EGR 1101 Unit 7 Systems of Linear Equations in Engineering (Chapter 7 of Rattan/Klingbeil text)
Systems of Linear Equations A linear equation in one variable has a unique solution. Example: 2x=8 has a unique solution, namely x=4. A linear equation in two variables does not have a unique solution. Example: 3x-4y=7 does not have a unique solution. But a system of two independent linear equations in two variables does have a unique solution. Example: The pair of equations 3x-4y=7 and 2x+8y=26 has a unique solution, namely x=5 and y=2.
Generalizing More generally, for any positive integer n, a system of n independent linear equations in n variables does have a unique solution. It’s not unusual in engineering problems to end up with, say, eight equations in eight variables.
Four Methods We’ll study four methods for attacking such problems: 1. Substitution 2. Graphical method 3. Matrix algebra 4. Cramer’s Rule (a shortcut derived from matrix algebra) For a given problem, all four methods should give the same solution!
Today’s Examples 1. Currents in a two-loop circuit 2. Forces in static equilibrium: Hanging weight
A 2-by-2 Matrix Equation Suppose we have the system of equations a 11 x 1 + a 12 x 2 = b 1 a 21 x 1 + a 22 x 2 = b 2 We can write this in matrix form as or A x = b
Rewriting a Matrix Equation Suppose that in the matrix equation A x = b A is a matrix of known constants, and x is a vector of unknowns, and b is a vector of known constants. We can solve for the unknowns in x by rewriting this equation as x = A -1 b The problem becomes: How do we find the inverse matrix A -1 ?
Determinant of a 2-by-2 Matrix Suppose we have a matrix A given by This matrix’s determinant is given by |A| a 11 a 22 a 12 a 21 We sometimes use the symbol for the determinant.
Inverse of a 2-by-2 Matrix Suppose again we have a matrix A given by This matrix’s inverse is given by
Method 4. Cramer’s Rule This shortcut rule says that the solutions of a matrix equation A x = b are given by: where A i is obtained by replacing the ith column of A with the vector b.
Solving Matrix Equations with MATLAB First, define our coefficient matrix and our vector of constants: >> A = [10 4; 4 12] >> b = [6; 9] MATLAB offers at least three ways to proceed from here: >> x = inv(A)*b >> x = A^-1 * b >> x = A \ b