Lattice Vibrations Part II

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Presentation transcript:

Lattice Vibrations Part II Solid State Physics 355

Three Dimensions For each mode in a given propagation direction, the dispersion relation yields acoustic and optical branches: Acoustic Longitudinal (LA) Transverse (TA) Optical Longitudinal (LO) Transverse (TO) If there are p atoms in the primitive cell, there are 3p branches in the dispersion relation: 3 acoustic and 3p -3 optical. NaCl – two atoms per primitive cell 6 branches: 1 LA 1 LO 2 TA 2 TO Transverse optical and transverse acoustic waves are shown for the two modes at the same wavelength. If the atoms have opposite charges, the motion can be excited by the electric field of an electromagnetic wave

Counting This enumeration follows from counting the number of degrees of freedom of the atoms. For p atoms in N primitive cells, there are pN atoms. Each atom has 3 degrees of freedom, one for each of the 3 directions x, y, and z. This gives 3Np degrees of freedom for the crystal.

q = ±/a q. q

Three Dimensions Al Ge For monatomic lattice… You write down Newton’s laws in 3D. You get three simultaneous equations that are solved using matrix methods. The result is an equation that is cubic in omega squared. Thus, there are three roots – or three dispersion equations. The three branches pass through the origin – making them all acoustic branches, which is expected for a monatomic lattice. The dispersion curves depend on the q direction you are looking in.

Quantization of Elastic Waves The energy of an elastic mode of angular frequency  is It is quantized, in the form of phonons, similar to the quantization of light, as both are derived from a discrete harmonic oscillator model. Elastic waves in crystals are made up of phonons. Thermal vibrations are thermally excited phonons. the quantum number n indicates the mode is occupied by n phonons. n can take on any integer value and vary with time The energy in the mode, as with any harmonic oscillator, is half kinetic and half potential energy, when averaged over time. Note the zero point energy

Phonon Momentum A phonon with a wavevector q will interact with particles, like neutrons, photons, electrons, as if it had a momentum (the crystal momentum) Be careful! Phonons do not carry momentum like photons do. They can interact with particles as if they have a momentum. For example, a neutron can hit a crystal and start a wave by transferring momentum to the lattice. However, this momentum is transferred to the lattice as a whole. The atoms themselves are not being translated permanently from their equilibrium positions. The only exception occurs when q = 0, where the whole lattice translates. This, of course, does carry momentum.

Phonon Momentum For example, in a hydrogen molecule the internuclear vibrational coordinate r1 r2 is a relative coordinate and doesn’t have linear momentum. The center of mass coordinate ½(r1 r2 ) corresponds to the uniform mode q = 0 and can have linear momentum. H2 R r Proton A Proton B electron r1 r2 O

Phonon Momentum Earlier, we saw that the elastic scattering of x-rays from the lattice is governed by the rule: If the photon scattering is inelastic, with a creation of a phonon of wavevector q, then If the photon is absorbed, then Where G is a reciprocal lattice vector. In this process, the whole crystal recoils with momentum -ħG

Phonon Scattering (Normal Process) q1 q3 = q1 + q2 q2 We can always add or subtract a crystal momentum wavevector from these totals. This is a general rule of solid state physics. Why is this true? Think about this in terms of the reciprocal lattice. Just like adding a lattice constant, a, to a real lattice doesn’t change the properties of the real space lattice, adding a wavevector G does not change the properties in momentum space (you are just in the next reciprocal lattice cell). This is only true because the lattice is periodic. q3 = q1 + q2 or q3 = q1 + q2 + G

Measuring Phonons reciprocal lattice vector scattered neutron Inelastic neutron scattering (INS) is the process of scattering neutrons from a specimen, accompanied by a change in energy of the neutron. Neutrons scattered off a specimen may absorb energy, but at low temperatures, neutron energy loss to the sample is much more likely. The energy imparted to the sample typically creates an elementary excitation, which may be a lattice vibration (phonon), magnetic excitation (magnon) or other type of excitation appropriate to the system under study (e.g., roton, Frenkel exciton, etc.). Although lattice vibrations were the earliest excitations measured in this manner (by Brockhouse, for which he shared the Nobel Prize) the technique is more general, and the measurement of magnetic excitations is equally if not more important. INS is an extremely valuable technique since it can reveal the total number of accessible excitation modes. This information is necessary, for example, in order to apply theories of thermodynamics which predict properties on the basis of the number and energy of all vibrational bands. Many materials have been studied this way. phonon wavevector (+ for phonon created,  for phonon absorbed) incident neutron Stokes or anti-Stokes Process

Measuring Phonons q

Measuring Phonons So, you can measure the incoming neutron’s wavevector and energy, and the outgoing neutron’s wavevector and energy, and then solve for the phonon’s energy. The phonon’s wavevector is solved for using: k + G = k’ +/- q

Measuring Phonons Other Techniques Inelastic X-ray Spectroscopy Raman Spectroscopy (IR, near IR, and visible light) Microwave Ultrasonics When light is scattered by any form of matter, the energies of the majority of the photons are unchanged by the process, which is elastic or Rayleigh scattering. However, about one in one million photons or less, loose or gain energy that corresponds to the vibrational frequencies of the scattering molecules. This can be observed as additional peaks in the scattered light spectrum. The process is known as Raman scattering and the spectral peaks with lower and higher energy than the incident light are known as Stokes and anti-Stokes peaks respectively. Most routine Raman experiments use the red-shifted Stokes peaks only, because they are more intense at room temperatures.

Heat Capacity Cv = yT+T3 You may remember from your study of thermal physics that the specific heat is the amount of energy per unit mass required to raise the temperature by one degree Celsius. Q = mcT Thermodynamic models give us this definition: We now move to a model that treats phonons like particles in a gas. As mentioned before, now we are going to look at how what we know about phonons will lead us to a description of the heat capacity as a function of temperature at constant volume. What we have to do is establish the rules we need to count how many phonons are active at a certain temperature, and then figure out how much energy goes into each. Cv = yT+T3 phonons electrons

Heat Capacity Equipartition Theorem: The internal energy of a system of N particles is Monatomic particles have only 3 translational degrees of freedom. They possess no rotational or vibrational degrees of freedom. Thus the average energy per degree of freedom is It turns out that this is a general result. The mean energy is spread equally over all degrees of freedom, hence the terminology – equipartition.

Heat Capacity Upon cooling to low temperature, scientists found that this law was no longer valid. It also wasn’t true for some materials, like diamond (why?) Also, it should be pointed out that the shape of the curves look different for different materials Can we use what we know about phonons to calculate the heat capacity? Some of our heat capacity goes to the electrons, and other sources, but in most materials the lattice vibrations absorb most of the energy.

Heat Capacity Answer: You need to use quantum statistics to describe this properly. Bosons and Fermions Bosons: particles that can be in the same energy state (e.g. photons, phonons) Fermions: particles that cannot be in the same energy level (e.g. electrons) Before we need to talk about how many phonons there are at a certain temperature, we need to discuss some terms in quantum statistics. Electrons can only be paired up if their spins are pointing in the opposite direction (and thus they have slightly different energies).

Planck Distribution Max Planck – first to come up with the idea of quantum energy worked to explain blackbody radiation empty cavity at temperature T, with which the photons are in equilibrium

Planck Distribution

Einstein Model 1907-Einstein developed first reasonably satisfactory theory of specific heat capacity for a solid assumed a crystal lattice structure comprising N atoms that are treated as an assembly of 3N one-dimensional oscillators approximated all atoms vibrating at the same frequency (unrealistic, but makes things easier) So, Einstein applied the Planck distribution to the problem and we know what the average energy distribution looks like. To get the average energy per oscillator, just multiply it by

all possible energy levels 0, 1, 2, etc. Planck Distribution Any system with a quadratic potential energy function has evenly spaced energy levels separated by energy hf, where f is the oscillation frequency. For a set of identical harmonic oscillators in equilibrium, the ratio of the number of oscillators in the (n+1)th state to the nth state is shown. number of phonons in energy level n total number of phonons all possible energy levels 0, 1, 2, etc.

Planck Distribution In order to calculate the heat capacity, we need to know how many phonons there are at each energy level on the average. So, what is the average energy level at a temp. T? Fraction of small as n gets large Phonons at energy n a constant

Planck Distribution average occupied energy level DENOMINATOR This is the average energy level, or the average number of phonons (since this is equal to n) that are occupied at a temperature T with frequency ω High T limit: as T →∞, <n> = 1/(exp(ħω/kT)-1) ~ 1/(1+ (ħω/kT) -1) ~ kT/ ħω(this is a large number) Low T limit: as T →0, <n> ~ exp(-ħω/kT) ~ 0 (ground state) no vibrations High energy limit, vibrations are suppressed or not active This is a handy number, because it tells us how many phonons are at each frequency we will need this to calculate the total phonon energy NUMERATOR

Einstein Model average energy per oscillator We have 3N such oscillators, so the total energy is

Einstein Model

Einstein Model How did Einstein do?

Einstein Model How did Einstein do? Third line down: the exponential part dominates over the 1/T^2 term In the last line, we have 1 over a very large number, which goes to zero.

Einstein Model The Einstein model failed to identically match the behavior of real solids, but it showed the way. In real solids, the lattice can vibrate at more than one frequency at a time. The model works well sometimes. Often, the optical modes are nearly constant with frequency, so the model works for those modes. I was reminded of a story that a friend of mine told about three guys who I think were with National Geographic. They were off in some dark part of Africa or someplace on an expedition and they were captured by what they thought or had been told would possibly be head-hunters or cannibals. And these three guys were scared to death and they were staked up to three stakes in the center of this village. Around them were 50-100 people with bones in their nose, spears and all kinds of things working themselves up into a frenzy and these guys were scared to death. All of a sudden it grew quiet and the Chief stepped forward and he went up to the first guy and he said, "you wish death-you wish Magumba?" And the guy said, "I don't want to die - I don't know what Magumba is, but I don't want to die - I choose Magumba." And the Chief said "Magumba!" at which point some guys step forward, cut him off of the stake, they picked him up over their heads, they dragged him off. This guy started screaming, the other two couldn't see him and he was goin' in the crowd. There was dust bein' raised - I mean it sounded like they were doing unspeakable, terrible things to this poor fellow. And as the screams got quieter and quieter, everything else got louder and louder and they couldn't imagine what was going on until pretty soon it got all quiet again. The Chief stepped up to the second guy - "you wish death - you wish Magumba?" "The poor guy's - God, I don't know what happened, but I don't want to die. I don't know what to do - Magumba." And the Chief said "Magumba!" Same thing - terrible unspeakable things were obviously happening to this poor fellow. Got quiet again - Chief stepped up to the third guy - "you wish death - you wish Magumba?" Guy said, "I ain't afraid of dyin' - I ain't afraid of Magumba - But I choose death." The Chief said, "Ah, very good choice, but first Magumba! Answer: the Debye Model