Anna Chang 10-1 / T2
Perpendicular bisector is a line that cuts a segment into two equal parts, it creates 90 degrees.
Here’s a segment AB N is the perpendicular bisector of segment AB b/c n is the perpendicular bisector, then it creates a 90 degree angle
A B 90 degrees n is the perpendicular bisector of the segmen AB
ㄱ 90 degrees n is the perpendicular bisector of the segmen AB
90 degrees n is the perpendicular bisector of XY
90 degrees Q is the perpendicular bisector of OP
If a point lies on the perpendicular bisector of a segment then it is equidistant from both of the endpoints of the segment. XA=XB
Example 1 : AB and CB 1.AB=CB 2.5z+23=6z =1z 4.Z=9 5.5(9)+23 AB=68 6.6(9)+14 CB=68
Find X X=24 Since l is perpendicular bisector of TU, W is the midpoint of TU. <TWV and <WUV are right angles by def. of perpendicular. Later WV=VW by reflexive property. VT=VU by CPCT So X=24
AA point lies on the perpendicular bisector of a segment if and only if is equidistant from both of the sides