Calculating the volume of a solid Sphere, cone and pyramid.

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Presentation transcript:

Calculating the volume of a solid Sphere, cone and pyramid

Formula, rounding and units You must show -the formula you are using -The substituted values -The answer prior to rounding -Rounded final answer -the units Example: Find the area of a circle with radius 6∙2 cm to 3 significant figures. A = π × r 2 = π × 6∙2 2 = 120∙762 …. = 121 cm 2

Reminders - Formulae Area of a Square Area of a Rectangle Area of a Triangle Area of a Circle Volume of a Cube Volume of a Cuboid Volume of a prism

Reminder – Pythagoras’ Theorem h cm 4 cm 6 cm Pythagoras’ theorem states that a 2 = a b c Example: Calculate the height of this triangle with sides 4 cm and a base of 6 cm to 2 significant figures. a 2 = b 2 + c 2 b 2 = a 2 - c 2 h 2 = h = Note: Never round until you have answered the question

r Calculating the volume of a sphere Example: Calculate the volume of this football which has a diameter of 30cm D = 30cmr = V = πr 3 V = Example: Calculate the volume of a hemisphere of radius 12 cm to 3 significant figures. (A hemisphere is half a sphere) V = πr 3 ½ V =

Calculating the volume of a cone A circular based pyramid is called a Volume = x area of circle x height So Example: Calculate the volume of this cone to 2 significant figures V = πr 2 h

Calculating the volume of a pyramid Volume (pyramid) = 1/3 x area (of base) x height A x h Example: Calculate the volume of the statue, with a square base of 9 cm and a height of 12 cm. V = Ah

Calculating the volume of a solid Sphere, cone and pyramid

Formula, rounding and units You must show -the formula you are using -The substituted values -The answer prior to rounding -Rounded final answer -the units Example: Find the area of a circle with radius 6∙2 cm to 3 significant figures. A = π × r 2 = π × 6∙2 2 = 120∙762 …. = 121 cm 2

Reminders - Formulae Area of a Square A = l 2 Area of a RectangleA = l × b Area of a TriangleA = ½ × b × h Area of a CircleA = π r 2 Volume of a CubeV = l 3 Volume of a CuboidV = l × b × h Volume of a prismV = face × h

Reminder – Pythagoras’ Theorem h cm 4 cm 6 cm Pythagoras’ theorem states that a 2 = b 2 + c 2 a b c Example: Calculate the height of this triangle with sides 4 cm and a base of 6 cm to 2 significant figures. a 2 = b 2 + c 2 b 2 = a 2 - c 2 h 2 = 4 2 – 3 2 = 7 h = √7 = 2.648… = 2.6 cm Note: Never round until you have answered the question

r Calculating the volume of a sphere Example: Calculate the volume of this football which has a diameter of 30cm D = 30cmr = 15cm V = πr 3 V = x π x 15 3 = … = cm 3 Example: Calculate the volume of a hemisphere of radius 12 cm to 3 significant figures. (A hemisphere is half a sphere) V = πr 3 ½ V = ÷ 2 = π x 12 3 = … = … = 3620 cm 3 = 7240 cm 3

Calculating the volume of a cone A circular based pyramid is called a Volume = x area of circle x height So Example: Calculate the volume of this cone to 2 significant figures V = πr 2 h cone = π x 15 2 x 12 = … = 2800 cm 3

= x 9² x 12 = x 81 x 12 = 324 cm 3 Calculating the volume of a pyramid Volume (pyramid) = 1/3 x area (of base) x height A x h Example: Calculate the volume of the statue, with a square base of 9 cm and a height of 12 cm. V = Ah