in a sealed oxygen atmosphere and combusted at ~1000 °C. Step 3 -CO 2, H 2 O and N x O y are produced and passed through a CHN analyzer (a different but similar analyzer is used for S) Step 4 -Other elements, except oxygen, are determined by alternative methods. Step 5 -Samples are analysed in dup;icates to give more reliable results.Results are calculated and expressed as a percentage, by mass. Now watch the RSC video on ‘Elemental Microanalysis’

Empirical Formula Calculations C H O  1 =6 12  1 =12 1  1 = ElementMass Present RAMMoles present  by smallest Whole number ratio Calculate the empirical mass of a compound that contains 72 % carbon, 12 % hydrogen, and 16 % oxygen Empirical Formula is C 6 H 12 O

Calculate the empirical formula of the following two examples a) C = % H = 7.32 % O = % b)C = % H = % O = % C5H6OC5H6O C 5 H 10 O

A sample of an organic compound with a mass of 1.224g was completely burned in oxygen and found to produce 2.340g of CO 2 and 1.433g of H 2 O. Calculate the empirical formula of the organic compound. Mass of carbon = 12.0/44.0 x = 0.638g Mass of hydrogen = 2.0/18.0 x = 0.159g Mass of oxygen = – ( ) =0.427g

Number of moles Mole ratio C0.638/12 = / = 2 H0.159/1 = / = 6 O0.427/16= / = 1 Empirical formula = C 2 H 6 O

Exercise Now try the exercise on page 3 of your Unit 3(d) notes.