Exercise 2.5 If each number is represented with 5 bits, 7 = 00111 in all three systems -7 = 11000 (1's complement) = 10111 (signed magnitude) = 11001 (2's.

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Presentation transcript:

Exercise 2.5 If each number is represented with 5 bits, 7 = in all three systems -7 = (1's complement) = (signed magnitude) = (2's complement)

Exercise 2.8 The answers are: (a) 127 in decimal, in binary. (b) -128 in decimal, in binary. (c) (2n^(n-1))-1 (d) -(2n^(n-1))

Exercise 2.10 The answers are: (a) -6 (b) 90 (c) -2 (d) 14803

Exercise 2.11 (a) (b) (c) (d) (e)

Exercise 2.13 (a) (b) (c) (d)

Exercise 2.16 (a) (binary) or -0 (decimal) (b) (binary) or -14(decimal) (c) (binary) or 0 (decimal)

Exercise 2.17 (a) 1100 (binary) or -4 (decimal) (b) (binary) or 84 (decimal) (c) 0011 (binary) or 3 (decimal) (d) 11 (binary) or -1 (decimal)

Exercise 2.20 (a) = = -1 (b) = = 0 (c) = 1000 OVERFLOW! = -8 (d) = = 0111 OVERFLOW! = -8 + (-1) = 7 (e) = = 0

Exercise 2.26 (a) 7 bits. (b) 63 in decimal ( in binary ) (c) 127 in decimal ( in binary )

Exercise 2.34 (a) 0111 (b) 0111 (c) 1101 (d) 0110

Exercise 2.36 (a) AND with (b) OR with (c) AND with (d) OR with (e) AND the BUSYNESS pattern with to isolate b2. Then add that result to itself 5 times.

Exercise 2.47 (a) -16 (b) 2047 (c) 22 (d)

Exercise 2.48 (a) x100 (b) x6F (c) x75BCD15 (d) xD4

Exercise 2.52

Exercise 2.53

Exercise 2.55 (a) 63 (b) 4^(n) – 1 (c) 310 (d) 222 (e) (f) (g) 4^(4m)

Exercise x 2^(12-7) = -52