1 WLTP Open Issue Phase 1B Issue: Generic formula for hydrocarbon density. JAPAN Informal Document 27.05.2014 WLTP-07-12e.

Slides:



Advertisements
Similar presentations
1 WLTP Open Issue Phase 1B Issue: Generic formula for hydrocarbon density. ACEA Informal Document WLTP rev1e.
Advertisements

Molecular Compostion of Gases
Moles, volume and density
1 WLTP Open Issue Phase 1B Issue: Generic formula for total hydrocarbon density. ACEA Informal Document WLTP-07-11e.
1 WLTP Open Issue Phase 1B Issue: Definition of NMHC & THC density. ACEA Informal Document WLTP-06-18e.
Using the Ideal Gas Law and Previously Learned Concepts
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
Chemistry Notes Empirical & Molecular Formulas. Empirical Formula The empirical formula gives you the lowest, whole number ratio of elements in the compound.
1 WLTP Open Issue Phase 1B Issue: Amendment of OIL#42 - Willans factors for petrol (E10) & diesel (B7). ACEA Informal Document WLTP rev1e.
1 WLTP Open Issue Phase 1B Issue: Fuel Consumption calculations for ICE vehicles. ACEA Informal Document WLTP-08-07e.
Chapter 2Stoichiometry Stoichiometry: the science dealing with quantitative relationships involving the mass of substances and the number of particles.
Molecular Formulas 1.Find empirical formula 2.Calculate molar mass of empirical formula 3.Molar mass of compound / molar mass of empirical formula (we’ll.
Chemical Quantities.  Calculate the mass of compounds.  Calculate the molar volumes of gases.  Solve problems requiring conversions between mass, and.
Chapter 3 Percent Compositions and Empirical Formulas
Applications of the Mole Concept Percent Composition Empirical Formula The makeup of a compound by mass.
Mole-Mass and Mole-Volume Relationships
PERCENT COMPOSITION. 2 3 Steps for Determining Chemical Formulas 1. Determine the percent composition of all elements. 2. Convert this information into.
The Mole: A Measurement of Matter
Chapter 10: Chemical Quantities
The Mole: A measurement of Matter
Combustion Analysis Topic #13
The Mole 1 dozen = 12 1 gross = ream = mole = 6.02 x 1023.
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
INTERNAL COMBUSTION ENGINES LECTURER PROF.Dr. DEMIR BAYKA.
Solving Limiting Reactant Problems. Background In limiting reactant problems, we have the amounts (masses or mols) of two of the reactants. The problem.
Percent Composition Empirical & Molecular Formulas.
Unit 6: Chemical Quantities
Combustion Analysis Ex - Find the empirical formula of vitamin C (ascorbic acid), a compound that contains only C, H, and O. Combustion of g of.
THE MOLE Chapter 10: Chemical Quantities Measuring Matter What is a mole? It is the SI unit that measures the amount of substance.
Empirical and Molecular Formulas. Caffeine is 49.48% C, 5.15% H, 28.87% N and 16.49% O. What is its empirical formula? Empirical Mass=
Percent Composition and Chemical Formulas
AEGPL amendments proposals to Regulations n. 83 and 115 Bi-fuel vehicles – New definition and provisions GFV - Brussels, 15 th December 2011.
% Composition, Empirical Formulas, & Molecular Formulas.
Relative Formula Mass expressed in grams
Stoichiometry and the mole Chapter 8 What is stoichiometry?  Quantitative aspects of chemistry  Stoicheon Greek root (element)  Metron Greek root(
Math in Chemistry. Percent Composition Purpose: Can be used to figure out chemical formulas.
Unit 5 Review The Mole. 1. What is the mass of 1 mole of iron atoms? A amu B L C x D g.
Calculating Empirical and Molecular Formulas. Calculating empirical formula A compound contains 79.80% carbon and 20.20% hydrogen. What is the empirical.
USING MOLAR CONVERSIONS TO DETERMINE EMPIRICAL AND MOLECULAR FORMULAS.
Molecular Formulas. An empirical formula shows the lowest whole-number ratio of the elements in a compound, but may not be the actual formula for the.
Honors Chemistry, Chapter 11 Page 1 Chapter 11 – Molecular Composition of Gases.
Section 6.2 Molar Mass and Percent Composition 1.To understand the definition of molar mass 2.To learn to convert between moles and mass 3.To learn to.
Calculating Empirical Formulas
Determining Empirical Formula from Combustion Analysis 1.
Chapter 7 Moles. What is a Representative Particle The smallest unit into which a substance can be broken down without changing the composition of the.
WHITEBOARD PRACTICE TEST REVIEW. How many molecules of ethane, C 2 H 6 are present in g C 2 H 6 ?
Percent Composition, Empirical and Molecular Formulas.
Chemical Quantities Chapter 10. The Mole  a mole is an amount of matter  mass is also an amount of matter, however the mole is much more useful to chemists,
Chemical Quantities Chapter 10.
Chemistry 200 Fundamentals D Chemical Composition.
Determine the empirical formula of the compound containing:
Chemistry 100 Chapter 6 Chemical Composition.
Gas fuelled vehicles in GTR 15: Bringing WLTP in line with Reg. 83:
IMMA proposal for GTR2 B2 on NMHC and CFV
Intermediate 2 Chemistry Unit 2(a)
Positions on open points WLTP DTP subgroup LabProcICE
% Formula Mass and % Composition
7.5 – NOTES Molecular Formulas
Combustion Analysis The composition of a substance is often determined by using a specified reaction to break down the substance into known measurable.
Empirical and Molecular Formulas
Empirical Formulas Unit 5.
Chapter 10: Chemical Quantities
Empirical Formulas  What do all of these formulas have in common? CH C2H2C2H2 C3H3C3H3 C4H4C4H4  Empirical Formula-Reduced version of the molecular formula.
Molecular Formula number and type of atoms covalent compounds
Percentage Composition
Calculating Empirical and Molecular Formulas
Empirical and Molecular Formulas
7.3 – NOTES Molecular Formulas
Calculating Empirical and Molecular Formulas
Molecular Formula Acetic Acid Glucose Formaldehyde.
Presentation transcript:

1 WLTP Open Issue Phase 1B Issue: Generic formula for hydrocarbon density. JAPAN Informal Document WLTP-07-12e

2 Counter-Proposal by It would be better to have generic formula for all fuel dependent coefficients (HC densities, dilution factors, fuel consumption, Willans factors), however, it is acceptable to add generic formula for HC densities with clarification of its usage to avoid unnecessary confusion. 1. Add specific densities for E10 and B7 into section of Annex 7 (same as EU registration) 2. Add section of Annex 7 with slight modification. 3. Modify section and of Annex 7 3. Need experts input for Willans factors for E10 and B7 (Annex6/Appendix2) 4. In case of new reference fuel, the following sections need to be amended (1) Annex6/Appendix2 (2) Annex7 Section , and 6 EU registrationGeneric formula for petrol (E10) ρ=0.645 g/ for diesel (B5) ρ=0.622 g/ for diesel (B7) ρ=0.623 g/

The mass M of gaseous compounds emitted by the vehicle during the test shall be determined by obtaining the product of the volumetric concentration of the gas in question and the volume of the diluted exhaust gas with due regard for the following densities under the reference conditions of K and kPa: Carbon monoxide (CO) ρ=1.25g/l Carbon dioxide (CO2) ρ=1.964 g/l Hydrocarbons: for petrol (E0) (C1H1.85) ρ=0.619 g/1 for petrol (E5) (C1H1.89O0.016) ρ=0.631 g/1 for petrol (E10) (C1H1.93O0.033) ρ=0.645 g/1 for diesel (B0) (C1Hl.86) ρ=0.619 g/1 for diesel (B5) (C1Hl.86O0.005) ρ=0.622 g/1 for diesel (B7) (C1Hl.86O0.007) ρ=0.623 g/1 g/1 for LPG (C1H2.525) ρ=0.649 g/l for NG/biomethane (CH4) ρ=0.714 g/l for ethanol (E85) (C1H2,74O0.385) ρ=0.932 g/l Nitrogen oxides (NOx) ρ=2.05 g/1 Nitrogen dioxide (NO2) ρ=2.05 g/1 Nitrous oxide (N2O) ρ=1.964 g/1 The density for NMHC mass calculations shall be equal to that of total hydrocarbons at K and kPa and is fuel-dependent In case the specific density is not available in section , general equation for the hydrocarbons densities (ρ) for each reference fuel with an average composition of CxHyOz is: ρHC: density of total hydrocarbons [g/l] MWC: molecular weight of carbon = g/mol MWH: molecular weight of hydrogen = g/mol MWO: molecular weight of oxygen = g/mol VM: molar volume for an ideal gas at 0°C and kPa = l/mol H/C: ratio of hydrogen to carbon for a specific fuel CxHyOz O/C: ratio of oxygen to carbon for a specific fuel CxHyO Annex 7

The dilution factor, DF, is calculated as follows: 13.4 for petrol (E0, E5 and E10) and diesel(B0) (5a) 13.5 for diesel (B5 and B7) (5b) for LPG (5c) for NG/biomethane (5d) for ethanol (E85) (5e) In case difference fuel other than listed in section general equation for the dilution Annex 6 -Appendix 2 Add E10 and B7 but no idea for these Willans factors. Is general equation for Willans factors available ? 6. Calculation of fuel consumption Is general equation for fuel consumption calculation available ? For a vehicle with a positive ignition engine fuelled with ethanol (E85) “(0.273 *)” shall be “(0.273 * CO 2 )”