3 properties of elements Atomic radius Ionisation energy Electronegativity.

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Presentation transcript:

3 properties of elements Atomic radius Ionisation energy Electronegativity

Atomic radius ½ distance between 2 nuclei of two atoms of the same element that are joined together by a single covalent bond. It is possible for scientists to measure experimentally the distance between the nuclei of 2 atoms. This is known as bond length and is measured using x-ray diffraction. Usually in nanometres. See table …. On page …. Of your maths tables

What do we notice?

What do you notice?

The values of atomic radii decrease going across a period. Why? Increase in effective nuclear charge. Increase in no. of protons in nucleus. These extra protons attract the outer electrons to draw energy levels closer to nucleus. No increase in screening effect. The addition of an electron going across a period is not added to a new energy level each time. There is an increase in the effective nuclear charge.

The values of atomic radii increase going down a group. Why? Must give 2 reasons As we go down a group there is a new energy level which is further from the nucleus. Screening effect. Even though nuclear charge increases this is counteracted by the shielding effect of the inner energy levels of electrons.

Trends in Ionisation energy 1 st ionisation of an atom is minimum energy required to remove the most loosely bound electron from a neutral gaseous atom in its ground state.

1 st Ionisation energy decreases going down a group why? Increase in atomic radius Screening effect of inner electrons.

Ionisation energy increase going across a period. Why? decreasing atomic radius Increase in nuclear charge

Exceptions

Plot a Graph of 1 st ionisation (y-axis against atomic no. (x-axis) for elements in period 2. Identify exceptions to thus trend.

Exceptions Be > B 1s 2, 2s 2 Beryllium has a full 2s sublevel. This gives an atom of Be extra stability so more energy than expected is needed to remove it’s most loosely bound electron N > O 1s 2, 2s 2,2p 3 Nitrogen has a half full 2p sublevel. This gives an atom of N extra stability so more energy than expected is needed to remove it’s most loosely bound electron

Can you explain Mg > AlP > S

Trends in electronegativity Is relative force of attraction that an atom has for the shared pair of electrons in a covalent bond Going across a period Electronegativity increase Due to increase in nuclear charge Decreasing atomic radius Going down a group Electronegativity decreases Increased atomic radius Screening effect

Electonegativity

Second ionisation E required to remove an electron from an ion with one positive charge in a gaseous state X + (g) X + (g) + e - Make sure to include (g) symbol as def states in gaseous state

Second ionisation E Potassium =1s 2, 2s 2,2p 6, 3s 2, 3p 6,4s 1 2 nd ionisation E is much higher than 1 st ionisation E as it involves removing an electron from a full 3p sublevel. The large difference in 1 st and 2 nd ionisation gives use evidence for existence of energy levels as the electron being removed from the 3p is closer to nucleus and experiences less shielding.

There is a steady increase in ionisation energy values as electrons are removed from an atom. Reason 1 For every electron that is removed the nuclear charge is increasing. Reason 2 Large increase in IE when an electron is being removed from a new energy level.

Classic mistakes noted when correcting questions on this topic. Not learning ionisation energy def. accurately. Not labelling axes on graphs Mixing energy levels/sub levels and orbitals Emphasize in your answer that a ½ filled or full filled sublevel makes an atom more stable. Bohr diagrams being used instead of Dot and cross diagrams. Use specific language like going across table effective nuclear charge increase and atomic radius decreases. Don’t waffle!