CH3Br, 031009: Energetics for CH 3 Br(g) -> H2(g) + C(g) + HBr(g) agust,heima,...Nov09/PPT-031109ak.ppt.

Slides:



Advertisements
Similar presentations
IR spectroscopy.
Advertisements

CH3Br, Energy for CH3Br ->->-> CH3 + Br
CF3Br Literature survey on energetics: agust,www,....cf3br/PPT ak.ppt Updated: ; 13:35 o´clock.
CH3Br, C atomic line assignments Agust, heima,....Sep09/CH3Br 16500_ vhw.pxp Agust, www,....Sept09/PPT ak.ppt.
HBr: 1)Bond energies 2)Energetics 3)Summary of our published (3+n) REMPI of HBr 4)Possible Br (3+1)REMPI lines agust,www,....Jan11/PPT ak.ppt agust,heima,....Jan11/XLS ak.xls.
MOLECULAR STRUCTURE CHAPTER 11 Experiments show O 2 is paramagnetic.
CH3Br, HBr detection agust, www,...Sept09/PPT ak.ppt.
CH 3 Br, Ion energetics agust,heima,...CH3Br/AFSTODUMYND hrh.pxp agust,www,....ch3br/PPT ak.ppt.
CH3Br, )PD summary status 2)Thresholds for direct excitations 3)CH3+ formation energetics / thresholds (direct and indirect)/ PD agust, heima,.....Dec09/CH3Br-Overall.
1 CH3Br, C, C* and C** dissociation formation channels vs C+ spectra Explanation for enhanced C+ Rydberg state spectra in the cm-1.
1 CH3Br, Energetics for CH2+ and CH+ formations agust,www,...Mars10/PPT ak.ppt.
CH3Br agust,www,...Sept09/PPt ak.ppt agust,heima,....Sept09/CH3BR avhwak.pxp agust,heima,....Sept09/CH3BR bvhwak.pxp.
Chemical Bonding I: Lewis Theory
5.1 MEASURING ENERGY CHANGES Thermodynamics is the study of energy and how it is interconverted. First law of thermodynamics – energy cannot be created.
Consider this reaction: N 2 (g) + 3H 2 (g) ----> 2 NH 3 (g) + 92 kJ  G 298K = kJ What does this equation tell us?
Thermochemistry. Thermochemistry is the study of heat changes that occur during chemical reactions. Heat (q) - energy that is transferred from one object.
CHEM 433 – 9/9/11 I.Introductory Topics B. Molecules and Energy (Ch. 0) - Definitions & Introductory comments - Energy Units - How do molecules Store energy?
HBr Energetics agust,www,....hbr/PPT ak.ppt agust, heima,...HBr/XLS ak.xls.
5.3 Bond Enthalpy. Understanding Bond forming releases energy and bond breaking requires energy. Bonds form because it is energetically favorable to do.
HESS’S LAW what is it ? how is it used ? AS Chemistry.
HC CHEMISTRY HC CHEMISTRY NATURES’ CHEMISTRY (F) Skin Care.
Chapter 16 Preview Multiple Choice Short Answer Extended Response
Topic VIII: “ Chemical Reactions”. Chapter 11 (Pearson)
Chapter 8 Chemical Bonding I: Basic Concepts
Aim: Explain the different types of Chemical Formulas
Chapter 17: Thermochemistry
Enthalpy.
Reaction Mechanisms Learning Goals:
Stoichiometry Mole-to-Mole:
Get out a piece of paper to take notes on.
IB SL Chemistry Mrs. Page
Energy changes in chemistry.
Quiz #12: Keq calculations and ICE charts
When a system is at equilibrium
SCH 4U1 Mr. Dvorsky Friday November 15
Bond enthalpies and mean bond enthalpies
The Formation of Halogenoalkanes
Transformation of Matter
Unit 5: Thermochemistry
2.50g C2H4 x 1 mole C2H4 x 2 mol CO2 x 22.4 L at STP = 4.00 L at STP
Bond Energy and Reaction Enthalpy
OBJECTIVES: RATE LAW, ORDER OF REACTION, k
Review Reaction mechanism Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l)
Chapter 8 Chemical Quantities in Reactions
Mr. Quinn & Ms. Tom March 24, 2014 Aim: How does chemical equilibrium correct itself? Do Now: What will happen to the size of the balloon.
Content: - Comparison of CH3 and CH2 KER - KER assignment for the two color experiment dissociation at 270 nm and probing of CH3 at nm (211 transition)
Molar Conversions (p.80-85, )
Review Reaction mechanism Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l)
13 Energetics Answers to Test yourself questions
Bond Energy and Calculations
OBJECTIVES: RATE LAW, ORDER OF REACTION, k
University of Kentucky
Section 11.4 Calculating Heat Changes
( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN
Review Reaction mechanism Br2(l) + C5H12(l)  C5H11Br(l) + HBr(l)
( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN
Free Energy and the Equilibrium Constant
Molecular Orbitals Two interacting orbitals make two new orbitals. Using a 1s orbital on two H atoms: anitbonding orbital = higher energy bonding orbital.
Lecture 15.
Chapter 16 Preview Multiple Choice Short Answer Extended Response
Chapter 5 Chemical Reactions and Quantities
CALCULATION OF ENTHALPY CHANGE USING BOND ENERGY
Conceptually Easy Example with Annoying Algebra:
1.2.6 Bond Enthalpies.
Chapter 5 Chemical Quantities and Reactions
Vibrational Spectroscopy
Chain reactions Chain reactions: a reaction intermediate produced in one step generates an intermediate in a subsequent step, then that intermediate generates.
Rotational Energy Levels for rigid rotor: Where Rotational Spectra of Rigid Diatomic molecule. BY G JANAKIRAMAN EGS A&S COLLAGE
Presentation transcript:

CH3Br, : Energetics for CH 3 Br(g) -> H2(g) + C(g) + HBr(g) agust,heima,...Nov09/PPT ak.ppt

CH 3 Br(g) -> H2(g) + C(g) + HBr(g) CH 3 (g) + Br(g)) 70.3 kcal mol -1 = cm -1 Handbook of bond energies: CH + (g) +H 2 (g) + Br(g)) eV =Appearance nergy eV = Bond energy (CH + ) C + (g) + H 2 (g) + H(g) + Br(g)) eV = = -D 0 0 (HBr) Huber and Herzberg: Constants of diatomic molecules C + (g) +H 2 (g) +HBr(g)) eV = cm -1 = - IE(C) notes eV= cm -1  E = = cm -1

CH3Br(g) -> H2(g) + C(g) + HBr(g) CH3(g) + Br(g)) 70.3 kcal mol-1 = cm-1 Handbook of bond energies: CH+(g) +H2(g) + Br(g)) eV CH+(g) +2H(g) + Br(g)) 4.5 eV eV C+(g) +3H(g) + Br(g)) cm eV = C+(g) +H2(g) +H(g) + Br(g)) eV = = -D 0 0 (HBr) Huber and Herzberg: Constants of diatomic molecules C+(g) +H2(g) +HBr(g)) eV = cm-1= - IE(C) notes