Lecture 11: Electrochemistry Introduction

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Presentation transcript:

Lecture 11: Electrochemistry Introduction Reading: Zumdahl 4.10, 4.11, 11.1 Outline General Nomenclature Balancing Redox Reactions (1/2 cell method) Electrochemical Cells

Nomenclature LEO goes GER “Redox” Chemistry: Reduction and Oxidation • Oxidation: Loss of electrons • Reduction: Gain of electrons (a reduction in oxidation number) LEO goes GER Loss of Electrons is Oxidation Gain of Electrons is Reduction

Redox Reaction Example A redox reaction: Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) Ox. #: 0 +1 +2 0 reduction oxidation

Redox Reaction Example (cont.) We can envision breaking up the full redox reaction into two 1/2 reactions: Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) reduction oxidation Cu(s) Cu2+(aq) + 2e- Ag+(aq) + e- Ag(s) “half-reactions”

Redox Reaction Example (cont.) Note that the 1/2 reactions are combined to make a full reaction: Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) reduction oxidation The important thing to remember: electrons are neither created or destroyed during a redox reaction. They are transferred from the species being oxidized to that being reduced.

Example Identify the species being oxidized and reduced in the following (unbalanced) reactions: ClO3- + I- I2 + Cl- reduction +5 -1 0 -1 oxidation NO3- + Sb Sb4O6 + NO reduction +5 0 +3 +2 oxidation

Balancing Redox Reactions One method of half reactions Key idea….make sure e- are neither created or destroyed in final reaction. Let’s balance the following reaction: CuS(s) + NO3-(aq) Cu2+(aq) + SO42-(aq) + NO(g)

Balancing (cont.) • Step 1: Identify and write down the unbalanced 1/2 reactions. CuS(s) + NO3-(aq) Cu2+(aq) + SO42-(aq) + NO(g) -2 +5 +6 +2 oxidation reduction CuS(s) Cu2+(aq) + SO42-(aq) oxidation NO3-(aq) NO(g) reduction

Balancing (cont.) • Step 2: Balance atoms and charges in each 1/2 reactions. Use H2O to balance O, and H+ to balance H (assume acidic media). Use e- to balance charge. 4H2O + CuS(s) Cu2+(aq) + SO42-(aq) + 8H+ + 8e- 3e- + 4H+ + NO3-(aq) NO(g) + 2H2O

Balancing (cont.) • Step 3: Multiply each 1/2 reaction by an integer such that the number of electronic cancels. 4H2O + CuS(s) Cu2+(aq) + SO42-(aq) + 8H+ + 8e- x 3 3e- + 4H+ + NO3-(aq) NO(g) + 2H2O x 8 3CuS + 8 NO3- + 8H+ 8NO + 3Cu2+ + 3SO42- + 4H2O • Step 4: Add and cancel.

Balancing (end) Step 5. For reactions that occur in basic solution, proceed as above. At the end, add OH- to both sides for every H+ present, combining to yield water on the H+ side. 3CuS + 8 NO3- + 8H+ 8NO + 3Cu2+ + 3SO42- + 4H2O + 8OH- + 8OH- 3CuS + 8 NO3- + 8H2O 8NO + 3Cu2+ + 3SO42- + 4H2O 4 + 8OH-

Example Balance the following redox reaction occurring in basic media: BH4- + ClO3- H2BO3- + Cl- BH4- H2BO3- oxidation -5 +3 ClO3- Cl- reduction +5 -1

Example (cont) 3H2O + BH4- H2BO3- + 8H+ + 8e- x 3 6e- + 6H+ + ClO3- Cl- + 3H2O x 4 3 3 BH4- + 4 ClO3- 4 Cl- + 3H2BO3- + 3H2O • Done!

Galvanic Cells In redox reaction, electrons are transferred from the oxidized species to the reduced species. Imagine separating the two 1/2 cells physically, then providing a conduit through which the electrons travel from one cell to the other.

Galvanic Cells (cont.) 8H+ + MnO4- + 5e- Mn2+ + 4H2O Fe2+ Fe3+ + e- x 5

Galvanic Cells (cont.) In turns out that we still will not get electron flow in the example cell. This is because charge build-up results in truncation of the electron flow. We need to “complete the circuit” by allowing positive ions to flow as well. We do this using a “salt bridge” which will allow charge neutrality in each cell to be maintained.

Galvanic Cells (cont.) Salt bridge/porous disk: allows for ion migration such that the solutions will remain neutral.

Galvanic Cells (cont.) • Galvanic Cell: Electrochemical cell in which chemical reactions are used to create spontaneous current (electron) flow

Voltmeter (–) Salt bridge (+) Zn Na+ Cu SO42– Zn2+ Cu2+

Voltmeter e– Anode (–) Salt bridge (+) Zn Na+ Cu SO42– Zn2+ Cu2+ Oxidation half-reaction Zn(s) Zn2+(aq) + 2e–

e– 2e– lost per Zn atom oxidized Zn Zn2+ Voltmeter e– Anode (–) Salt bridge (+) Zn Na+ Cu SO42– Zn2+ Cu2+ Oxidation half-reaction Zn(s) Zn2+(aq) + 2e–

e– 2e– lost per Zn atom oxidized Zn Zn2+ Voltmeter e– e– Anode (–) Salt bridge Cathode (+) Zn Na+ Cu SO42– Zn2+ Cu2+ Oxidation half-reaction Zn(s) Zn2+(aq) + 2e– Reduction half-reaction Cu2+(aq) + 2e– Cu(s)

e– 2e– gained per Cu2+ ion reduced 2e– lost per Zn atom oxidized Zn Cu2+ Cu e– Zn2+ Voltmeter e– e– Anode (–) Salt bridge Cathode (+) Zn Na+ Cu SO42– Zn2+ Cu2+ Oxidation half-reaction Zn(s) Zn2+(aq) + 2e– Reduction half-reaction Cu2+(aq) + 2e– Cu(s)

e– 2e– gained per Cu2+ ion reduced 2e– lost per Zn atom oxidized Zn Cu2+ Cu e– Zn2+ Voltmeter e– e– Anode (–) Salt bridge Cathode (+) Zn Na+ Cu SO42– Zn2+ Cu2+ Oxidation half-reaction Zn(s) Zn2+(aq) + 2e– Reduction half-reaction Cu2+(aq) + 2e– Cu(s) Overall (cell) reaction Zn(s) + Cu2+(aq) Zn2+(aq) + Cu(s)