© T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter.

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© T Madas

6 m 8 m Finding the hypotenuse x = x2= x = x2= x2 100 = x2= x2 = x= x = x= x 10 x = m 13 m Finding one of the shorter sides x x2+ x2 = x 2 = 169 x2x2 = 25 x x = 5 – 144 x2x2

© T Madas 10 m 12 m Finding the hypotenuse x = x2= x = x2= x2 244 = x2= x2 = x= x = x= x x ≈ m 15 m Finding one of the shorter sides x x2+ x2 = x 2 = 225 x2x2 = 104 x x ≈ – 121 x2x2

© T Madas 5 cm 12 cm x a Find x Double application Pythagoras theorem

© T Madas 5 m x Find the perimeter of this triangle 20 m 13 m Two applications of Pythagoras Theorem to find x h The perimeter of this triangle is 54 m

© T Madas

Calculate the hypotenuse of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate. all measurements in cm

© T Madas Calculate the hypotenuse of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate. all measurements in cm

© T Madas Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate. all measurements in cm

© T Madas Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate. all measurements in cm

© T Madas Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate. all measurements in cm

© T Madas Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate. all measurements in cm

© T Madas