Splash Screen. Then/Now I CAN solve radical equations. Learning Target.

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Splash Screen. Then/Now I CAN simplify radical expressions by using the Product Property of Square Roots and the Quotient Property of Square Roots. Learning.

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Presentation transcript:

Splash Screen

Then/Now I CAN solve radical equations. Learning Target

Concept Radical Equations – equations that contain radicals in the radicand.

Example 1 Variable as a Radicand FREE-FALL HEIGHT An object is dropped from an unknown height and reaches the ground in 5 seconds. Use the equation, where t is time in seconds and h is height in feet, to find the height from which the object was dropped. UnderstandYou know the time it takes for the object to hit the ground. You need to find the height.

Example 1 Variable as a Radicand Original equation Replace t with 5. Multiply each side by 4. Plan Solve

Example 1 Variable as a Radicand Square each side. 400 = h Simplify. Answer: The object was dropped from a height of 400 feet. Check by substituting 400 for h in the original equation. Original equation t = 5 and h = 400 ? ? 5 = 5  Divide.

A.A B.B C.C D.D Example 1 A.28 ft B.11 ft C.49 ft D.784 ft

Example 2 Expression as a Radicand x = 52Add 3 to each side. Answer: The solution is 52. Original equation Subtract 8 from each side. Square each side.

A.A B.B C.C D.D Example 2 A.64 B.60 C.4 D.196

Extraneous Solutions – when squaring each side of an equation you sometimes end up with a solution that is not a solution to the original equation.

Example 3 Variable on Each Side 2 – y =y 2 Simplify. 0=y 2 + y – 2 Subtract 2 and add y to each side. 0=(y + 2)(y – 1)Factor. y + 2=0 or y – 1= 0Zero Product Property y=–2 y = 1Solve. Original equation Square each side. Check your solution.

Example 3 Variable on Each Side Check Answer: Since –2 does not satisfy the original equation, 1 is the only solution. ? ? ? X ?

A.A B.B C.C D.D Example 3 A.3 B.–1 C.–1, 3 D.–3