7.5 Asian Options 指導老師:戴天時 演講者:鄭凱允. 序 An Asian option is one whose payoff includes a time average of the underlying asset price. The average may be over.

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7.5 Asian Options 指導老師:戴天時 演講者:鄭凱允

序 An Asian option is one whose payoff includes a time average of the underlying asset price. The average may be over the entire time period between initiation and expiration or may be over some period of time that begins later than the initiation of the option and ends with the option’s expiration.

The average may be from continuous sampling, Or may be form discrete sampling, It more difficult for anyone to significantly affect the payoff by manipulation of the underlying asset price. The price of Asian options is not known in closed form. Therefore, in this section we discuss two ways to derive partial differential equations for Asian option prices. The first of these was briefly presented in Example The other method for computing Asian option prices is Monte Carlo simulation.

7.5.1 Fixed-Strike Asian Call Once again, we begin with a geometric Brownian motion S(t) given by where is a Brownian motion under the risk-neutral measure. Consider a Fixed-strike Asian call whose payoff at time T is where the strike price K is a nonnegative constant. The price at times t prior to the expiration time T of this call is given by the risk-neutral pricing formula The usual iterated conditioning argument shows is a martingale under

7.5.2 Augmentation of the State The Asian option payoff V(T) in (7.5.2) is path-dependent. We cannot invoke the Markov property to claim that V(t) is a function of t and S(t) because V(T) is not a function of T and S(T); V(T) depends on the whole path of S. To overcome this difficulty, we augment the state S(t) by defining a second process Because the pair of processes (S(t),Y(t)) is governed by the pair of stochastic differential equations (7.5.1) and (7.5.5), they constitute a two-dimensional Markov process. Furthermore, the call payoff V(T) is a function of T and the final value (S(T),Y(T)) of this process. Indeed, V(T) depends only on T and Y(T), by the formula

This implies that there must exist some function v(t,x,y) such that the Asian call price (7.5.3) is given as Theorem the Asian call price function v(t,x,y) of (7.5.7) satisfies the partial differential equation

and the boundary conditions Proof: Using the stochastic differential equations (7.5.1) and (7.5.5) and noting that dS(t)dY(t)= dY(t) dY(t)= 0,we take the differential of the -martingale This differential is

In order for this to be a martingale, the dt term must be zero, which implies Replacing S(t) by the dummy variable x and Y(t) by the dummy variable y, we obtain (7.5.8) We note that S(t) must always be nonnegative, and so (7.5.8) holds for. If S(t)=0 and Y(t)=y for some value of t, then S(u)=0 for all and so Y(u) is constant on [t,T]. Therefore, Y(T)=y, and the value of the Asian call at time t is, discounted from T back to t. this gives us the boundary condition (7.5.9). If at time t we set Y(t)=y, then Y(T) is defined by (7.5.5). In integrated form, this formula is

Remark After we set the dt term in (7.5.12) equal to zero, we see that The discounted value of a portfolio that at each time t holds shares of the underlying asset is given by (see (5.2.27)) To hedge a short position in the Asian call, an agent should equate these two differentials, which leads to the delta-hedging formula

7.5.3 Change of Numeraire In this subsection we present a partial differential equation whose solution leads to Asian option prices. We work this out for both continuous and discrete averaging. The derivation of this equation involves a change of numeraire, a concept discussed systematically in Chapter 9. in the section, we derive formulas under the assumption that the interest rate r is not zero. The case r=0 is treated in Exercise 7.8 We first consider the case of an Asian call with payoff where c is a constant satisfying and K is a nonnegative constant. If c=T, this is the Asian call (7.5.2) considered in Subsection Here we also admit the possibility that the averaging is over less than the full time between initiation and expiration of the call.

To price this call, we create a portfolio process whose value at time T is We begin with a nonrandom function of time which will be the number of shares of the risky asset held by our portfolio. There will be no Brownian motion term in, and because of this it will satisfy This implies that which further implies Rearranging terms in (7.5.18), we obtain

an agent who holds shares of the risky asset at each time t and finances his by investing or borrowing at the interest rate r will have a portfolio whose value evolves according to the equation using this equation and (7.5.19), we obtain To study the Asian call with payoff (7.5.16), we take to be

and we take the initial capital to be In the time interval [0,T-c], the process mandates a buy-and-hold strategy. At time zero, we buy shares of the risky asset, which costs. Our in initial capital is insufficient to do this, and we must borrow from the money market account. For,the value of our holdings in the risky asset is and we owe to the money market account. Therefore, In particular,

For we have and we compute X(t) by first integrating (7.5.21) form T-c to t and using (7.5.25) and (7.5.22) to obtain therefore,

In particular, As desired, and The price of the Asian call at time t prior to expiration is The calculation of the right-hand side of (7.5.29) uses a change-of- numeraire argument, which we now exlain. Let us define

This is the value of the portfolio denominated in units of the risky asset rather than in dollars. We have changed the numeraire, the unit of account, from dollars to the risky asset. we work out the differential of Y(t). Note first that Therefore,

On the other hand, (7.5.20) and (7.5.30) imply product rule implies

The process Y(t) is not a martingale under because its differential (7.5.31) has a dt term. However, we can change measure so that Y(t) is a martingale, and this will simplify (7.5.31). We set And then have According to Girsanov’s Theorem, Theorem 5.2.3, we can change the measure so that,,is a Brownian motion. In this situation, plays the role of in Theorem 5.2.3, and and play the roles of W and P. the Radon-Nikodym derivative process of (5.2.11) is

In other words, Under the probability measure defined by is a Brownian motion and Y(t) is a martingale. Under the probability measure, the process Y(t) is Markov. It is given by the stochastic differential equation (7.5.33) is a function of t and Y(t) and has no source of randomness other than Y(t). Equation (7.5.33) is a stochastic differential equation of the type (6.2.1), and solutions to such equations are Markov (see Corollary 6.3.2).

We return to the option price V(t) of (7.5.29) and use Lemma to write (7.5.29) as where denotes conditional expectation under the probability measure. Because Y is Markov under, there must be some function g(t,y) such that

From (7.5.36), we see that We note that can take any value since the numerator X(T), given by (7.5.27), can be either positive or negative, and the denominator S(T) can be any positive number. Therefore, (7.5.37) leads to the boundary condition The usual iterated conditioning argument shows that the right-hand side of (7.5.36) is a martingale under, and so the differential of g(t,Y(t)) should gave only a term. This differential is

We conclude that g(t,y) satisfies the partial differential equation Theorem ( ). For, the price V(t) at time t of the continuously averaged Asian call with payoff (7.5.16) at time T is where g(t,y) satisfies (7.5.39) and X(t) is given by (7.5.24) and (7.5.26). The boundary conditions for g(t,y) are (7.5.38) and

We adapt the arguments just given to treat a discretely sampled Asian call. Assume we are given times and the Asian call payoff is We wish to create a portfolio process so that In place of (7.5.22), we define

Then and We complete the definition of by setting This defines for all In this situation, (7,5,21) still holds, but now in each subinterval Integrating (7.5.21) from to and using (7.5.44) and the fact that for we obtain

Summing this equation from j=1 to j=k, we see that We set so this equation becomes

In particular, as desired. To determine X(t) for we integrate (7.5.21) from to t to obtain

Therefore, We now proceed with the change of numeraire as before. This leads again to Theorem for the discretely sampled Asian call with payoff (7.5.42). The price at time t is given by (7.5.40), where g(t,x) satisfies (7,5,39) with boundary conditions (7.5.38) and (7.5.41). The only difference is that now the nonrandom function appearing in (7.5.39) is given by (7.5.43) and (7.5.45) and the process X(t) in (7.5.40) is given by (7.5.48).

5.2 Risk-Neutral Measure Girsanov’s Theorem for a Single Brownian Motion Thm1.6.1:probability space Z>0 ; E[Z]=1 We defined new probability measure (5.2.1) Any random variable X has two expectations:

5.2.1 Girsanov’s Theorem for a Single Brownian Motion If P{Z>0}=1 , then P and agree which sets have probability zero and (5.2.2) has the companion formula Z is the Radon-Nikody’m derivative of w.r.t. P, and we write

5.2.1 Girsanov’s Theorem for a Single Brownian Motion Suppose further that Z is an almost surely positive random variable satisfying E[Z]=1, and we define by (5.2.1). We can then define the We perform a similar change of measure in order to change mean, but this time for a whole process.

Lemma Lemma Let t satisfying be given and let Y be an -measurable random variable. Then Proof:

Lemma Lemma Let s and t satisfying be given and let Y be an -measurable random variable. Then

Lemma PROOF : : measurable We must check the partial-averaging property (Definition 2.3.1(ii)), which in this case is the left hand side of(5.2.10)

5.2.1 Girsanov’s Theorem for a Single Brownian Motion ( Lemma 5.2.2)

Girsanov’s Theorem

5.2.1 Girsanov’s Theorem for a Single Brownian Motion( Girsanov, one dimension) Using Levy’s Theorem : The process starts at zero at t=0 and is continuous. Quadratic variation=t It remain to show that is a martingale under

5.2.1 Girsanov’s Theorem for a Single Brownian Motion( Girsanov, one dimension) Check Z(t) to change of measure. We take and Z(t)=exp{X(t)} ( f(X)=exp{X}) By Ito’s lemma( next page):

5.2.1 Girsanov’s Theorem for a Single Brownian Motion( Girsanov, one dimension) no drift term>>martingale

5.2.1 Girsanov’s Theorem for a Single Brownian Motion( Girsanov, one dimension) Integrating>> Z(t) is Ito’ integral >>Z(t)~ martingale So,EZ=EZ(T)=Z(0)=1. Z(t) is martingale and Z=Z(T),we have Z(t) is a

5.2.1 Girsanov’s Theorem for a Single Brownian Motion( Girsanov, one dimension) We next show that is martingale under P is a martingale under