SURVIVOR Polynomials, GCF, Double Distributive. Simplify the expression below 2y + 3 – 5y – 2 a. 3y + 1 b. -3y-1 c. -3y + 1 d. 3y -1.

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Presentation transcript:

SURVIVOR Polynomials, GCF, Double Distributive

Simplify the expression below 2y + 3 – 5y – 2 a. 3y + 1 b. -3y-1 c. -3y + 1 d. 3y -1

What is the greatest common factor of 16y and 20y 2 a. 16y b. 8y 2 c. 4y 2 d. 4y

True or False: A method used to multiply two monomials is called “double distributive”.

Solve the equation below 9y – 3 = 7y + 5 a. - 8 b. - 4 c. 0.5 d. 4

Multiply the two binomials below: (2x – 1)(2x + 4) a. 4x 2 – 6x + 4 b. 4x 2 + 6x – 4 c. x 2 + 6x – 4 d. 4x 2 – 4

What is the value of the expression b 2 – a 2 if a = 4 and b = -4 a. -8 b. -4 c. 0 d. 8

Which operation do you perform first in the expression: 3x + 5 (3x + 2x) - 8 a. parenthesis b. multiplication c. addition d. subtraction

Which ordered pair (x, y) is on the line y = 4x – 3? a. (0, 3) b. (2, 5) c. (1, -1) d. (-1, -3)

What is the quotient of 21x 6 y 3 and -7xy 2 ? a. 3x 7 y 5 b. 3x 5 y c. -3x 7 y 5 d. -3x 5 y

Simplify the expression (4x 2 + 9x) – (-2x 2 + 4x – 5) a. 6x 2 + 5x + 5 b. 5x + 5 c. 4x 2 + 5x + 5 d. 6x 2 + 5x – 5

Khadijah spent $144 for 4 pairs of jean each of equal cost. Which expression represents the cost of one pair of jeans? a. 144 ÷ 4 b c. 144 x 4 d

What is the GCF of 12m 2 n 3, 3mn, and 15m 2 n? a.3mn b.15m 2 n c.24m 2 n d.60m 2 n 3

What is the product of (r 4 ) and (-3r 2 )? a. -3r 8 b. -3r 6 c. 3r 2 d. 3r 6

Which expression shows (6x 4 x 3 )÷ 2x simplified? a. 12x 8 b. 3x 6 c.12x 12 d. 3x 12

True or False The product of (3x – 1) and (2x + 4) is 6x x - 4

Which value is equivalent to the expression a. -14 b. 4 c. 6 d. 210

True of False The value of x 4 divided by x 4 is x 0.

Factor the expression 8x x x 5 a. 8x 2 (1 +2x 2 + 4x 3 ) b. 8x 2 (0 +2x 2 + 4x 3 ) c. 8x 2 (2x +4x 3 + 8x 4 ) d. 4x 2 (2 +4x 2 + 8x 3 )

True of False The product of 2y and (3y-10) could be solved by using the Distributive property.

Which solution is correct? (5a 2 – 2a +5) – (a 2 + 2a -5) a. -4a +6a 2 +5 b. 4a 2 – 4a c a 2 d. 4a 2 – 4a + 10