1 Announcement #1 r Did you all receive homework #1 and #2? r Homework #3 will be available online during the day r Midterm.

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Presentation transcript:

1 Announcement #1 r Did you all receive homework #1 and #2? r Homework #3 will be available online during the day r Midterm

2 Announcement #2 r CS395/495 Advanced Networking r “Let’s bring down the Internet together!” r Classes m Analyzing some classical and novel networking papers You read the paper and provide a review before the class Two teams give opposite presentation in-favor and against the paper (20 minutes each) Two teams argue about the paper (20 minutes) The whole class discusses the paper (20 minutes)

3 CS395/495 Advanced Networking r Projects m I will provide you with initial suggestions m You are free to come up with your own idea for the project m We will submit the best paper to a conference r Goals m To help you learn how to do networking (or more broadly systems) research m To help you learn how to argue and convey your ideas

4 Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing

5 Network layer r transport segment from sending to receiving host r on sending side encapsulates segments into datagrams r on rcving side, delivers segments to transport layer r network layer protocols in every host, router r Router examines header fields in all IP datagrams passing through it network data link physical network data link physical network data link physical network data link physical network data link physical network data link physical network data link physical network data link physical application transport network data link physical application transport network data link physical

6 Key Network-Layer Functions r forwarding: move packets from router’s input to appropriate router output r routing: determine route taken by packets from source to dest. m Routing algorithms analogy: r routing: process of planning trip from source to dest r forwarding: process of getting through single interchange

value in arriving packet’s header routing algorithm local forwarding table header value output link Interplay between routing and forwarding

8 Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing

9 Network layer connection and connection-less service r Datagram network provides network-layer connectionless service r VC network provides network-layer connection service r Analogous to the transport-layer services, but: m Service: host-to-host m No choice: network provides one or the other m Implementation: in the core

10 Virtual circuits r call setup, teardown for each call before data can flow r each packet carries VC identifier (not destination host address) r every router on source-dest path maintains “state” for each passing connection r link, router resources (bandwidth, buffers) may be allocated to VC “source-to-dest path behaves much like telephone circuit” m performance-wise m network actions along source-to-dest path

11 VC implementation A VC consists of: 1. Path from source to destination 2. VC numbers, one number for each link along path 3. Entries in forwarding tables in routers along path r Packet belonging to VC carries a VC number. r VC number must be changed on each link. m New VC number comes from forwarding table

12 Forwarding table VC number interface number Incoming interface Incoming VC # Outgoing interface Outgoing VC # … … Forwarding table in northwest router: Routers maintain connection state information!

13 Virtual circuits: signaling protocols r used to setup, maintain teardown VC r used in ATM, frame-relay, X.25 r not used in today’s Internet application transport network data link physical application transport network data link physical 1. Initiate call 2. incoming call 3. Accept call 4. Call connected 5. Data flow begins 6. Receive data

14 Datagram networks r no call setup at network layer r routers: no state about end-to-end connections m no network-level concept of “connection” r packets forwarded using destination host address m packets between same source-dest pair may take different paths application transport network data link physical application transport network data link physical 1. Send data 2. Receive data

15 Datagram vs. VC r Which of the above introduces larger signaling load? m VC each time a new connection arrives – a new VC has to be set Each time a connection is closed – the state has to be changed in each router along the path m Datagram No changes in routing tables are made because of flow arrivals/departures Changes are made on much longer time-scales (e.g., hours, days)

16 Forwarding table Destination Address Range Link Interface through through through otherwise 3 4 billion possible entries

17 Longest prefix matching Prefix Match Link Interface otherwise 3 DA: Examples DA: Which interface?

18 Datagram or VC network: why? Internet r data exchange among computers m “elastic” service, no strict timing req. r “smart” end systems (computers) m can adapt, perform control, error recovery m simple inside network, complexity at “edge” r many link types m different characteristics m uniform service difficult ATM r evolved from telephony r human conversation: m strict timing, reliability requirements m need for guaranteed service r “dumb” end systems m telephones m complexity inside network

19 Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing

value in arriving packet’s header routing algorithm local forwarding table header value output link Interplay between routing and forwarding

21 u y x wv z Graph: G = (N,E) N = set of routers = { u, v, w, x, y, z } E = set of links ={ (u,v), (u,x), (v,x), (v,w), (x,w), (x,y), (w,y), (w,z), (y,z) } Graph abstraction Remark: Graph abstraction is useful in other network contexts Example: P2P, where N is set of peers and E is set of TCP connections

22 Graph abstraction: costs u y x wv z c(x,x’) = cost of link (x,x’) - e.g., c(w,z) = 5 cost could always be 1, or inversely related to bandwidth, or inversely related to congestion Cost of path (x 1, x 2, x 3,…, x p ) = c(x 1,x 2 ) + c(x 2,x 3 ) + … + c(x p-1,x p ) Question: What’s the least-cost path between u and z ? Routing algorithm: algorithm that finds least-cost path

23 Routing Algorithm classification Global or decentralized information? Global: r all routers have complete topology, link cost info r “link state” algorithms Decentralized: r router knows physically- connected neighbors, link costs to neighbors r iterative process of computation, exchange of info with neighbors r “distance vector” algorithms Static or dynamic? Static: r routes change slowly over time Dynamic: r routes change more quickly m periodic update m in response to link cost changes

24 Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing

25 A Link-State Routing Algorithm Dijkstra’s algorithm r net topology, link costs known to all nodes m accomplished via “link state broadcast” m all nodes have same info r computes least cost paths from one node (‘source”) to all other nodes m gives forwarding table for that node r iterative: after k iterations, know least cost path to k dest.’s Notation:  c(x,y): link cost from node x to y; = ∞ if not direct neighbors  D(v): current value of cost of path from source to dest. v  p(v): predecessor node along path from source to v  N': set of nodes whose least cost path definitively known

26 Dijsktra’s Algorithm 1 Initialization: 2 N' = {u} 3 for all nodes v 4 if v adjacent to u 5 then D(v) = c(u,v) 6 else D(v) = ∞ 7 8 Loop 9 find w not in N' such that D(w) is a minimum 10 add w to N' 11 update D(v) for all v adjacent to w and not in N' : 12 D(v) = min( D(v), D(w) + c(w,v) ) 13 /* new cost to v is either old cost to v or known 14 shortest path cost to w plus cost from w to v */ 15 until all nodes in N'

27 Dijkstra’s algorithm: example Step N' u ux uxy uxyv uxyvw uxyvwz D(v),p(v) 2,u D(w),p(w) 5,u 4,x 3,y D(x),p(x) 1,u D(y),p(y) ∞ 2,x D(z),p(z) ∞ 4,y u y x wv z

28 Dijkstra’s algorithm, discussion Algorithm complexity: n nodes r each iteration: need to check all nodes, w, not in N r n(n-1)/2 comparisons: O(n 2 ) r more efficient implementations possible: O(nlogn) Oscillations possible: r e.g., link cost = amount of carried traffic A D C B 1 1+e e 0 e A D C B 2+e e 1 A D C B 0 2+e 1+e A D C B 2+e 0 e 0 1+e 1 initially … recompute routing … recompute