Trapezoids and Kites Chapter 8, Section 5 (8.5).

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Presentation transcript:

Trapezoids and Kites Chapter 8, Section 5 (8.5)

Essential Questions How do I use properties of trapezoids? How do I use properties of kites?

Vocabulary Trapezoid – a quadrilateral with exactly one pair of parallel sides. A trapezoid has two pairs of base angles. In this example the base angles are A & B and C & D leg base

8.14 Base Angles Trapezoid Theorem If a trapezoid is isosceles, then each pair of base angles is congruent.  A   B,  C   D

8.15 Base Angles Trapezoid Converse If a trapezoid has a pair of congruent base angles, then it is an isosceles trapezoid. ABCD is an isosceles trapezoid

8.16 Diagonals of a Trapezoid Theorem A trapezoid is isosceles if and only if its diagonals are congruent.

Example 1 PQRS is an isosceles trapezoid. Find m P, m Q and mR. m R = 50 since base angles are congruent mP = 130 and mQ = 130 (consecutive angles of parallel lines cut by a transversal are )

Definition Midsegment of a trapezoid – the segment that connects the midpoints of the legs.

8.17 Midsegment Theorem for Trapezoids The midsegment of a trapezoid is parallel to each base and its length is one half the sum of the lengths of the bases.

Definition Kite – a quadrilateral that has two pairs of consecutive congruent sides, but opposite sides are not congruent.

8.18 Theorem: Perpendicular Diagonals of a Kite If a quadrilateral is a kite, then its diagonals are perpendicular.

8.19 Theorem: Opposite Angles of a Kite If a quadrilateral is a kite, then exactly one pair of opposite angles are congruent A  C, B  D

Example 2 Find the side lengths of the kite.

Example 2 Continued We can use the Pythagorean Theorem to find the side lengths. 122 + 202 = (WX)2 144 + 400 = (WX)2 544 = (WX)2 122 + 122 = (XY)2 144 + 144 = (XY)2 288 = (XY)2

Example 3 Find mG and mJ. Since GHJK is a kite G  J So 2(mG) + 132 + 60 = 360 2(mG) =168 mG = 84 and mJ = 84

Try This! RSTU is a kite. Find mR, mS and mT. x +30 + 125 + 125 + x = 360 2x + 280 = 360 2x = 80 x = 40 So mR = 70, mT = 40 and mS = 125

Homework Pages 546 (7-15)