Permutations and Combinations With Beanie Babies.

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Presentation transcript:

Permutations and Combinations With Beanie Babies

If Mr. Chandler has 3 Beanie Baby Bears, How many ways can he arrange them? 1 st 2 nd 3 rd 3 X 2 x 1 = 6 arrangements

If JD has 13 Beanie Babies, how many ways can he arrange them? 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 13! or 6,227,020,800 arrangements 13! Is read as “13 factorial” and is on many calculators under the MATH: PRB menu.

If JD has 13 Beanie Babies, how many ways can he arrange 5 of them? 1 st 2 nd 3 rd 4 th 5 th 13 x 12 x 11 x 10 x 9 = 154,440 permutations

If JD has 13 Beanie Babies, how many collections of 5 can he make? 1 st 2 nd 3 rd 4 th 5 th 13 x 12 x 11 x 10 x 9 There are 154,440 permutations There are 5 x 4 x 3 x 2 x 1 = 120 ways to arrange each set of 5 There are 154,440 120 = 1,287 sets of 5 beanie babies.

If JD has 13 Beanie Babies, how many ways can he arrange them? = 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 The formula for Permutations is: 13 x 12 x 11 x 10 x 9 = 154,440 permutations

The formula for Combinations is: 13 x 12 x 11 x 10 x 9 = 154,440 permutations If JD has 13 Beanie Babies, how many collections of 5 can he make? 5! = 120 There are 154,440 120 = 1,287 Combinations of 5 beanie babies.