Spectral Regions and Transitions

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Presentation transcript:

Spectral Regions and Transitions Infrared radiation induces stretching of bonds, and deformation of bond angles. Associated with each vibrational transition for gas phase molecules is a series of rotational levels leading to more complex rotation-vibrational transitions symmetrical stretch H-O-H symmetrical deformation (H-O-H bend) asymmetrical stretch H-O-H

Vibrational States and Transitions The simplest case is a diatomic molecule. Rotations (2) and translations (3) leave only one vibrational degree of freedom, the bond length change, Dr, a one dimensional harmonic oscillator One can solve this problem exactly as a classical Hook’s law problem with a restoring force: F = –kDr and potential energy: V=1/2 k(Dr)2 Quantum mechanically: Ev = (v+1/2)hn , n is the vibration frequency

Model for vibrational spectroscopy Harmonic Oscillator Model for vibrational spectroscopy v = 1 v = 2 v = 3 v = 4 v = 0 hn 1 2 3 5 7 9 E re Ev = (v+½)hn Dv =  1 DE = hn n = (1/2p)(k/m)½ (virtual state) Raman IR re r re q

Vibrational States and Transitions for the simplest harmonic oscillator case (diatomic): n = (1/2p)(k/µ)1/2 where k is the force constant (d2V/dq2). In practice, stronger bonds have sharper (more curvature) potential energy curves, result: higher k, and higher frequency. and µ is the reduced mass [m1m2 / (m1+m2)]. In practice, heavier atom moving, have lower frequency.  vibrational frequencies reflect structure, bonds and atoms

Vibrational States and Transitions Summary: high mass ==> low frequency strong bond ==> high frequency Some simple examples (stretches in polyatomics): -C-C- ~1000 cm-1 C-H ~2800 cm-1 -C=C- ~1600 cm-1 C-D ~2200 cm-1 -C  C- ~2200 cm-1 C---N ~1300 cm-1

Polyatomic Vibrational States For a molecule of N atoms, there are (3N-6) vibrational degrees of freedom. This complex problem can be solved the harmonic approximation by transforming to a new set of normal coordinates (combinations of internal coordinates, qi) to simplify the potential energy V—method unimportant for this course V = V0 + S (dV/dqi)0qi + (½) S (d2V/dqiqj)0qiqj + . . . . . This results in a molecular energy that is just the sum of the individual vibrational energies of each normal mode: E = S Ei = S (vi + ½) hni As a result we have characteristic IR and Raman frequencies, ni, which are reflect bond types in the molecule. The frequency pattern forms a “fingerprint” for the molecule and its structure. Variations due to conformation and environment give structural insight and are the prime tools for Protein IR and Raman.

Dipole Moment Interaction of light with matter can be described as the induction of dipoles, mind , by the light electric field, E: mind = a . E where a is the polarizability IR absorption strength is proportional to A ~ |<Yf |m| Yi>|2, transition moment between Yi Yf To be observed in the IR, the molecule must change its electric dipole moment, µ , in the transition—leads to selection rules dµ / dQi  0 Raman intensity is related to the polarizability, I ~ <Yb |a| Ya>2, similarly da / dQi  0 for Raman observation

IR vs. Raman Selection Rules At its core, Raman also depends on dipolar interaction, but it is a two-photon process, excite with n0 and detect ns, where nvib = n0 - ns, so there are two m’s. <Y0|m| Yi> • <Yi|m| Yn> ~ a => need a change in POLARIZABILITY for Raman effect Raman IR i n0 ns n n nvib = nn- n0 = DE / h nvib = n0- ns

Symmetry Selection Rules (Dipole, etc.) Example: symmetric stretch O=C=O infrared inactive dm/dQ = 0 Raman Intense da/dQ  0 asymmetric stretch O=C=O infrared active dm/dQ  0 bending O=C=O infrared active dm/dQ  0

Complementarity: IR and Raman If molecule is centrosymmetric, no overlap of IR and Raman

Vibrational Transition Selection Rules Harmonic oscillator: only one quantum can change on each excitation D vi = ± 1, D vj = 0; i  j . These are fundamental vibrations Anharmonicity permits overtones and combinations Normally transitions will be seen from only vi = 0, since most excited states have little population. Population, ni, is determined by thermal equilibrium, from the Boltzman relationship: ni = n0 exp[-(Ei-E0)/kT], where T is the temperature (ºK) – (note: kT at room temp ~200 cm-1)

Anharmonic Transitions Real molecules are anharmonic to some degree so other transitions do occur but are weak. These are termed overtones (D vi = ± 2,± 3, . .) or combination bands (D vi = ± 1, D vj = ± 1, . .). ( r - re )/re E/De DE01 = hnanh D0 Biological systems we generally overlook this, most important in C-H stretch region

Peak Heights Beer-Lambert Law: A = lc A = Absorbance  = Absorptivity l = Pathlength c = Concentration An overlay of 5 spectra of Isopropanol (IPA) in water. IPA Conc. varies from 70% to 9%. Note how the absorbance changes with concentration. The size (intensity) of absorbance bands depend upon molecular concentration and sample thickness (pathlength) The Absorptivity () is a measure of a molecule’s absorbance at a given wavenumber normalized to correct for concentration and pathlength – but as shown can be concentration dependent if molecules interact

Peak Widths Water Water Benzene Peak Width is Molecule Dependent Strong Molecular Interactions = Broad Bands Weak Molecular Interactions = Narrow Bands