QUESTION #1 GIVEN: m<1 = m<2 m<2 = 35 CONCLUSION: m<1 = 35 REASON: Transitive Property.

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Presentation transcript:

QUESTION #1 GIVEN: m<1 = m<2 m<2 = 35 CONCLUSION: m<1 = 35 REASON: Transitive Property

QUESTION #2 GIVEN: EG = FG FG = GH CONCLUSION: EG = GH REASON: Transitive Property

QUESTION #3 GIVEN: X + 9 = 15 CONCLUSION: x = 6 REASON: Subtraction Property

QUESTION #4 GIVEN: JK = KL MN = KL CONCLUSION: JK = MN REASON: Transitive Property

QUESTION #5 GIVEN: 7x = 35 CONCLUSION: x = 5 REASON: Division Property

QUESTION #6 GIVEN: m<3 = 75 m<4 = 75 CONCLUSION: m<3 + m<4 = 150 REASON: Addition Property

QUESTION #7 GIVEN: <1 = <2 <2 = <3 CONCLUSION: <1 = <3 REASON: Transitive Property

QUESTION #8 GIVEN: XY is a segment CONCLUSION: XY = XY REASON: Reflexive Property

QUESTION #9 GIVEN: 3x + y = 60 2x = y CONCLUSION: 3x + 2x = 60 REASON: Substitution Property

QUESTION #10 GIVEN: <A = <B CONCLUSION: <B = <A REASON: Symmetric Property

GIVEN:16y + 8 = 13 – 24y PROVE: y = 1/5 Statement Reason 16y + 8 = 13 –24y 40y + 8 = 13 40y = 5 y = 1/5 Given Addition Prop. Subtraction Prop. Division Prop.

GIVEN: <1 + <2 = 120 <1 = 100 PROVE: m<2 = 20 Statement Reason m<1 + m<2 = 120 m<1 = 100 100 + m<2 = 120 m<2 = 20 Given Substitution Subtraction Prop.

GIVEN: m<1 = 60; m<2 = 60. m<1 + m<3 = 120 GIVEN: m<1 = 60; m<2 = 60 m<1 + m<3 = 120 m<4 + m<2 = 120 PROVE: m<3 = m<4 Statement Reason m<1 + m<3 = 120 m<1 = 60 m<3 = 60 m<4 + m<2 = 120 m<2 = 60 m<4 = 60 m<3 = m<4 Given Subtraction Prop. Transitive Prop.

GIVEN: m<1 + m<2 = 180 m<2 + m<3 = 180 PROVE: m<2 = m<3 Statement Reason m<1 +m<2 =180 m<2 + m<3 = 180 m<1 + m<2 = m<2 + m<3 m<2 = m<2 m<1 = m<3 Given Transitive Prop. Reflexive Prop. Subtraction Prop.

GIVEN: X lies between A and B; AX = 5; XB = 3 PROVE: AB = 8 STATEMENTS X lies between A and B. AX + XB = AB AX = 5; XB = 3 5 + 3 = AB 8 = AB AB = 8 REASONS Given Segment Addition Post. Substitution Property Symmetric Property

GIVEN: S lies between points R and T PROVE: ST = RT - RS STATEMENTS S lies between R and T. RS + ST = RT ST = RT - RS REASONS Given Segment Addition Postulate Subtraction Property of Equality

GIVEN: m<AOC = m<BOD PROVE: m<1 = m<3 STATEMENTS m< AOC = m<BOD m<AOC = m<1 + m<2; m<BOD = m<2 + m<3 m<1 + m<2 = m<2 + m<3 m<2 = m<2 m<1 = m<3 REASONS Given Angle Addition Postulate Substitution Property Reflexive Property Subtraction Property

GIVEN: Ray XS bisects <RXT; m<RXS = j PROVE: m<RXT = 2j STATEMENTS XS bisects <RXT. <RXS ≅ <SXT m<RXS = m<SXT m<RXS = j m<SXT = j m<RXT = m<RXS + m<SXT m<RXT = j + j or 2j REASONS Given Def. of < bisector Def. of ≅ <‘s Substitution Property Angle Addition Thm.

GIVEN: B lies between A and C;. C lies between B and D; GIVEN: B lies between A and C; C lies between B and D; AC = BD PROVE: AB = CD STATEMENTS B lies between A and C. AB + BC = AC C lies between B and D. BC + CD = BD AC = BD AB + BC = BC + CD AB = CD REASONS Given Segment Addition Post. Substitution Property Subtraction Property

GIVEN: <2 ≅ <3 PROVE: <1 ≅ <4 STATEMENTS <1 ≅ <2 <2 ≅ <3 <3 ≅ < 4 <1 ≅ < 4 REASONS Vertical <‘s are ≅. Given Vertical <‘s are ≅ Transitive Property (used twice).

GIVEN: Ray BX is the bisector of <ABC PROVE: m<ABX = ½m<ABC; GIVEN: Ray BX is the bisector of <ABC PROVE: m<ABX = ½m<ABC; m<XBC = ½m<ABC STATEMENTS BX is the bisector of <ABC. <ABX ≅ <XBC m<ABX + m<XBC = m<ABC 2m<ABX = m<ABC m<ABX = ½m<ABC m<XBC = ½m<ABC REASONS Given Def. of a bisector Angle Addition Postulate Substitution Property Division Property