Notes #14, Ch. 9 Stoichiometry and Theoretical Yield.

Slides:



Advertisements
Similar presentations
Mole Review 1.) Calculate the number of moles in 60.4L of O2. 2.) How many moles are there in 63.2g of Cl2? 1 mol O2 60.4L O2 = 2.7 mol O2 22.4L O2 1mol.
Advertisements

LIMITING REACTANT The reactant that gives the least number of product moles “limits” the reaction. To understand this concept, let’s suppose you were an.
Copyright©2004 by Houghton Mifflin Company. All rights reserved. 1 Introductory Chemistry: A Foundation FIFTH EDITION by Steven S. Zumdahl University of.
Copyright©2004 by Houghton Mifflin Company. All rights reserved. 1 Introductory Chemistry: A Foundation FIFTH EDITION by Steven S. Zumdahl University of.
Chemical Quantities Chapter 9
HONORS CHEMISTRY Feb 27, Brain Teaser Cu + 2 AgNO 3  2 Ag + Cu(NO 3 ) 2 – How many moles of silver are produced when 25 grams of silver nitrate.
Copyright © Houghton Mifflin Company. All rights reserved. 9 | 1 Information Given by the Chemical Equation Balanced equations show the relationship between.
Zumdahl • Zumdahl • DeCoste
Limiting Reagent What happens in a chemical reaction, if there is an insufficient amount of one reactant?
Chapter 9 Chemical Equations & Reaction Stoichiometry.
Stoichiometry, Limiting Reactants and Percent Yield
Chapter 9 Stoichiometry.
Limiting Reactants Very rare that reactants are present in the same ratio that they are used in the rxn. This means one reactant will run out first. This.
Stoichiometry Introduction.
Chapter 9 Chemical Quantities. 9 | 2 Information Given by the Chemical Equation Balanced equations show the relationship between the relative numbers.
AP Chemistry Chap. 3 Stoichiometry, Part Chemical Equations (p. 100)- shows a chemical change. Reactants on the LHS, products on the RHS. Bonds.
Percent Yield and Limiting Reactants
Stoichiometry.
Limiting Reactants and Excess
Limiting reagent, Excess reactant, Theoretical or Percent yield
Lecture 109/21/05. Mass reactant Stoichiometric factor Moles reactant Moles product Mass product Stoichiometric Calculations.
Chapter 9 Stoichiometry
© 2014 Pearson Education, Inc. Basic Chemistry, 4/e Chapter 9: Chemical Quantities in Reactions Karen Timberlake.
CHAPTER THREE CHEMICAL EQUATIONS & REACTION STOICHIOMETRY Goals Chemical Equations Calculations Based on Chemical Equations The Limiting Reactant Concept.
P ERCENT Y IELD. OBJECTIVE I can calculate percent yield of a reaction.
Mass Relationships in Chemical Reactions. Names associated with an amount Can you think of any more?????
1 Chapter 9-Stoichiometry Stoichiometry – measures and calculates amounts of chemicals in a reaction. A.Mole/Mole Problems Coefficients: Show # of molecules.
Things you must KNOW and what to expect  Things you must KNOW  You must KNOW your polyatomics  You must KNOW how to write a balanced formula  You have.
Mass Relationships in Chemical Reactions Chapter 3.
April 7, 2014 Today: Stoichiometry and % Yield. Percent Yield Remember, stoichiometry is used to tell you how much product you can form from X amount.
Chapter 12 Review “Stoichiometry”
Stoichiometry. Information Given by the Chemical Equation  The coefficients in the balanced chemical equation show the molecules and mole ratio of the.
Limiting Reactants and Percent Yield
Quantities in Chemical Reactions. the amount of every substance used and made in a chemical reaction is related to the amounts of all the other substances.
Chapter 9 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
 Objective: Understand molecular formulas and balancing equations.  Before: Introduction to molecular formulas  During: Discuss molecular formulas.
Chapter 9 Chemical Quantities. Copyright © Houghton Mifflin Company. All rights reserved. 9 | 2 Information Given by the Chemical Equation Balanced equations.
Chapter 12 Stoichiometry. 1. The part of chemistry that deals with the amount of substances involved in chemical reactions A. 3 basic steps to every stoichiometry.
Gravimetric Stoichiometry Is used to calculate masses of reactants and products in a reaction.
II. Stoichiometry in the Real World Stoichiometry.
Limiting Reactions and Percent Yield Calculating by moles or mass ©2011 University of Illinois Board of Trustees
Stoichiometry: A calculation based on a balanced equation. Granada Hills Charter High School.
Stoichiometry Warmup I have 1 mole of CO 2 gas at STP. How many grams of CO 2 do I have? How many Liters of CO 2 do I have? How many molecules of CO 2.
Limiting reagents In lab a reaction is rarely carried out with exactly the required amounts of each reactant. In lab a reaction is rarely carried out with.
PERCENT YIELD. Percent Yield Percent yield is the ratio of actual yield of an experiment to theoretical yield. To find percent yield, you divide the actual.
Mass-Mass Stoichiometry If the mass of any reactant or product is known for a chemical reaction, it is possible to calculate the mass of the other reactants.
Video 9-1 Reaction Stoichiometry Steps for Problem Solving.
Copyright©2004 by Houghton Mifflin Company. All rights reserved. 1 Introductory Chemistry: A Foundation FIFTH EDITION by Steven S. Zumdahl University of.
By Steven S. Zumdahl & Donald J. DeCoste University of Illinois Introductory Chemistry: A Foundation, 6 th Ed. Introductory Chemistry, 6 th Ed. Basic Chemistry,
Limiting Reactants, Theoretical Yield, and % Yield.
1 Percent Yield. 2 Theoretical, Actual, and Percent Yield Theoretical yield The maximum amount of product calculated using the balanced equation. Actual.
Ch. 9-3 Limiting Reactants & Percent Yield. POINT > Define limiting reactant POINT > Identify which reactant is limiting in a reaction POINT > Define.
TOPIC 17: INTRO TO STOICHIOMETRY EQ: EQ: How does a balanced chemical equation help you predict the number of moles and masses of reactants and products?
Chemistry Chapter 9 - Stoichiometry South Lake High School Ms. Sanders.
Section 9.1 Using Chemical Equations Steven S. Zumdahl Susan A. Zumdahl Donald J. DeCoste Gretchen M. Adams University of Illinois at Urbana-Champaign.
Challenge Problem When nitrogen and hydrogen react, they form ammonia gas, which has the formula NH 3. If 56.0 g of nitrogen are used up in the reaction,
Mass-Mass Conversions 56.0 g N 2 x g N 2 g NH = 1904 = When nitrogen and hydrogen react, they form ammonia gas, which has the formula.
Stoichiometry. Stoichiometry Stoichiometry – the process of using a balanced chemical equation to calculate the relative amounts of reactants and products.
Stoichiometry Pronounced: Stoy-kee-AHM-uh-tree. What is stoichiometry? Its math that helps us to see the relationship between what is used and formed.
Limiting Reagent What happens in a chemical reaction, if there is an insufficient amount of one reactant?
Chapter 9 Stoichiometry
Stoichiometry Chapter 3
Chapter 12 Review.
HONORS CHEMISTRY Feb 27, 2012.
Chapter 9 “Stoichiometry”
Chapter 7: 7.3 Reaction Yields
How many moles of water are made by
Bell Work: Limiting Reactant Problems
Stoichiometry.
Presentation transcript:

Notes #14, Ch. 9 Stoichiometry and Theoretical Yield

What is Stoichiometry? It is a way to calculate how much of a chemical is consumed or produced in a chemical reaction using Dimensional Analysis.

Propanol (rubbing alcohol) C 3 H 7 OH, burns in air. Write and balance the reaction: 2C 3 H 7 OH + 9O 2  6CO 2 + 8H 2 O What are the Equivalents? 2 mols C 3 H 7 OH  9 mols O 2  6 mols CO 2  8 mols H 2 O This reaction will be used in the next few examples.

Example 1: How many moles of water are produced from the combustion of 20.0 g propanol? The arrow: 20.0 g C 3 H 7 OH  ? mols H 2 O Chemistry Tip of the Year: “When in doubt, go to moles!” Why? So you can use the mole ratios in the reaction as equivalents.

Solution: So, 1.33 mols of H 2 O is produced

Example 2: How many grams of oxygen is needed to react with 12.0 grams of propanol? 12.0 g C 3 H 7 OH  ? g O 2

Solution: So, 28.8 grams of oxygen is needed for the 12.0 grams of propanol to burn

Example 3: If 25.3 g of carbon dioxide is produced, how many grams of propanol was burned? 25.3g CO 2  ? g C 3 H 7 OH

Solution: So 11.5 grams of propanol was burned to produce the 25.3 grams of CO 2.

The Theoretical Yield Concept What if the reacts aren’t present in the exact ratio needed?

What theoretical yield is all about: Ordinarily, reactants are not present in the exact ratio needed to complete a reaction. One reactant is used up, or “limits the reaction.” The other reactant has some left over, unused.

Steps for calculating theoretical yield: 1. Calculate the yield as if the first reactant was limiting how much product is made. 2. Calculate the yield as if the second reactant was limiting the amount of product. 3. The Lesser of these two yields is the theoretical yield (T.Y.), or how much product you could ideally make. 4. The reactant in the D.A. which leads to the T.Y. is used up and is your “limiting reactant.”

Hot Dog Example: 8 buns + 10 wieners  ? hot dogs?

Step 1. 8 buns  ? hot dogs

Step wieners  ? hot dogs

Step 3: TY & LR Possible Yield from step 1 was 8 hot dogs Possible Yield from step 2 was 10 hot dogs You can make lesser yield, 8 hot dogs. This is the Theoretical Yield The buns are the limiting reactant. There are extra wienies.

Skateboard Factory Example: You inherit the remnants of a skateboard store which went under. You have:  167 wheels  93 wheel “trucks”  71 boards How many skateboards can you make?

So, 41 skateboards is the theoretical yield. The limiting reactant is the wheels.

Chemistry Example: 2Ag + I 2  2AgI If you start with 1.00 g of each reactant, how much silver iodide could you make?

2Ag + I 2  2AgI Step g Ag  ? g AgI Possible Yield: 2.18 g AgI

2Ag + I 2  2AgI Step g I 2  ? g AgI Possible Yield: 1.85 g AgI

Step 3: So, the theoretical Yield is 1.85 g AgI, lesser of the two. Limiting Reactant is iodine, it’s all used up. There’s left over silver. The actual yield is always a little less, due to unwanted side reactions and loss.

Percent Yield Example: If you do the reaction in lab, mixing 1.0 grams of each reactant, and you get 1.50 g AgI in your filter paper, what is the actual percent yield?