Algebra 2 Bell-work 10/14/2014 Multiple Choice: Which set of ordered pairs is a solution to the system? 4x + 2y = 4 6x + 2y = 8 A. (7,5)B. (2,4)C. (2,-2)D.

Slides:

Advertisements

Similar presentations

LINEAR EQUATION IN TWO VARIABLES. System of equations or simultaneous equations – System of equations or simultaneous equations – A pair of linear equations.

Advertisements

Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.

3.5 Solving systems of equations in 3 variables

Algebra II w/ trig. Substitution Method: 1. Solve an equation for x or y 2. Substitute your result from step 1 into the other equation and solve for the.

Bell Work2/12/15 Solve the system by elimination..

Solving Systems of Linear Equations in Three Variables; Applications

3.2 Solving Systems Algebraically

Module 6-3 Objectives Solve systems of linear equations in two variables by elimination. Compare and choose an appropriate method for solving systems of.

Algebra-2 Section 3-2B.

The Quadratic Formula. What does the Quadratic Formula Do ? The Quadratic formula allows you to find the roots of a quadratic equation (if they exist)

Solving Systems Using Elimination (For help, go to Lesson 7-2.) Solve each system using substitution. 1.y = 4x – 32.y + 5x = 4 3. y = –2x + 2 y = 2x +

Solving Systems Using Elimination

SOLVING SYSTEMS ALGEBRAICALLY SECTION 3-2. SOLVING BY SUBSTITUTION 1) 3x + 4y = 12 STEP 1 : SOLVE ONE EQUATION FOR ONE OF THE VARIABLES 2) 2x + y = 10.

Section 3-2: Solving Systems Algebraically (Pg.125) By Ms. Beydoun.

Graph the following lines on the same coordinate plane. y = 2x - 1

Solving Systems of Equations using Elimination. Solving a system of equations by elimination using multiplication. Step 1: Put the equations in Standard.

3-2 Day 2 Solving Systems Algebraically: Elimination Method Objective: I can solve a system of equations using the elimination method.

Example 1A Solve the equation. Check your answer. (x – 7)(x + 2) = 0

Solving by Substitution Method or Elimination (Addition) Method

Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination.

3-2 Solving Linear Systems Algebraically Objective: CA 2.0: Students solve system of linear equations in two variables algebraically.

Elimination Method: Solve the linear system. -8x + 3y=12 8x - 9y=12.

Lesson 7.4A Solving Linear Systems Using Elimination.

Chapter 3 Examples Section 5 Solving System of Equations Algebraically with 3 variables.

Good Morning, We are moving on to chapter 3. If there is time today I will show you your test score you can not have them back as I still have several.

Solve by Graphing Solve: 3x + 4y = - 4 x + 2y = 2

Solve Systems of Equations Using Elimination Section 6.3.

SOLVING SYSTEMS USING ELIMINATION 6-3. Solve the linear system using elimination. 5x – 6y = -32 3x + 6y = 48 (2, 7)

Solving Systems of Equations

Multi Step Equations. Algebra Examples 3/8 – 1/4x = 1/2x – 3/4 3/8 – 1/4x = 1/2x – 3/4 8(3/8 – 1/4x) = 8(1/2x – 3/4) (Multiply both sides by 8) 8(3/8.

Solving Systems by Elimination 5.4 NOTES, DATE ____________.

EXAMPLE 4 Solve linear systems with many or no solutions Solve the linear system. a.x – 2y = 4 3x – 6y = 8 b.4x – 10y = 8 – 14x + 35y = – 28 SOLUTION a.

Systems of Equations By Substitution and Elimination.

5.4 Elimination Using Multiplication Algebra 1 Objective: Each student will understand if addition and subtraction does not eliminate a variable – how.

Solving Systems of Linear Equations by Elimination; Applications Solve systems of linear equations using elimination. 2.Solve applications using.

Chapter 3 Section 2. EXAMPLE 1 Use the substitution method Solve the system using the substitution method. 2x + 5y = –5 x + 3y = 3 Equation 1 Equation.

Elimination Method - Systems. Elimination Method  With the elimination method, you create like terms that add to zero.

 Variable with coefficient of one Solve for variable, and substitute  Two equations with opposite coefficients for one variable Add the two equations.

Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.

Solving Systems by Elimination

Objective I can solve systems of equations using elimination with addition and subtraction.

10.3 Solving Linear Systems

Elimination Method Day 1

Solving Systems of Equations by Elimination2

Warm-Up Graph Solve for y: Graph line #2.

Solving Two-Step Equations

3.2 Solve Linear Systems Algebraically

Solving a system of equations by elimination using multiplication.

Factoring Quadratic Equations

3.5 Solving systems of equations in 3 variables

Lesson 7.1 How do you solve systems of linear equations by graphing?

Elimination Using Multiplication

3.2a – Solving Systems algebraically

Objectives Solve systems of linear equations in two variables by elimination. Compare and choose an appropriate method for solving systems of linear equations.

Solving one- and two-step equations

Solving Systems of Equations

SYSTEMS OF LINEAR EQUATIONS

Systems with Three Variables

Elimination Using Multiplication.

Solve the linear system.

Solving Systems by Elimination

Example 2B: Solving Linear Systems by Elimination

Section 2.6 Solve Equations by Multiplying or Dividing

A, b and c can be any numbers

The student will be able to:

Ch. 6 Vocabulary 7.) Substitution method (6-2) 8.) Elimination method (6-3)

Solving Systems by ELIMINATION

A, b and c can be any numbers

Systems of three equations with three variables are often called 3-by-3 systems. In general, to find a single solution to any system of equations,

A, b and c can be any numbers

Presentation transcript:

Algebra 2 Bell-work 10/14/2014 Multiple Choice: Which set of ordered pairs is a solution to the system? 4x + 2y = 4 6x + 2y = 8 A. (7,5)B. (2,4)C. (2,-2)D. (-1,3) What type of system is this?

Algebra 2 Solving Systems Algebraically

Algebra 2 Use the elimination method to solve the system. Lesson 3-2 Solving Systems Algebraically 3x + y = –9 –3x – 2y = 12 y= –3 3x + (–3)= –9Substitute y. Solve for x. x= –2 The solution is (–2, –3). 3x + y= –9Choose one of the original equations. 3x + y = –9 –3x – 2y = 12Two terms are additive inverses, so add. –y = 3Solve for y. Additional Examples

Algebra 2 Solving Systems Algebraically Lesson 3-2 Use the elimination method to solve the system x + y = 12 x – y = 2

Algebra 2 Solve each system by elimination. Lesson 3-2 Solving Systems Algebraically The two equations in the system represent parallel lines. The system has no solution. Multiply the first line by 2 to make the x terms additive inverses. –3x + 5y= 6 6x – 10y= 0 –6x + 10y= 12 6x – 10y= 0 0 = 12 a.–3x + 5y = 6 6x – 10y = 0 Additional Examples

Algebra 2 Solving Systems Algebraically Lesson 3-2 Use the elimination method to solve the system 2a + 3b = 12 5a - b = 13

Algebra 2 Lesson 3-2 Solving Systems Algebraically Multiply the first line by 2 to make the x terms additive inverses. –3x + 5y= 6 6x – 10y= –12 –6x + 10y= 12 6x + 10y = –12 0 = 0 b.–3x + 5y = 6 6x – 10y = –12 The two equations in the system represent the same line. The system has an infinite number of solutions. Additional Examples On your index card solve:

Algebra 2 Solving Systems Algebraically