Lecture 17 10/12/05. pH of diprotic acids Leucine H 2 L + ⇄ HL + H + pK a1 = 2.329 HL ⇄ L - + H + pK a2 = 9.747.

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Presentation transcript:

Lecture 17 10/12/05

pH of diprotic acids Leucine H 2 L + ⇄ HL + H + pK a1 = HL ⇄ L - + H + pK a2 = 9.747

Diprotic acids/bases When adding as H 2 L + or L - first dissociation dominates To solve pH - treat like monoprotic acid or monoprotic base To solve for concentration of all species [L - ] = K a2 (when you added H 2 L - ) [H 2 L + ] = K b2 (when you added L - )

When adding as HL (add 0.05 M) Use systematic equilibrium Equations Charge balance Mass balance K b expression K a expression K w Substitute to get equation in terms of H + and HL For Mass Balance a ssume: [HL] >> [H 2 L + ] and [HL] >> [L - ] So [HL]  0.05 M Solve for H +