Prime Numbers Prime numbers only have divisors of 1 and self

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Presentation transcript:

Module :MA3036NI Number theory and Public key Encryption Lecture Week 6

Prime Numbers Prime numbers only have divisors of 1 and self they cannot be written as a product of other numbers note: 1 is prime, but is generally not of interest E.g. 2,3,5,7 are prime; 4,6,8,9,10 are not Prime numbers are central to Number Theory List of prime numbers less than 200 is: 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199

Prime Factorisation To factor a number n is to write it as a product of other numbers: n=a × b × c Note that factoring a number is relatively hard compared to multiplying the factors together to generate the number The prime factorisation of a number n is when it is written as a product of primes eg. 91=7×13 ; 3600=24×32×52 The idea of "factoring" a number is important - finding numbers which divide into it. Taking this as far as can go, by factorising all the factors, we can eventually write the number as a product of (powers of) primes - its prime factorisation.

Relatively Prime Numbers & GCD Two numbers a , b are relatively prime if have no common divisors apart from 1 e.g. 8 & 15 are relatively prime since factors of 8 are 1,2,4,8 and of 15 are 1,3,5,15 and 1 is the only common factor Conversely can determine the greatest common divisor by comparing their prime factorizations and using least powers e.g. 300=22×31×52 ,18=21×32 hence GCD(18,300)=21×31×50=6

Fermat's Theorem Fermat’s theorem states that, ap-1 mod p = 1 where p is prime and gcd(a , p)=1 Also known as Fermat’s Little Theorem Useful in public key Encryption and primality testing

Euler Totient Function ø(n) When doing arithmetic modulo n complete set of residues is: 0..n-1 Reduced set of residues is those numbers (residues) which are relatively prime to n e.g. for n=10, complete set of residues is {0,1,2,3,4,5,6,7,8,9} reduced set of residues is {1,3,7,9} Number of elements in reduced set of residues is called the Euler Totient Function ø(n)

Euler Totient Function ø(n) To compute ø(n) need to count number of elements to be excluded In general need prime factorization, but for p (p prime) ø(p) = p-1 for p*q (p,q prime) ø(p*q) = (p-1)(q-1) E.g. ø(37) = 36 ø(21) = (3–1)×(7–1) = 2×6 = 12

Euler's Theorem A generalisation of Fermat's Theorem, Which States that , aø(n)mod n = 1 where gcd(a , n)=1 E.g. a=3;n=10; ø(10)=4; hence 34 = 81 = 1 (mod 10) a=2;n=11; ø(11)=10; hence 210 = 1024 = 1 (mod 11)

Primality Testing Often need to find large prime numbers Traditionally sieve using trial division ie. divide by all numbers (primes) in turn less than the square root of the number only works for small numbers Alternatively can use statistical primality tests based on properties of primes for which all primes numbers satisfy property but some composite numbers, called pseudo-primes, also satisfy the property

Miller Rabin Algorithm A test based on Fermat’s Theorem Algorithm is: TEST (n) is: 1. Find integers k, q, k > 0, q odd, so that (n–1)=2kq 2. Select a random integer a, 1<a<n–1 3. if aq mod n = 1 then return ("maybe prime"); 4. for j = 0 to k – 1 do 5. if (a2jq mod n = n-1) then return("maybe prime ") 6. return ("composite")

Probabilistic Considerations If Miller-Rabin returns “composite” the number is definitely not prime Otherwise is a prime or a pseudo-prime Chance it detects a pseudo-prime is < ¼ Hence if repeat test with different random a then chance n is prime after t tests is: Pr(n prime after t tests) = (¼)t eg. for t=10 this probability is > 0.99999 = 1 – (¼)t

Prime Distribution Prime number theorem states that primes occur roughly every (ln n) integers (ln is log value with base e) Since can immediately ignore evens and multiples of 5, in practice only need test 0.4 ln(n) numbers of size n before locate a prime note this is only the “average” sometimes primes are close together, at other times are quite far apart

Summary Have considered: Prime numbers Fermat’s and Euler’s Theorems Primality Testing

Private-Key Cryptography - Revision Traditional private/secret/single key cryptography uses one key Shared by both sender and receiver If this key is disclosed communications are compromised Also it is symmetric, parties are equal. So far all the cryptosystems discussed have been private/secret/single key (symmetric) systems. All classical, and modern block and stream ciphers are of this form.

Public-Key Cryptography Probably most significant advance in the 3000 year history of cryptography Uses two keys – a public & a private key Asymmetric since parties are not equal Uses clever application of number theoretic concepts to function Complements rather than replaces private key cryptography Will now discuss the radically different public key systems, in which two keys are used. Anyone knowing the public key can encrypt messages or verify signatures, but cannot decrypt messages or create signatures, counter-intuitive though this may seem. It works by the clever use of number theory problems that are easy one way but hard the other. Note that public key schemes are neither more secure than private key (security depends on the key size for both), nor do they replace private key schemes (they are too slow to do so), rather they complement them.

Public-Key Cryptography Public-key/two-key/asymmetric cryptography involves the use of two keys: a public-key, which may be known by anybody, and can be used to encrypt messages, and verify signatures a private-key, known only to the recipient, used to decrypt messages, and sign (create) signatures It is asymmetric because those who encrypt messages or verify signatures cannot decrypt messages or create signatures

Why Public-Key Cryptography? Developed to address two key issues: key distribution – how to have secure communications in general without having to trust a Key distribution channel(KDC) with your key digital signatures – how to verify a message comes intact from the claimed sender Public invention due to Whitfield Diffie & Martin Hellman at Stanford Uni in 1976 known earlier in classified community The idea of public key schemes, and the first practical scheme, which was for key distribution only, was published in 1977 by Diffie & Hellman. The concept had been previously described in a classified report in 1970 by James Ellis (UK CESG) - and subsequently declassified in 1987. See History of Non-secret Encryption (at CESG). Its interesting to note that they discovered RSA first, then Diffie-Hellman, opposite to the order of public discovery!

Public-Key Characteristics Public-Key algorithms rely on two keys with the characteristics that it is: computationally infeasible to find decryption key knowing only algorithm & encryption key computationally easy to en/decrypt messages when the relevant (en/decrypt) key is known either of the two related keys can be used for encryption, with the other used for decryption (in some schemes) Public key schemes utilise problems that are easy (P type) one way but hard (NP type) the other way, eg exponentiation vs logs, multiplication vs factoring. Consider the following analogy using padlocked boxes: traditional schemes involve the sender putting a message in a box and locking it, sending that to the receiver, and somehow securely also sending them the key to unlock the box. The radical advance in public key schemes was to turn this around, the receiver sends an unlocked box to the sender, who puts the message in the box and locks it (easy - and having locked it cannot get at the message), and sends the locked box to the receiver who can unlock it (also easy), having the key. An attacker would have to pick the lock on the box (hard).

Public-Key Applications Can classify uses into 3 categories: -encryption/decryption -The sender encrypts a message with the recipient's public key(provide secrecy) -digital signatures- The sender signs a message with its private key by using cryptographic algorithm to the message or block of data.(provide authentication) -key exchange- Two sides cooperate to exchange a session key .(of session keys) Some algorithms are suitable for all uses, others are specific to one

Security of Public Key Schemes Like private key schemes brute force exhaustive search attack is always theoretically possible But keys used are too large (>512bits) Security relies on a large enough difference in difficulty between easy (en/decrypt) and hard (cryptanalyse) problems Requires the use of very large numbers Hence is slow compared to private key schemes Public key schemes are no more or less secure than private key schemes - in both cases the size of the key determines the security. Note also that you can't compare key sizes - a 64-bit private key scheme has very roughly similar security to a 512-bit RSA - both could be broken given sufficient resources. But with public key schemes at least there's usually a firmer theoretical basis for determining the security since its based on well-known and well studied number theory problems.

The RSA Algorithm By Rivest, Shamir & Adleman in 1977 at MIT Best known & widely used public-key scheme Uses large integers (eg. 1024 bits) Security due to cost of factoring large numbers nb. factorisation takes O(e log n log log n) operations (hard) RSA is the best known, and by far the most widely used general public key encryption algorithm.

RSA Key Setup Each user generates a public/private key pair by: Selecting two large primes at random - p, q Computing their system modulus N=p*q note ø(N)=(p-1)(q-1) Selecting at random the encryption key e where 1<e<ø(N), gcd(e,ø(N))=1 Solve following equation to find decryption key d e*d=1 mod ø(N) and 0≤d≤N Publish their public encryption key: PU={e,N} Keep secret private decryption key: PR={d,p,q} This key setup is done once (rarely) when a user establishes (or replaces) their public key. The exponent e is usually fairly small, just must be relatively prime to ø(N). Need to compute its inverse to find d. It is critically important that the private key PR={d,p,q} is kept secret, since if any part becomes known, the system can be broken. Note that different users will have different moduli N.

RSA Use To encrypt a message M the sender: obtains public key of recipient PU={e,N} computes: C=Me mod N, where 0≤M<N To decrypt the ciphertext C the owner: uses their private key PR={d,p,q} computes: M=Cd mod N Note that the message M must be smaller than the modulus N

RSA Example Select primes: p=17 & q=11 Compute n = pq =17×11=187 Select e : gcd(e,160)=1; choose e=7 Determine d: de=1 mod 160 and d<160 Value is d=23 since 23×7=161= 1×160+1 Publish public key PU={e,N}={7,187} Keep secret private key PR={d,p,q}={23,17,11} Here walk through example using “trivial” sized numbers. Selecting primes requires the use of primality tests. Finding d as inverse of e mod ø(n) requires use of Inverse algorithm (see Ch4)

RSA Example cont Sample RSA encryption/decryption is: Given message M = 88 (nb. 88<187) Encryption: C = 887 mod 187 = 11 Decryption: M = 1123 mod 187 = 88 Rather than having to laborious repeatedly multiply, can use the "square and multiply" algorithm with modulo reductions to implement all exponentiations quickly and efficiently (see next).

RSA Key Generation Users of RSA must: determine two primes at random - p, q select either e or d and compute the other Primes p,q must not be easily derived from modulus N=p*q means must be sufficiently large typically guess and use probabilistic test Exponents e, d are inverses, so use Inverse algorithm to compute the other(d= 1/e mod Ø(n)) Both the prime generation and the derivation of a suitable pair of inverse exponents may involve trying a number of alternatives, but theory shows the number is not large.

RSA Security Three approaches to attacking RSA: brute force key search i.e trying all possible private keys(infeasible given size of numbers) mathematical attacks (based on difficulty of computing ø(N), by factoring N) timing attacks (on running of decryption)

Tutorial exercises… Perform encryption and decryption using RSA algorithm, for the following: p = 3; q = 11, M = 5 p = 5; q = 11, M = 9 In a public-key system using RSA, you intercept the cipher text C = 10 sent to a user whose public key is e = 5, n = 35. What is the plaintext M?

Summary Have considered: Principles of public-key cryptography RSA algorithm, implementation, security