Comparing Alternatives with Rate of Return

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Presentation transcript:

Comparing Alternatives with Rate of Return Use Incremental Analysis

Topics In this section, we recall the definition of ROR, discuss decision situations for multiple alternatives, and discuss the appropriate decision methodology for each situation

Rate of Return Recall that the ROR of an investment is the interest rate that makes NPW = 0 NAW = 0 PW Benefits = PW Costs AW Benefits = AW Costs For a single project, accept if ROR ≥ MARR.

Decisions Involving Multiple Projects Given a set of possible projects, any subset of the projects may be selected. only one may be selected, but one must be chosen. only one may be selected, but it is OK to choose none.

Non-Mutually Exclusive Alternatives Suppose we can select any subset of the projects. Solution Methodology: Compute the ROR of each alternative Select each alternative for which ROR ≥ MARR

Example 1: MARR = 13%

Analysis ROR of A = 13.7% ROR of B = 12.7% ROR of C = 15.3% Both A and C have ROR larger than our MARR. Therefore, select both A and C.

Mutually Exclusive Alternatives Suppose we must select one, only one, but at least one, alternative. Solution Methodology: Each increment of investment must yield the MARR. Perform Incremental Analysis:

Recall Incremental Analysis 1. Rank the alternatives in increasing order of investment. 2. Select as the defender the alternative with the smallest investment. 3. Let the challenger be the alternative with the next higher investment. 4. Accept or reject the challenger on the basis of the return on the extra investment. The winner becomes the defender. 5. If the highest level of investment has been reached, stop. Otherwise return to step 3.

Example 2: Comparing cost alternatives

Ranked Alternatives MARR = 15% Alternatives: All have five-year life and no salvage Ranked Alternatives : Rank by order of increasing investment: D, B, C, A.

Example 2: Incremental Analysis Defender: Project D. Next greater investment (Challenger): Project B. Is the extra investment in B over D justified? Incremental Investment: -$500 Incremental Benefit: $125 NAW= -500 (A/P, i, 5) + 125 => ROR = 8% < MARR Decision: Reject Challenger, Project B.

Example 2: Incremental Analysis (cont’d) Defender: Project D. Next greater investment (Challenger): Project C. Is the extra investment in C over D justified? Incremental Investment: -$1500 Incremental Benefit: $500 NAW= -1500 (A/P, i, 5) + 500 => ROR = 20% > MARR Decision: Accept Challenger, Project C.

Example 2: Incremental Analysis (cont’d) Defender: Project C. Next greater investment (Challenger): Project A. Is the extra investment in A over C justified? Incremental Investment: -$1000 Incremental Benefit: $260 NAW= -1000 (A/P, i, 5) + 260 => ROR = 9% < MARR Decision: Reject Challenger, Keep Defender, Project C

Example 3: Projects with Benefits Choose one of the three

Example 3 (cont’d) MARR = 13% (select one and only one) Ranked Projects: C, B, A

Example 3: Incremental Analysis Defender: Project C Challenger: Project B Is the extra investment in B over C justified? Incremental Investment: -$25,000 Incremental Benefit: $6000 NAW= -25 (A/P, i, 5) + 6 => ROR = 6.4% < MARR Decision: Reject Challenger, Keep Project C

Example 3: Incremental Analysis (cont’d) Defender: Project C Challenger: Project A Is the extra investment in A over C justified? Incremental Investment: -$40,000 Incremental Benefit: $2000 Useful Life: Project lives are different!!

Example 3: Incremental Analysis (cont’d) Select a common study period, say 45 years. 20,000 A 10 20 30 40 100,000 … 18,000 C 60,000

Example 3: Incremental Analysis (cont’d) Compute the incremental cash flows. The cash flows of A-C represent a non-simple investment. 60,000 2,000 A-C 10 20 30 40 40,000 60,000

Example 3: Incremental Analysis (cont’d) We must verify graphically (or with another method) that the interest found correspond to a rate of return. Luckily, it does. The rate of return of the incremental cash flows is 11.6%. Therefore reject the challenger, project A and accept C.

An Easier way for Different Lives Find ROR of A - C NAW(A - C) = NAW(A) - NAW(C) = 0 -100(A/P, i, 9) + 20 - [-60(A/P, i, 5) + 18] -100(A/P, i, 9) + 60(A/P, i, 5) + 2 = 0 i NAW(A - C) 0% 2889 5% 1789 10% 463 15% -1058 12% -123 ROR of A - C is 11.6%. Reject A - C and choose C

Mutually Exclusive Alternatives with a Do-Nothing Alternative Suppose we can select one alternative or no alternative Solution Methodology: Compute ROR of each alternative Reject any alternatives that do not yield the MARR If only one remains, choose that alternative If more than one remains, do incremental analysis to select the best

Example 4 MARR = 13% (select one or none)

Example 4 (cont’d) Since B does not return 13% it can be discarded. We most compare A and C, by computing the rate of return of the extra investment of A over C. The rate of return of A over C is 11.6%. Since the return on the extra investment is less than 13% (the MARR) reject the extra investment. We should choose option C.

Conclusion: Measure of merit is the ROR (a percentage) For a single alternative, accept if ROR ≥ MARR For multiple alternatives: Accept an increment if the ROR for the increment≥ MARR