Warm Up For each translation of the point (–2, 5), give the coordinates of the translated point. 1. 6 units down (–2, –1) 2. 3 units right (1, 5) For each.

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Presentation transcript:

Warm Up For each translation of the point (–2, 5), give the coordinates of the translated point. 1. 6 units down (–2, –1) 2. 3 units right (1, 5) For each function, evaluate f(–2), f(0), and f(3). 3. f(x) = x2 + 2x + 6 6; 6; 21 4. f(x) = 2x2 – 5x + 1 19; 1; 4

Unit 5: Quadratic Functions Section 4: Using Transformations to Graph Quadratic Functions

How do you graph quadratic Functions and transform them on the coordinate plane? Essential Question

Standards in this section text book pages 493-500 Build new functions from existing functions MCC9-12.F.BF.3Identify the effect on the graph of replacing f(x) byf(x) + k, k f(x), f(kx), and f(x + k) for specific values of k (both positive and negative); find the value of k given the graphs. Experiment with cases and illustrate an explanation of the effects on the graph using technology. Include recognizing even and odd functions from their graphs and algebraic expressions for them. MCC9-12.A.CED.4 Rearrange formulas to highlight a quantity of interest, using the same reasoning as in solving equations. MCC9-12.F.IF.7a Graph quadratic functions and show intercepts, maxima, and minima. MCC9-12.F.IF.5 Relate the domain of a function to its graph and, where applicable, to the quantitative relationship it describes.★ (Focus on quadratic functions; compare with linear and exponential functions studied in Coordinate Algebra.) MCC9-12.F.BF.1Writea function that describes a relationship between two quantities.★(Focus on quadratic functions; compare with linear and exponential functions studied in Coordinate Algebra.)

Vocabulary Quadratic Equation: An equation of degree 2, which has at most two solutions. Quadratic Function: A function of degree 2 which has a graph that “turns around” once, resembling an umbrella-like curve that faces either rightside up or upside down. This graph is called a parabola. Parabola- a U shaped curve Vertex of a parabola- The lowest or highest point of a graph Standard Form of a Quadratic Function: ax2+bx +c vertex form of a quadratic function is f(x) = a(x – h)2 + k, where a, h, and k are constants. The vertex is (h,k)

A quadratic function is a function that can be written in the form of f(x) = a (x – h)2 + k (a ≠ 0). In a quadratic function, the variable is always squared. The table shows the linear and quadratic parent functions.

Notice that the graph of the parent function f(x) = x2 is a U-shaped curve called a parabola. As with other functions, you can graph a quadratic function by plotting points with coordinates that make the equation true.

Example 1: Graphing Quadratic Functions Using a Table Graph f(x) = x2 – 4x + 3 by using a table. Make a table. Plot enough ordered pairs to see both sides of the curve. x f(x)= x2 – 4x + 3 (x, f(x)) f(0)= (0)2 – 4(0) + 3 (0, 3) 1 f(1)= (1)2 – 4(1) + 3 (1, 0) 2 f(2)= (2)2 – 4(2) + 3 (2,–1) 3 f(3)= (3)2 – 4(3) + 3 (3, 0) 4 f(4)= (4)2 – 4(4) + 3 (4, 3)

Example 1 Continued f(x) = x2 – 4x + 3 • • • • •

Check It Out! Example 1 Graph g(x) = –x2 + 6x – 8 by using a table. Make a table. Plot enough ordered pairs to see both sides of the curve. x g(x)= –x2 +6x –8 (x, g(x)) –1 g(–1)= –(–1)2 + 6(–1) – 8 (–1,–15) 1 g(1)= –(1)2 + 6(1) – 8 (1, –3) 3 g(3)= –(3)2 + 6(3) – 8 (3, 1) 5 g(5)= –(5)2 + 6(5) – 8 (5, –3) 7 g(7)= –(7)2 + 6(7) – 8 (7, –15)

Check It Out! Example 1 Continued f(x) = –x2 + 6x – 8 • • • • •

You can also graph quadratic functions by applying transformations to the parent function f(x) = x2. Transforming quadratic functions is similar to transforming linear functions (Lesson 2-6).

Example 2A: Translating Quadratic Functions Use the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. g(x) = (x – 2)2 + 4 Identify h and k. g(x) = (x – 2)2 + 4 h k Because h = 2, the graph is translated 2 units right. Because k = 4, the graph is translated 4 units up. Therefore, g is f translated 2 units right and 4 units up.

Example 2B: Translating Quadratic Functions Use the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. g(x) = (x + 2)2 – 3 Identify h and k. g(x) = (x – (–2))2 + (–3) h k Because h = –2, the graph is translated 2 units left. Because k = –3, the graph is translated 3 units down. Therefore, g is f translated 2 units left and 4 units down.

Check It Out! Example 2a Using the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. g(x) = x2 – 5 Identify h and k. g(x) = x2 – 5 k Because h = 0, the graph is not translated horizontally. Because k = –5, the graph is translated 5 units down. Therefore, g is f is translated 5 units down.

Check It Out! Example 2b Use the graph of f(x) =x2 as a guide, describe the transformations and then graph each function. g(x) = (x + 3)2 – 2 Identify h and k. g(x) = (x – (–3)) 2 + (–2) h k Because h = –3, the graph is translated 3 units left. Because k = –2, the graph is translated 2 units down. Therefore, g is f translated 3 units left and 2 units down.

Recall that functions can also be reflected, stretched, or compressed.

Example 3A: Reflecting, Stretching, and Compressing Quadratic Functions Using the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. 1 ( ) g x =- x 2 4 Because a is negative, g is a reflection of f across the x-axis. Because |a| = , g is a vertical compression of f by a factor of .

Example 3B: Reflecting, Stretching, and Compressing Quadratic Functions Using the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. g(x) =(3x)2 Because b = , g is a horizontal compression of f by a factor of .

Check It Out! Example 3a Using the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. g(x) =(2x)2 Because b = , g is a horizontal compression of f by a factor of .

Check It Out! Example 3b Using the graph of f(x) = x2 as a guide, describe the transformations and then graph each function. g(x) = – x2 Because a is negative, g is a reflection of f across the x-axis. Because |a| = , g is a vertical compression of f by a factor of .

If a parabola opens upward, it has a lowest point If a parabola opens upward, it has a lowest point. If a parabola opens downward, it has a highest point. This lowest or highest point is the vertex of the parabola. The parent function f(x) = x2 has its vertex at the origin. You can identify the vertex of other quadratic functions by analyzing the function in vertex form. The vertex form of a quadratic function is f(x) = a(x – h)2 + k, where a, h, and k are constants.

Because the vertex is translated h horizontal units and k vertical from the origin, the vertex of the parabola is at (h, k). When the quadratic parent function f(x) = x2 is written in vertex form, y = a(x – h)2 + k, a = 1, h = 0, and k = 0. Helpful Hint

Example 4: Writing Transformed Quadratic Functions Use the description to write the quadratic function in vertex form. The parent function f(x) = x2 is vertically stretched by a factor of and then translated 2 units left and 5 units down to create g. Step 1 Identify how each transformation affects the constant in vertex form. Vertical stretch by : 4 3 a = Translation 2 units left: h = –2 Translation 5 units down: k = –5

Example 4: Writing Transformed Quadratic Functions Step 2 Write the transformed function. g(x) = a(x – h)2 + k Vertex form of a quadratic function = (x – (–2))2 + (–5) Substitute for a, –2 for h, and –5 for k. = (x + 2)2 – 5 Simplify. g(x) = (x + 2)2 – 5

Check It Out! Example 4a Use the description to write the quadratic function in vertex form. The parent function f(x) = x2 is vertically compressed by a factor of and then translated 2 units right and 4 units down to create g. Step 1 Identify how each transformation affects the constant in vertex form. Vertical compression by : a = Translation 2 units right: h = 2 Translation 4 units down: k = –4

Check It Out! Example 4a Continued Step 2 Write the transformed function. g(x) = a(x – h)2 + k Vertex form of a quadratic function = (x – 2)2 + (–4) Substitute for a, 2 for h, and –4 for k. = (x – 2)2 – 4 Simplify. g(x) = (x – 2)2 – 4

Check It Out! Example 4b Use the description to write the quadratic function in vertex form. The parent function f(x) = x2 is reflected across the x-axis and translated 5 units left and 1 unit up to create g. Step 1 Identify how each transformation affects the constant in vertex form. Reflected across the x-axis: a is negative Translation 5 units left: h = –5 Translation 1 unit up: k = 1

Check It Out! Example 4b Continued Step 2 Write the transformed function. g(x) = a(x – h)2 + k Vertex form of a quadratic function = –(x –(–5)2 + (1) Substitute –1 for a, –5 for h, and 1 for k. = –(x +5)2 + 1 Simplify. g(x) = –(x +5)2 + 1

Homework: Text book: (exercises 15-1) P 498 # 1-15 Worksheet: Transforming Quadratics worksheet Transforming Quadratics Multiple Choice