Energy Review
The unit for kinetic energy. Joule
The quantity represented by the kilowatt hour. Answer: Electric energy
The unit for charge. Answer:Coulomb
The equation for power Answer: P=IV
In the equation for Ohm’s Law, represented by the “I” Answer: Current
The equation to solve for current which includes charge and time. Answer: I = q/t
The equation for Ohm’s Law Answer: V=IR
The rate at which energy is consumed Answer: Power
The definition of electric current. Answer: flow of electric charge
The relationship between current and resistance. Answer: direct
The quantity that slows down current in a circuit Answer:resistance
The unit for power. Answer: watt
The quantity that expresses the amount of energy in a charge Answer: voltage
The flow of positive charges in a circuit Answer: conventional current
The current through the starter motor of a car is 120 A. If the battery maintains 10 V across the motor, how much electric energy is delivered to the starter in 10 s? (Hint: calculate power first) Answer: Find power P=IV=120 A(10V)=1200 W Find EnergyE=PtE=1200 W(10s)=12,000J
In the equation for Coulomb’s Law, represented by the letter “q” Answer: charge
The type of relationship shown between current and voltage Answer:direct
The type of circuit in which one pathway exists Answer:series
The quantity that represents potential difference. Answer:voltage
A flashlight bulb is rated at 9.0 W. If the light bulb drops 3.0 V, how much current goes through it? Answer:P=IV 9.0W = I(3.0V) I=3 A
A drawing of a circuit using symbols Answer: schematic
The outcome of adding resistors in a circuit when voltage does not change. Answer: decrease in current
The letter that represents resistance in Ohm’s Law. Answer: R
The symbol that represents a battery in a circuit Answer:
The type of circuit in which total resistance is greater than a single resistor Answer: series
The total voltage drop across each resistor in a parallel circuit is ____ the total voltage in the circuit. Answer: equal to
The unit for resistance. Answer: ohms
The current through a light bulb connected across the terminals of a 125 V outlet is 0.5 A. How much power is supplied to the bulb? Answer: » P=IV » P=(0.5A)(125V) » P=62.5 W
The connection required for a voltmeter. Answer: Parallel
A lamp uses 6.0 V and 12 W when it is operating. What is the current through the lamp? Answer: P=IV 12W=I(6.0V) I=2A
A 15 ohm and a 5 ohm resistor are connected in series. What is the equivalent resistance? Answer: 20 ohms
The behavior of current in a parallel circuit. Answer: Adds up to total
A device for measuring current. Answer: ammeter
Draw a parallel circuit with three lamps in parallel, and a battery.
Three types of energy which electric energy can be converted to Answer: sound, light, heat
A device for measuring voltage. Answer: voltmeter
Type of circuit in which current is the same through each branch. Answer: series
The type of connection used for an ammeter Answer: series
An outlet that prevents injuries that are caused when an electric appliance falls into water. It contains an electric circuit that detects an extra current path and opens the circuit. Answer: ground fault interrupter
The symbol for a resistor in a circuit. Answer: Ώ
An automatic switch that opens when the current reaches a value greater than the rated value in the circuit. Answer: circuit breaker
A mobile source of electric power Answer: battery
The man who created the first battery to produce a lasting current Answer: Volta
Type of circuit in which voltage is the same through each branch. Answer: parallel
The current that passes through a 6 ohm resistor and uses 12 V. Answer: V=IR » 12V=I (6.0 ohms) » I=2A
Draw a series circuit with one lamp, battery and ammeter.
The purpose of a resistor in a circuit. Answer: decrease current
The flow of electric charge Answer: current
One way in which current can be increased in a circuit. Answer: increase voltage or decrease resistance