pH P ractice Practice Problem # 1 © Mr. D. Scott; CHS If the hydrogen ion concentration of a solution is 2.5 x M, what is the pH of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH pH = -log [H + ] Step 2 Substitute & solve. pH = -log [H + ] pH = -log (2.5 x ) pH = Step 3 Check sig-figs & round. pH = 4.60 Level 1
pH P ractice Practice Problem # 2 © Mr. D. Scott; CHS If the hydrogen ion concentration of a solution is 3.71 x M, what is the pOH of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH pH = -log [H + ] pOH = pK w -pH Step 2 Substitute & solve. pH = -log [H + ] pH = -log (3.71 x ) pH = Step 3 Check sig-figs & round. pOH = pOH = pK w -pH pOH = 14 – pOH = sig-figs Level 1
pH P ractice Practice Problem # 3 © Mr. D. Scott; CHS If a solution has [OH - ] = 4.7 x M, what is the pH of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH pOH=-log[OH - ] pH = pK w -pOH Step 2 Substitute & solve. pOH = -log [OH - ] pOH = -log (4.7 x ) pOH = Step 3 Check sig-figs & round. pH = pH = pK w -pOH pH = 14 – pH = sig-figs Level 1
pH P ractice Practice Problem # 4 © Mr. D. Scott; CHS If a solution has a pH of 3.75, what is the [OH - ] of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH pOH = pK w -pH [OH - ]= 10 -pOH Step 2 Substitute & solve. pOH = pK w -pH pOH = pOH = Step 3 Check sig-figs & round. [OH - ] = 5.6 x M [OH - ] = 10 -pOH [OH - ] = [OH - ] = x sig-figs Level 1
pH P ractice Practice Problem # 5 © Mr. D. Scott; CHS If a solution has a pOH of 11.49, what is the [H + ] of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH [OH - ]= 10 -pOH [H + ]=K w ÷[OH - ] Step 2 Substitute & solve. [OH - ] = 10 -pOH [OH - ] = 10 –11.49 [OH - ] = x Step 3 Check sig-figs & round. [H + ] = 3.1 x M [H + ] = K w ÷[OH - ] [H + ] = ÷ x [H + ] = x sig-figs Level 1
pH P ractice Practice Problem # 6 © Mr. D. Scott; CHS If a solution has a [H + ] of 2.2 x 10 -1, what is the pOH of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH [OH - ]= K w ÷[H + ] pOH=-log[OH - ] Step 2 Substitute & solve. [OH - ] = K w ÷[H + ] [OH - ] = ÷ 2.2 x [OH - ] = x Step 3 Check sig-figs & round. pOH = pOH = -log[OH - ] pOH = -log(4.545 x ) pOH = sig-figs Level 1
pH P ractice Practice Problem # 7 © Mr. D. Scott; CHS If a solution has a [OH - ] of 8.4 x , what is the pH of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH pOH=-log[OH - ] pH = pK w -pOH Step 2 Substitute & solve. pOH = -log [OH - ] pOH =-log(8.4 x ) pOH = Step 3 Check sig-figs & round. pH = pH = pK w -pOH pH = 14 – pH = sig-figs Level 1
pH P ractice Practice Problem # 8 © Mr. D. Scott; CHS If a solution has a pOH of 14.52, what is the [H + ] of the solution? Step 1 Identify the steps to be taken to solve. [H + ] [OH - ] pH pOH pH = pK w -pOH [H + ] = 10 -pH Step 2 Substitute & solve. pH = pK w - pOH pH = 14 – pH = Step 3 Check sig-figs & round. [H + ] = 3.3 M [H + ] = 10 -pH [H + ] = 10 -(-0.52) [H + ] = 3.311M 2 sig-figs Level 1