C 2 + c 2 = i 2 8 2 + 6 2 = i 2 64 + 36 = 100 Q1Q1 Q2Q2 Q1+ Q2Q1+ Q2.

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Presentation transcript:

C 2 + c 2 = i = i = 100

Q1Q1 Q2Q2 Q1+ Q2Q1+ Q2

Q 1 + Q 2 Q1+ Q2Q1+ Q2

cateto catetocateto ipotenusa

catetocateto cateto

Teorema di Pitagora applicato al triangolo isoscele. C AB H Dati h=12cm b=10cm CH=altezza=cateto HB=1\2base=cateto CB=lato=ipotenusa 13*2=26 cm 2 lati perimetro= base + 2 lati = = 36 cm HB 2 + CH 2 = CB = = = 169 = 13 lato=? 13 P=?36

catetocateto ipotenusa cateto

catetocateto ipotenusa cateto

catetocateto ipotenusa cateto