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Presentation transcript:

Building Blocks 1d Int

Which elements are conductors of electricity? Metals and the non-metal carbon(graphite)

Which elements are non- conductors of electricity? Non metals except carbon(graphite)

Why are metals able to conduct electricity? They contain free moving electrons

Which type of compounds (solid, liquid, solution) do not conduct electricity? Covalent compounds (non metals atoms)

Why are covalent compounds unable to conduct electricity? They are made up of molecules which are uncharged. They do not contain charged ions.

In which state will an ionic compound not conduct electricity? solid

Why are ionic compounds able to conduct electricity when molten or in solution? They ions are free to move

Why do ionic compounds not conduct electricity when solid? They ions are not free to move

A solid substance conducts electricity. What type of substance is it? Metal or carbon(graphite) (no compound conducts when solid)

A substance does not conduct when solid but is able to conduct when molten/solution. What type of substance is it? Ionic Metal/non-metal compound

A substance does not conduct electricity in any state. What type of substance is it? Covalent

A substance does not conduct electricity in any state and has a very high melting/boiling point. What type of substance is it? Covalent network

A substance does not conduct electricity in any state and has a low melting/boiling point. What type of substance is it? Covalent molecule

Are ionic compounds usually soluble or insoluble in water? soluble

Are covalent compounds usually soluble or insoluble in water? Insoluble

What is electrolysis? The breaking up of an ionic compound using electricity.

What is an electric current? A flow of electrons

A pupil passed electricity through copper chloride solution. What would be seen at the negative electrode? Brown solid/copper metal - positive metal ions are attracted to the negative electrode. Chlorine gas(bubbles of gas would be seen at the positive electrode - chloride ions are negative.

A pupil passed electricity through copper chloride solution. Write ion electron equations showing the formation of copper and the formation of chlorine. ? At negative electrode: Cu e - Cu At positive electrode: 2Cl - Cl 2 + 2e -

Why must a d.c supply be used in electrolysis? So that the products can be identified. So only one product is collected/given off at an electrode.

Are electrons gained or lost at the negative electrode? Positive metal ions gain electrons.

Write the formula for the following- carbon monoxide, nitrogen dioxide, sulphur trioxide, dinitrogen tetraoxide, carbon tetrachloride, CO NO 2 SO 3 N 2 O 4 CCl 4

Write the formula for the following lithium chloride, magnesium nitride, aluminium nitride, sodium sulphide LiCl Mg 3 N 2 AlN Na 2 S

Write the formula for the following iron(II) oxide, copper(I) oxide, Silver(I) chloride, iron(III)chloride FeO Cu 2 O AgCl FeCl 3

Write the formula for the following sodium sulphate, copper carbonate, magnesium hydroxide, ammonium carbonate, calcium nitrate Na 2 SO 4 CuCO 3 Mg(OH) 2 (NH 4 ) 2 CO 3 Ca(NO 3 )

Balance to following equations C 3 H 8 + O 2 CO 2 + H 2 O Al + Cl 2 AlCl 3 CaCO 3 + HCl CaCl 2 + CO 2 + H 2 O C 3 H O 2 3 CO H 2 O 2Al + 3Cl 2 2AlCl 3 CaCO 3 + 2HCl CaCl 2 + CO 2 + H 2 O

Calculate the formula mass of the following CH 4 H 2 O Na 2 SO 4 Ca(NO 3 ) 2 CH =16 H 2 O (2 x 1) + 16 = 18 Na 2 SO 4 (2 x 23) (4 x16) = 142 Ca(NO 3 ) (2 x 14) + (6 x 16) =164

Calculate one mole of the following Cl 2 CaCO 3 CO 2 Mg(OH) 2 Cl 2 2 x 35.5 = 71g CaCO (3x16) = 100g CO (2 x 16) = 44g Mg(OH) (2 x 16) + (2 x 1) = 58.5 g

Calculate the number of moles in the following 88g CO 2 10g CaCO g KNO 3 16g O 2 1 mole CO 2 = 12 + (2 x 16) = 44g 88/44 = 2 moles 1 mole CaCO 3 = (3 x 16) = 100g 10/100 = 0.1 moles 1 mole KNO 3 = (3 x 16) = 101g 10.1/101 = 0.1 moles 1 mole O 2 = 2 x 16 = 32 g 16/32 = 0.5 moles

Calculate the mass of the following 4 moles HCl 0.1 moles H 2 S 0.25 moles CaCO moles (NH 4 ) 2 SO 4 1mole HCl = 1 x 35.5 = 36.5g 4 moles = 4 x 36.6 = 146g 1mole of H 2 S = (2 x 1) + 32 = 34 g 0.1 moles = 0.1 x 34 = 3.4g 1 moles CaCO 3 = (3 x 16) = 100g 0.25 moles = 0.25 x 100 = 25g 1 mole (NH 4 ) 2 SO 4 = (2 x 14) + (8 x 1) (4 x 16) = 132g 0.5 moles = 0.5 x 132 = 66g

Calculate the mass of carbon dioxide is produced when 4g of methane burns completely in oxygen. CH 4 + 2O 2 CO 2 + 2H 2 O 1 mole of CH 4 produced 1 mole of CO 2 if 16g gives 44g then 4g gives 4/16 x 44 = 11g ( 4g is a 1/4 of 16g so a 1/4 of 44g is 11g)

Calculate the mass of water produced on burning 2.8g of ethene. C 2 H 4 + 3O 2 2CO 2 + 2H 2 O 1 moles of ethene C 2 H 4 produced 2 moles water H 2 O 28g (1 mole) gives 36g (2 moles) 2.8g gives 2.8/28 x 36 = 3.6g ( 2.8g is a tenth of 28g so a tenth of 36g is 3.6g

Building Blocks 1d Int