Basics of Imaging systems Lecture 3 prepared by Rick Lathrop 9/99 revised 9/06

Learning objectives RSS concepts: –Basic components/mechanics of image framing vs. scanning systems –Concept of focal length –Variables affecting image exposure –Image scale and ground coverage and their relationship with flying height and focal length Math concepts: –Scale equation(s) as fundamental to all of geomatics –Basic application of trigonometry

Framing systems Instantaneously acquire an image Film Camera - uses a lens to form an image at the focal plane. A shutter opens at selected intervals to allow light to enter, where the image is recorded on photographic film or an array of detectors Digital Camera - type of camera that records an image on an array of photosensitive electronically charged detectors that is recorded on magnetic disk

Components of a framing camera Lens - function is to gather light directed from the ground scene and bring it into focus at the focal plane Focal length - the linear distance from the center of the lens to the focal plane Shutter speed - various times of exposure Diaphragm - controls the amount of light transmitted to the film when the shutter is open

Components of a framing camera Graphic from

Single-lens reflex camera Text and graphics from This cross-section (side-view) of the optical components of an SLR shows how the light passes through the lens (1), is reflected by the mirror (2) and is projected on the matte focusing screen (5). Via a condensing lens (6) and internal reflections in the pentaprism (7) the image appears in the eye piece (8). When an image is taken, the mirror moves in the direction of the arrow, the focal plane shutter (3) opens, and the image is projected in the film (4) in exactly the same manner as on the focusing screenfilm

Focal length oi Graphic from

1/f = 1/o + 1/i Where f = focal length o = object distance = object to lens i = image distance = lens to focal plane f is constant, as object distance changes the image distance must change. In aerial photos, o is large, 1/o goes to zero, so i must equal f

Mapping or metric camera Single lens frame camera High geometric quality Film format is 230 mm (~9 in) on a side Focal length of 152 mm common Fiducial marks for later registration and defining principal point of the photo Keystone’s Wild RC-10 mapping camera B&W NAPP photo

Large Format Camera (LFC) Large Format Camera (LFC) flown in Space Shuttle has f = 305 mm and film size of 230x460 mm which resulted in a typical ground dimensions of 225 x 450 km (140 x 280 mi) Photos: NASA

Digital Framing/Scanning Systems Charge coupled device (CCD): electronic sensor sensitive to a particular wavelength of light, that are generally physically separate on the focal plane RGB color image generally has separate RGB CCDs There can be difficulty in spatial co-registering of the different wavebands for the same pixel

Digital Mapping Camera: Zeiss/Intergraph Imaging 2d CCD matrix (array) to ensure a rigid image geometry similar to a traditional precision film platen Panchromatic 7000 x 4000 pixels Color 3000 x 2000 pixels Separate lens for each band Multiple smaller camera heads to create image rather than a single, large diameter 12 bit radiometric resolution

Digital Line Sensing Systems: Leica Airborne Digital Sensor (ADS40) Pushbroom linear array system rather than a 2D framing system 3 line scanners : forwards, downwards and backwards to provide for stereoscopic coverage Three CCD sensors: B&W color (RGB) & NIR 12,000 pixels across RGB co-registration through special trichroid filter that splits beam from single lens, rather than 3 different lens Field of View of 64 o Produces up to 100GB of data per hour of flight

Compact Airborne Spectrographic Imager (CASI) Hyperspectral: 288 channels between  m ; each channel  m wide Spatial resolution depends on flying height of aircraft For more info: CASI 550

Most aerial photo mapping missions require overlapped coverage of successive aerial photos along a flight line

Pushbroom Scanning vs. 2D Framing Graphics from

Film Exposure Graphics from OverexposedUnderexposed

Image Exposure Exposure, E = s * d 2 * t / 4 f 2 where E = image exposure, J mm -2 s = scene brightness, J mm -2 sec -1 d = diameter of lens opening, mm t = exposure time, sec f = focal length of lens, mm

Photo exposure example Case 1Case 2 f = 40 mmif d = 10 mm d = 5 mmt = ? t = 1/125 s E 1 = s 1 (d 1 ) 2 t 1 = s 2 (d 2 ) 2 t 2 = E 2 4(f 1 ) 2 4(f 2 ) 2

Image exposure example Case 1Case 2 f = 40 mmif d = 10 mm d = 5 mmt = ? t = 1/125 s E 1 = s 1* (5) 2* 1/125sec = s 2* (10) 2* t 2 = E 2 4(40) 2 4(40) 2 t 2 = (5) 2 * 1/125sec = 25/125 sec = 1 / 500 sec (10) 2 100

F/STOP F/STOP = relative aperture or lens opening F/STOP = f/d = lens focal length/ lens opening diameter F/STOP increases, d decreases, E decreases must change F/STOP and exp. time, t, together. As F/STOP increases, t increases E = s * t / 4 F 2

F/STOP example Case 1Case 2 F/8 if F/STOP = F/4 t = 1/125 s t = ? E 1 = s 1 t 1 = s 2 t 2 = E 2 4(F 1 ) 2 4(F 2 ) 2

F/STOP example Case 1Case 2 F/8 if F/STOP = F/4 t = 1/125 s t = ? E 1 = 1/125s = t 2 = E 2 4(8) 2 4(4) 2 t 2 = 1/125s * (4) 2 = 16/125 sec = 1/500 sec (8) 2 64

F/STOP Each F/STOP changes the amount of light E by a factor of 2 F/STOPShutter Speed 22all equal1/4 2x exp 162x exp1/30 at F/81/8 111/60 at F/5.61/15 81/125 at F/41/30 5.6another example1/60 41/125 at F/81/ /250 at F/5.61/250 21/500 at F/41/ /1000

F/STOP Interrelationships Double the focal length, quadruple the time 1/4 the time, double the diameter or 1/2 F/STOP double the f, double the diameter

Lens speed The larger the lens diameter at full aperture, the more light the lens will admit in a given time interval lens speed = F/STOP at full aperture the smaller the F/STOP, the faster the lens F/2 has double the aperture diameter as F/4 fast speed lenses are needed for low light conditions

Example: F/Stop effect on depth of field F/22 F/8 F/4 F/STOP increases, Depth of Field increases The range of distance over which objects are in focus

Remote Sensing Platforms Geostationary Polar orbit manned space High altitude aircraft (U-2) Jets low alt. aircraft Platforms In-situ/ground 36,000km 900 km km 90,000 ft 10-30,000 ft ,000 ft ft 0-5 ft

Image Scale Scale = f /H’ = d/D where f = focal length H’ = height above terrain d = image distance D = ground distance h = terrain elevation H = flying height (h + H’) H’ f D d h H

Example: Image Scale vs. flying height example Scale = 1 /RF d = f /H’ = d/D where f = 152 mm D = 5000m d = 230mm H’ = ? H’ = f x D= 152mm x 5000m = 3304 m = 3300m d230 mm If I want a ground coverage of 5km, what flying height should I use?

Example: Image Scale vs. flying height example Scale = 1 /RF d = 1/50,000 = f /H’ where f = 152 mm H’ = ? H’ = f x RF d = 152mm x 50,000 = 7600m 1 1 If I want a scale of 1/50,000, what flying height should I use?

Effect of flying height on ground coverage x Adapted from Lillesand & Kiefer, 2 nd edition H’ 1 H’ 2 H’ 1 > H’ 2 D 1 > D 2 D2D2 D1D1

Effect of focal length on ground coverage x Adapted from Lillesand & Kiefer, 2 nd edition H’ 1 f 1 > f 2 D 1 < D 2 f1f1 f2 D1D1 D2D2

Ground Coverage Ground coverage, D, of photo frame varies with f and H’ as f decreases, ground coverage increases e.g. f 1 = 1/2 f 2 D 1 = 2D 2 A 1 = 4A 2 as H’ increases, ground coverage increases e.g. H’ 2 = 2H’ 1 D 2 = 2D 1 A 2 = 4A 1

Ground Coverage example

National High Altitude program (NHAP) Flying Height, H’ = 12,200 m color IR camera f = 210 mm scale 1:58,000 area per frame 13.3 x 13.3 km panchromatic camera f = 152 mm scale 1:80,000 area per frame 18.4 x 18.4 km

Ground Coverage for Scanning Systems W = 2 H’ tan  where W = swath width H’ = flying height above terrain  = one half total field of view of scanner  H’ W Hint: remember your trigonometry Tangent of a right angle  opposite adjacent Opposite = tan  * adjacent opp adj 

Ground Coverage for Scanning Systems W = 2 H’ tan  Example: Leica ADS40  = 64 o if H’ = 2880 m W = 2 * 2880m * tan32 o = 3600m  H’ W

Extra Puzzler The Quickbird satellite is flown at an altitude of 450 km, with a total angular field of view of 2.12 o. What is the swath width?

Extra Puzzler The Quickbird satellite is flown at an altitude of 450 km, with a total angular field of view of 2.12 o. What is the swath width? W = 2 H’ tan  W = 2 * 450km * tan (1.06 o ) = 900km * W = 16.65km