Clicker Questions Chapter 4 Barbara Mowery York College

A homogeneous mixture of two or more components is referred to as a solute. a solution. an electrolyte. a mess. Answer: b

A homogeneous mixture of two or more components is referred to as a solute. a solution. an electrolyte. a mess. Answer: b

The solvent in a sample of soda pop is sugar. carbon dioxide. water. air. Answer: c

The solvent in a sample of soda pop is sugar. carbon dioxide. water. air. Answer: c

The gaseous solute in a sample of soda pop is sugar. carbon dioxide. water. air. Answer: b

The gaseous solute in a sample of soda pop is sugar. carbon dioxide. water. air. Answer: b

water. sugar. air. electrolytes. Gatorade® and other sports drinks conduct electricity because they contain water. sugar. air. electrolytes. Answer: d

water. sugar. air. electrolytes. Gatorade® and other sports drinks conduct electricity because they contain water. sugar. air. electrolytes. Answer: d

When Fe(NO3)2 dissolves in water, the particles in solution are Fe+ and (NO3)2–. Fe2+ and 2 NO3–. Fe and 2 NO3. Fe and N2 and 3 O2. Answer: b

When Fe(NO3)2 dissolves in water, the particles in solution are Fe+ and (NO3)2–. Fe2+ and 2 NO3–. Fe and 2 NO3. Fe and N2 and 3 O2. Answer: b

Which set includes only substances that produce electrolytes in water? NaBr, KCl, MgSO4 C6H12O6, CH3OH, C6H6 HCl, NH3, Cl2, N2 SiO2, CaCO3, H2SO4 Answer: a

Which set includes only substances that produce electrolytes in water? NaBr, KCl, MgSO4 C6H12O6, CH3OH, C6H6 HCl, NH3, Cl2, N2 SiO2, CaCO3, H2SO4 Answer: a

Which compound below is not soluble in water? NaBr KNO3 MgSO4 ZnS Answer: d

Which compound below is not soluble in water? NaBr KNO3 MgSO4 ZnS Answer: d

Pb(NO3)2 + 2 KI  PbI2 + 2 KNO3 The physical evidence that the above reaction occurs is an explosion. the formation of a gas. that the solution boils. the formation of a precipitate. Answer: d

Pb(NO3)2 + 2 KI  PbI2 + 2 KNO3 The physical evidence that the above reaction occurs is an explosion. the formation of a gas. that the solution boils. the formation of a precipitate. Answer: d

H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2 Which pair of compounds will produce a precipitate if solutions of appropriate concentrations are mixed together? H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2 Answer: c

H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2 Which pair of compounds will produce a precipitate if solutions of appropriate concentrations are mixed together? H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2 Answer: c

When an acid reacts with a base, the result is cancellation. elimination. neutralization. adduct formation. Answer: c

When an acid reacts with a base, the result is cancellation. elimination. neutralization. adduct formation. Answer: c

K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–. When nitric acid is neutralized by potassium hydroxide, the spectator ions are K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–. Answer: a

K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–. When nitric acid is neutralized by potassium hydroxide, the spectator ions are K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–. Answer: a

Which compound below is not a strong acid? HC2H3O2 H2SO4 HNO3 HBr Answer: a

Which compound below is not a strong acid? HC2H3O2 H2SO4 HNO3 HBr Answer: a

When an atom undergoes oxidation, it ______ electrons. gains loses retains balances Answer: b

When an atom undergoes oxidation, it ______ electrons. gains loses retains balances Answer: b

When an atom undergoes reduction, it ______ electrons. gains loses retains balances Answer: a

When an atom undergoes reduction, it ______ electrons. gains loses retains balances Answer: a

reduced; gains reduced; loses oxidized; gains oxidized; loses When Zn(s) reacts with HCl(aq) to produce H2(g) and ZnCl2(aq), the zinc is _____ because it _____ electrons. reduced; gains reduced; loses oxidized; gains oxidized; loses Answer: d

reduced; gains reduced; loses oxidized; gains oxidized; loses When Zn(s) reacts with HCl(aq) to produce H2(g) and ZnCl2(aq), the zinc is _____ because it _____ electrons. reduced; gains reduced; loses oxidized; gains oxidized; loses Answer: d

Al + H+  Al3+ + H2 When the oxidation–reduction reaction above is correctly balanced, the coefficients are 1, 2  1, 1. 1, 3  1, 2. 2, 3  2, 3. 2, 6  2, 3. Answer: d

Al + H+  Al3+ + H2 When the oxidation–reduction reaction above is correctly balanced, the coefficients are 1, 2  1, 1. 1, 3  1, 2. 2, 3  2, 3. 2, 6  2, 3. Answer: d

In the list shown, the metal that is most easily oxidized is ___. Ca Fe Cu Answer: a

In the list shown, the metal that is most easily oxidized is ___. Ca Fe Cu Answer: a

A solution is prepared by dissolving 35 A solution is prepared by dissolving 35.0 g of NaCl in water to make 500 mL of solution. What is the molarity? 7.00 M 3.04 M 1.97 M 1.20 M Answer: d

A solution is prepared by dissolving 35 A solution is prepared by dissolving 35.0 g of NaCl in water to make 500 mL of solution. What is the molarity? 7.00 M 3.04 M 1.97 M 1.20 M Answer: d

250.0 mL of 0.100 M AgNO3 solution contains _____ g of silver nitrate. 4.25 8.50 17.0 34.0 Answer: a

250.0 mL of 0.100 M AgNO3 solution contains _____ g of silver nitrate. 4.25 8.50 17.0 34.0 Answer: a

To make 250. 0 mL of 0. 500 M KI solution, _____ mL of 6 To make 250.0 mL of 0.500 M KI solution, _____ mL of 6.00 M KI must be used. 20.8 41.7 500.0 3000.0 Answer: a

To make 250. 0 mL of 0. 500 M KI solution, _____ mL of 6 To make 250.0 mL of 0.500 M KI solution, _____ mL of 6.00 M KI must be used. 20.8 41.7 500.0 3000.0 Answer: a

HCl + KOH  KCl + H2O 25. 00 mL of HCl was titrated using 18 HCl + KOH  KCl + H2O 25.00 mL of HCl was titrated using 18.50 mL of 0.1554 M NaOH. The concentration of HCl is 0.0777 M. 0.1150 M. 0.2100 M. 0.2875 M. Answer: b

HCl + KOH  KCl + H2O 25. 00 mL of HCl was titrated using 18 HCl + KOH  KCl + H2O 25.00 mL of HCl was titrated using 18.50 mL of 0.1554 M NaOH. The concentration of HCl is 0.0777 M. 0.1150 M. 0.2100 M. 0.2875 M. Answer: b

HX + NaOH  NaX + H2O 229 mg of HX was titrated using 29. 33 mL of 0 HX + NaOH  NaX + H2O 229 mg of HX was titrated using 29.33 mL of 0.0965 M NaOH. What is element X? F Cl Br I Answer: c

HX + NaOH  NaX + H2O 229 mg of HX was titrated using 29. 33 mL of 0 HX + NaOH  NaX + H2O 229 mg of HX was titrated using 29.33 mL of 0.0965 M NaOH. What is element X? F Cl Br I Answer: c