Solving Systems of Linear Equations by Graphing

Slides:



Advertisements
Similar presentations
SOLUTION EXAMPLE 1 A linear system with no solution Show that the linear system has no solution. 3x + 2y = 10 Equation 1 3x + 2y = 2 Equation 2 Graph the.
Advertisements

Chapter 11 Systems of Equations.
Solving Special Systems
Unit 4 – Linear Systems in Two Dimensions Topic: Solving Linear Systems of Equations.
7.1 Systems of Linear Equations: Two Equations Containing Two Variables.
Review for Final Exam Systems of Equations.
Chapter 7 – Linear Systems
Solving Systems of Linear Equations and Inequalities
7.1 Graphing Linear Systems
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 11 Systems of Equations.
Solving Systems of Linear Equations by Graphing
Solving Systems of Linear Equations Graphically
Solving Special Systems
Linear Equations by Graphing
Topic: Solving Systems of Linear Equations by Graphing.
13.7 – Graphing Linear Inequalities Are the ordered pairs a solution to the problem?
Section 3.5 Systems of Equations. What is a system of equations? Two or more equations in the same variables.
Solving Special Systems
Copyright © 2015, 2011, 2007 Pearson Education, Inc. 1 1 Chapter 4 Systems of Linear Equations and Inequalities.
SOLVING SYSTEMS OF LINEAR EQUATIONS AND INEQUALITIES.
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 14 Systems of Equations.
Solving Systems of Linear Equations in Two Variables
Do Now 1/15/10 Copy HW in your planner. Copy HW in your planner. Text p. 462, #1-8 all, #10, #12, #16-30 evens, #36 Text p. 462, #1-8 all, #10, #12, #16-30.
Chapter 13 Section 2 Solutions of Systems of Equations.
Holt McDougal Algebra Solving Special Systems Warm Up Solve each equation. 1. 2x + 3 = 2x (x + 1) = 2x + 2 no solution infinitely many solutions.
 What is the slope of the line that passes through the following points. 1.(-2, 5) (1, 4)  Identify the slope and y -intercept of each equation. 2.y.
This screen shows two lines which have exactly one point in common. The common point when substituted into the equation of each line makes that equation.
What is a system of equations? A system of equations is when you have two or more equations using the same variables. The solution to the system is the.
Solving Systems of Equations by Graphing
Copyright © 2014, 2010, and 2006 Pearson Education, Inc. 8-1 Copyright © 2014, 2010, and 2006 Pearson Education, Inc. Chapter 8 Systems of Linear Equations.
Systems of Linear Equations A system of linear equations consists of two or more linear equations. We will focus on only two equations at a time. The solution.
Holt Algebra Solving Special Systems 6-4 Solving Special Systems Holt Algebra 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Lesson Quiz.
Copyright © 2014, The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
Objective: To solve a system of linear equations by graphing and substitution.
Chapter 3 Systems of Equations. Solving Systems of Linear Equations by Graphing.
Systems of Equations.
10.1 SYSTEMS OF LINEAR EQUATIONS: SUBTRACTION, ELIMINATION.
EXAMPLE Determine whether the given point is a solution of the following system. point: (– 3, 1) system: x – y = – 4 2x + 10y = 4 Plug.
Systems of linear equations
Solving Special Systems
Solving Equations with Variables on Both Sides
Solving Special Systems
Solving Systems of Linear Equations and Inequalities
5.1 Graphing Systems of Equations
6-1 Solving Systems by Graphing
Solve Systems of Equations
Solving Special Systems
Graphing systems of linear equations and inequalities
Do Now 1/18/12 In your notebook, explain how you know if two equations contain one solution, no solutions, or infinitely many solutions. Provide an example.
Warm-Up What do you have to do to make this problem solvable?
Solving Special Systems
Graphing Systems of Equations.
Lesson Objectives: I will be able to …
Solving Special Systems
Systems of Linear Equations and Problem Solving
Solving Special Systems
Objectives Identify solutions of linear equations in two variables.
Solving Special Systems
Solving Special Systems
Systems of Equations Solving by Graphing.
Solving Special Systems
Algebra 1 Section 7.5.
Graphing Systems of Equations.
Solving Special Systems
7.5 Special Types of Linear Systems
Solving Special Systems
Chapter 5 Review.
Solving Special Systems
4 Chapter Chapter 2 Solving Systems of Linear Equations.
Linear Systems of Equations
Presentation transcript:

Solving Systems of Linear Equations by Graphing 4.1 Solving Systems of Linear Equations by Graphing

Systems of Linear Equations A system of linear equations consists of two or more linear equations. This section focuses on solving systems of linear equations containing two equations in two variables. A solution of a system of linear equations in two variables is an ordered pair of numbers that is a solution of both equations in the system.

Example Determine whether (–3, 1) is a solution of the system x – y = – 4 2x + 10y = 4 Replace x with –3 and y with 1 in both equations. First equation: –3 – 1 = – 4 True Second equation: 2(–3) + 10(1) = – 6 + 10 = 4 True Since the point (–3, 1) produces a true statement in both equations, it is a solution of the system.

Example Determine whether (4, 2) is a solution of the system 2x – 5y = – 2 3x + 4y = 4 Replace x with 4 and y with 2 in both equations. First equation: 2(4) – 5(2) = 8 – 10 = – 2 True Second equation: 3(4) + 4(2) = 12 + 8 = 20 ≠ 4 False Since the point (4, 2) produces a true statement in only one equation, it is NOT a solution.

Solving Systems of Equations by Graphing Since a solution of a system of equations is a solution common to both equations, it is also a point common to the graphs of both equations. To find the solution of a system of two linear equations, we graph the equations and see where the lines intersect.

Example Solve the system of equations by graphing. 2x – y = 6 (-5, 5) (6, 6) (-2, 4) (4, 2) (1, 3) First, graph 2x – y = 6. (3, 0) Second, graph x + 3y = 10. The lines APPEAR to intersect at (4, 2). (0, -6) continued

continued Although the solution to the system of equations appears to be (4, 2), you still need to check the answer by substituting x = 4 and y = 2 into the two equations. First equation: 2(4) – 2 = 8 – 2 = 6 True Second equation: 4 + 3(2) = 4 + 6 = 10 True The point (4, 2) checks, so it is the solution of the system.

Helpful Hint Neatly drawn graphs can help when “guessing” the solution of a system of linear equations by graphing.

Example Solve the system of equations by graphing. –x + 3y = 6 (6, 4) (0, 2) (6, 1) (3, 0) First, graph – x + 3y = 6. (-6, 0) (0, -1) Second, graph 3x – 9y = 9. The lines APPEAR to be parallel. continued

continued Although the lines appear to be parallel, we need to check their slopes. –x + 3y = 6 First equation 3y = x + 6 Add x to both sides. y = x + 2 Divide both sides by 3. 3x – 9y = 9 Second equation –9y = –3x + 9 Subtract 3x from both sides. y = x – 1 Divide both sides by –9. Both lines have a slope of , so they are parallel and do not intersect. Hence, there is no solution to the system.

Example Solve the system of equations by graphing. x = 3y – 1 (5, 2) (-1, 0) (2, 1) First, graph x = 3y – 1. (-4, -1) (7, -2) Second, graph 2x – 6y = –2. The lines APPEAR to be identical. continued

continued Although the lines appear to be identical, we need to check that their slopes and y-intercepts are the same. x = 3y – 1 First equation 3y = x + 1 Add 1 to both sides. y = x + Divide both sides by 3. 2x – 6y = – 2 Second equation –6y = – 2x – 2 Subtract 2x from both sides. y = x + Divide both sides by -6. Any ordered pair that is a solution of one equation is a solution of the other. This means that the system has an infinite number of solutions.

Identifying Special Systems of Linear Equations There are three possible outcomes when graphing two linear equations in a plane. One point of intersection—one solution Parallel lines—no solution Coincident lines—infinite number of solutions If there is at least one solution, the system is considered to be consistent. If the system defines distinct lines, the equations are independent.

Possible Solutions of Linear Equations Graph Type of System Number of Solutions If the lines intersect, the system of equations has one solution given by the point of intersection. Consistent The equations are independent. (3, 5) Two lines intersect at one point. If the lines are parallel, then the system of equations has no solution because the lines never intersect. Inconsistent The equations are independent. Parallel lines If the lines lie on top of each other, then the system has infinitely many solutions. The solution set is the set of all points on the line. Consistent The equations are dependent. Lines coincide

Identifying Special Systems of Linear Equations Since there are only three possible outcomes with two lines in a plane, we can determine how many solutions of the system there will be without graphing the lines. Change both linear equations into slope-intercept form. We can then easily determine if the lines intersect, are parallel, or are the same line.

Example Without graphing, determine the number of solutions of the system. 3x + y = 1 3x + 2y = 6 Write each equation in slope-intercept form. 3x + y = 1 First equation y = –3x + 1 Subtract 3x from both sides. 3x + 2y = 6 Second equation 2y = –3x + 6 Subtract 3x from both sides. Divide both sides by 2. The lines are intersecting lines (since they have different slopes), so the system is consistent and independent and has one solution.

Example Without graphing, determine the number of solutions of the system. 3x + y = 0 2y = –6x Write each equation in slope-intercept form. 3x + y = 0 First equation y = –3x Subtract 3x from both sides. 2y = –6x Second equation y = –3x Divide both sides by 2. The two lines are identical, so the system is consistent and dependent, and there are infinitely many solutions.

Example Without graphing, determine the number of solutions of the system. 2x + y = 0 y = –2x + 1 Write each equation in slope-intercept form. 2x + y = 0 First equation y = –2x Subtract 2x from both sides. y = –2x + 1 Second equation is already in slope-intercept form. The two lines are parallel lines. Therefore, the system is inconsistent and independent, and there are no solutions.