Unit 12: Gas Laws Ch. 14. The Kinetic Theory of Gases Assumes the following statements about gas behavior: –Do not attract or repel each other. This is.

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Presentation transcript:

Unit 12: Gas Laws Ch. 14

The Kinetic Theory of Gases Assumes the following statements about gas behavior: –Do not attract or repel each other. This is because they are so spread out. –The distance between one particle and another is much larger than the size of the particles themselves. Therefore, almost all of the volume of a gas is empty space. –Are in constant, random motion. –No kinetic energy is lost when gas particles collide with each other or the sides of their container. These collisions are called elastic. –All gases have the same average kinetic energy at a given temperature. As temperature increases, energy increases.

Characteristics of Gases Gases expand to fill any container. –random motion, no attraction Gases are fluids (like liquids). –no attraction Gases have very low densities. –no volume = lots of empty space

Characteristics of Gases Gases can be compressed. –no volume = lots of empty space Gases undergo diffusion. –random motion

Pressure Which shoes create the most pressure?

Atmospheric Pressure The earth is surrounded by an atmosphere that extends for hundreds of kilometers. This blanket of air is pushing down on us at all times. At sea level, the pressure is equal to 14.7 pounds per square inch. (pounds is the force unit, square inch is the area unit) Atmospheric pressure is measured with a barometer. The barometer was invented by Evangelista Torricelli ( ). Torricelli said, “We live at the bottom of an ocean of air.”

Torricelli’s barometer:

Pressure Barometer –measures atmospheric pressure Mercury Barometer Aneroid Barometer

Pressure varies with altitude. The higher the altitude, the lower the atmospheric pressure, because there is less atmosphere piled on top of you if you are higher on the earth’s surface. Also, the air tends to be “thinner” at higher altitudes. Examples: LocationElevationAtmospheric Pressure in pounds per square inch (psi) Galveston, TXSea level14.7 psi Denver, CO5280 ft12.2 psi Pike’s Peak, CO14,000 ft8.8 psi Top of Mt. Everest29,000 ft4.9 psi

Pressure Units and Conversions Pressure units can look a bit strange. Here is an explanation of the ones you will most commonly use: Pounds per square inch = psi; simply expresses the force in pounds over an area in inches2 Atmosphere = atm; 1 atm is the pressure at sea level (the entire atmosphere is pushing down) Millimeters of mercury or inches of mercury = mm Hg or in Hg; comes from the height that Hg climbs in a barometer Torr; named after Torricelli and is equal to mm Hg Pascal = Pa; named after Blaise Pascal, a famous scientist who studied gas pressure

Conversions Kilopascal = kPa; just 1000 times greater than a Pascal Relationships between pressure units: **important for conversions!!! 1 atm = 14.7 psi = 760 mm Hg = 29.9 in Hg = 760 Torr = 101,300 Pa = kPa

Try these pressure conversions: atm = ? kPa Torr = ? mm Hg psi = ? Atm kPa = ? psi

Relationships between Pressure, Volume, and Temperature of a Gas Pressure and Temperature Assume that the volume of the container is constant. As temperature increases, pressure increases. The higher the T, the more kinetic energy the particles get. They hit the walls more often and with greater force, so P goes up. As temperature decreases, pressure decreases. DIRECT relationship. P is directly proportional to T. Graph: P T

Relationships between Pressure, Volume, and Temperature of a Gas Volume and Temperature Assume that the pressure of the container is constant. As temperature increases, volume increases. The higher the T, the more kinetic energy the particles get. Their increased motion causes the container to expand. As temperature decreases, volume decreases. DIRECT relationship. V is directly proportional to T. Graph: V T

Relationships between Pressure, Volume, and Temperature of a Gas Pressure and Volume Assume that the temperature of the container is constant. As volume increases, pressure decreases. This is because a greater volume results in less “crowded” particles; they have more space to move, so the pressure drops. As volume decreases, pressure increases. INVERSE relationship. P is inversely proportional to V. Graph: P V

Temperature ºF ºC K K = ºC Always use absolute temperature (Kelvin) when working with gases.

STP Standard Temperature & Pressure 0°C 273 K 1 atm kPa -OR- STP

Boyle’s Law The pressure and volume of a gas are inversely related –at constant mass & temp P V P 1 V 1 =P 2 V 2

Example: A 5.0 L container of nitrogen gas is at a pressure of 1.0 atm. What is the new pressure if the volume is decreased to 500 mL, and the temperature remains constant? Formula needed Rearrange for unknown Plug-in to formula Include units and cancellation! Final answerUnit Unit conversion(s) needed:

V T Charles’ Law The volume and absolute temperature (K) of a gas are directly related –at constant mass & pressure

Example: A container of helium gas at 25oC in an expandable 500 mL container is heated to 80.oC. What is the new volume if the pressure remains constant? Formula needed Rearrange for unknown Plug-in to formula Include units and cancellation! Final answerUnit Unit conversion(s) needed:

P T Gay-Lussac’s Law The pressure and absolute temperature (K) of a gas are directly related –at constant mass & volume

Example: A tank of propane gas at a pressure of 3.0 atm is cooled from 90.oC to 30.oC. What is the new pressure if the volume remains constant? Formula needed Rearrange for unknown Plug-in to formula Include units and cancellation! Final answerUnit Unit conversion(s) needed:

= kPV PTPT VTVT T Combined Gas Law P1V1T1P1V1T1 = P2V2T2P2V2T2 P 1 V 1 T 2 = P 2 V 2 T 1

Example: A helium-filled balloon at sea level has a volume of 2.1 L at atm and 36 o C. If it is released and rises to an elevation at which the pressure is atm and the temperature is 28 o C, what will be the new volume of the balloon? Formula needed Rearrange for unknown Plug-in to formula Include units and cancellation! Final answerUnit Unit conversion(s) needed:

Ideal Gas Law The ideal gas law is different from the previous laws in that it is not used for “initial and final conditions” problems. It only uses one set of conditions, and it incorporates the moles of the gas, represented by n. You will also need the ideal gas constant, R. R = L atm The units in your problem K mol must match R!

A. Ideal Gas Law UNIVERSAL GAS CONSTANT R= L  atm/mol  K PV=nRT You don’t need to memorize these values!

YOU MUST CONVERT: P into atm –Use pressure conversions V into L –Divide by 1000 if mL n into moles –divide by molecular weight T into K –Add 273 to Celcius

Example: 32.0 g of oxygen gas is at a pressure of 760 mm Hg and a temperature of 0 o C. What is the volume of the gas? Formula needed Rearrange for unknown Plug-in to formula Include units and cancellation! Final answerUnit Unit conversion(s) needed:

Example: A sample of helium gas is in a 500. mL container at a pressure of 2.00 atm. The temperature is 27 o C. What is the mass of the gas? Formula needed Rearrange for unknown Plug-in to formula Include units and cancellation! Final answerUnit Unit conversion(s) needed:

Gas Stoichiometry Review the 3 basic steps in stoichiometry: 1) Identify the given, and convert it to moles if not already in moles. 2) Identify the unknown, and do a mole-to-mole ratio between given and unknown using the coefficients from the balanced equation. This is the key step: it gets you from moles of given to moles of unknown. 3) Convert the unknown to the unit specified in the problem. If it asks for moles, you are finished at step 2!

Example: 4 Fe(s) + 3 O 2 (g)  2 Fe 2 O 3 (s) Calculate the volume of oxygen gas at STP that is required to completely react with 52.0 g of iron.

Example: 4 Fe(s) + 3 O 2 (g)  2 Fe 2 O 3 (s) Refer to the equation above. If 22.4 L of oxygen gas is reacted at STP (with an excess of iron), how many grams of iron (III) oxide will be formed?

V n Avogadro’s Law Equal volumes of gases contain equal numbers of moles –at constant temp & pressure –true for any gas

Avogadro’s Law Avogadro’s Law says that equal volumes of gases at the same temperature and pressure contain equal numbers of moles. This means that the coefficients in the balanced equation stand for volume as well as moles, but only for the gases.

Example N2(g) + 3 H2(g)  2 NH3(g) If 25.0 L of nitrogen gas is reacted with an excess of hydrogen, what volume of ammonia is produced?

Example 2 H 2 (g) + O 2 (g)  2 H 2 O(g) If 300. mL of water vapor is produced in the above reaction, how many mL of oxygen reacted?