Binary Solutions LECTURE 2.

Slides:



Advertisements
Similar presentations
Energy and Chemical Change
Advertisements

The thermodynamics of phase transformations
Solutions of Nonelectrolytes
CHEMICAL AND PHASE EQUILIBRIUM (1)
MSEG 803 Equilibria in Material Systems 12: Solution Theory
Department of Civil & Environmental Engineering
Solutions Lecture 6. Clapeyron Equation Consider two phases - graphite & diamond–of one component, C. Under what conditions does one change into the other?
Entropy and Free Energy Chapter 19. Laws of Thermodynamics First Law – Energy is conserved in chemical processes neither created nor destroyed converted.
A cup of hot tea is made and is left on a table. What do you expect to spontaneously happen to the temperature of the tea?
2. Solubility and Molecular Weights Polymer Solubility1.
Phase Equilibrium II - Two Component System. How many components and phases in this system? 2 components and 1 liquid phase Method to separate ethanol.
Chemical Thermodynamics 2013/ th Lecture: Thermodynamics of Simple Mixtures Valentim M B Nunes, UD de Engenharia.
Solutions Chapter 14. Key concepts 1.Understand the solvation process at the molecular level. 2.Be able to qualitatively describe energy changes during.
Properties of Solutions
Vapour Pressure and Heat Phase changes can be expressed as enthalpy changes at constant temperatures (Claussius-Clapeyron equation). What happens to a.
Lecture 18Multicomponent Phase Equilibrium1 Theories of Solution The Gibbs energy of mixing is given by: And the chemical potential is: For ideal gases,
Peter Atkins • Julio de Paula Atkins’ Physical Chemistry
Thermodynamics Chapter 19 Liquid benzene Production of quicklime Solid benzene ⇅ CaCO 3 (s) ⇌ CaO + CO 2.
1 CHEM 212 Chapter 5 Phases and Solutions Dr. A. Al-Saadi.
Crystalline Arrangement of atoms. Chapter 4 IMPERFECTIONS IN SOLIDS The atomic arrangements in a crystalline lattice is almost always not perfect. The.
Thermodynamics: Spontaneity, Entropy and Free Energy.
Chemistry Thermodynamics Lecture 13 : Non Ideal Solutions and Activity Lecture 14 : Chemical Equilibria Lecture 15 : Kinetic Coefficients & the.
Thermodynamics of Multi-component Systems Consider a binary solid solution of A and B atoms: Let n A = # of moles of A n B = # of moles of B def:mole(or.
 Section 1 – Thermochemistry  Section 2 – Driving Force of Reactions.
SIMPLE MIXTURES Chapter 5.
Advanced Thermodynamics Note 9 Vapor/Liquid Equilibrium: Introduction
Chemical Thermodynamics Chapter 19 (except 19.7!).
Chapter Outline: Phase Diagrams
 Section 1 – Thermochemistry  Section 2 – Driving Force of Reactions.
Chemistry Thermodynamics Lecture 10 : Phase Diagrams and Solubility Lecture 11 : Solubility (cont.) Lecture 12: Kinetic Coefficients for the Relaxation.
Notation convention Let G' stand for total free energy and in a similar fashion S', V', H', etc. Then we will let = G'/n represent the free energy per.
CHE 124: General Chemistry II
Daniel L. Reger Scott R. Goode David W. Ball Chapter 17 Chemical Thermodynamics.
Microstructure and Phase Transformations in Multicomponent Systems
Lecture 12: Phase diagrams PHYS 430/603 material Laszlo Takacs UMBC Department of Physics.
Chapter 20 Thermodynamics and Equilibrium. Overview First Law of Thermodynamics Spontaneous Processes and Entropy –Entropy and the Second Law of Thermodynamics.
Partial Molar Quantities and the Chemical Potential Lecture 6.
Lecture 6. NONELECTROLYTE SOLUTONS. NONELECTROLYTE SOLUTIONS SOLUTIONS – single phase homogeneous mixture of two or more components NONELECTROLYTES –
Solution properties Definitions –Solution –Solvent –Solute –Solubility –Saturated solution Concentration expression Matter – Solid, liquid, gas Vapor.
Chapter 13 – Solutions.
Rule of Solid Solubility. Positive deviation of the enthalpy of mixing and consequently limited solid solubility may be predicted from known atomic.
 Section 1 – Thermochemistry  Section 2 – Driving Force of Reactions.
June 16, 2009 – Class 43 and 44 Overview
Activity Coefficients; Equilibrium Constants Lecture 8.
Lecture 8 Stability and reactivity. We tend to say that substances are ‘stable’ or ‘unstable’, ‘reactive’ or ‘unreactive’ but these terms are relative.
CHEE 311J.S. Parent1 4. Chemical Potential in Mixtures When we add dn moles of a component to n moles of itself, we will observe (?) a change in Gibbs.
Peter Atkins • Julio de Paula Atkins’ Physical Chemistry
Energy & Heat Energy – ability to produce heat Heat - energy in the process of flowing from a warmer object to a cooler object. In chemical reactions.
Chapter 19 Lecture presentation
THERMOCHEMISTRY ENERGY CHANGES ASSOCIATED WITH CHEMICAL REACTION.
42C.1 Non-Ideal Solutions This development is patterned after that found in Molecular Themodynamics by D. A. McQuarrie and John D. Simon. Consider a molecular.
Affect of Variables on Recrystallization
Ideal and Dilute Solutions 2/21/2016. Master Thermodynamics Equations.
Thermodynamics Chemical-reaction Equilibria
Thermodynamics: Spontaneity, Entropy and Free Energy.
Phase Diagrams Chapter 9 4 th Edition Chapter 10 5 th Edition.
Lecture 4 Phase Diagram.
Classical Thermodynamics of Solutions
Chapter 12 Solutions. Solutions solute is the dissolved substance ◦ seems to “disappear” ◦ “takes on the state” of the solvent solvent is the substance.
Chemical Thermodynamics First Law of Thermodynamics You will recall from earlier this year that energy cannot be created nor destroyed. Therefore, the.
Chapter 19 Spontaneity, entropy and free energy (rev. 11/09/08)
Gibbs-Duhem and the Chemical Potential of Ideal Solutions
Topic Name : Solid solution
Mr. Kinton Honors Chemistry
Mr. Kinton Honors Chemistry
Lecture 49 More on Phase Transition, binary system
Practice Problem Would you expect the following molecules to dissolve better in water or hexane? Toluene Ethylene glycol Hexane water.
Grand Valley State University
Chapter 12 Solutions.
Reaction Kinetics and Equilibrium
Presentation transcript:

Binary Solutions LECTURE 2

BINARY SOLUTION Composition as a thermodynamic variables Gibbs free energy of binary solutions Entropy of formation and Gibbs free energy of an ideal solution Chemical potential of an ideal solution Regular solutions: Heat of formation of a solution Activity of a component, Henry’s and Raoult’s laws Real solutions: interstitial solid solutions, ordered phases, intermediate phases, compounds Equilibrium in heterogeneous systems

Solid Solutions (terminology) Solid solutions are made of a host (the solvent or matrix) which dissolves the minor component (solute). The ability to dissolve is called solubility. Solvent: in an alloy, the element or compound present in greater amount Solute: in an alloy, the element or compound present in lesser amount

Solid Solution: homogeneous maintains crystal structure contains randomly dispersed impurities (substitutional or interstitial) Second Phase: as solute atoms are added, new compounds /structures are formed, or solute forms local precipitates

Solubility Limit of a component in a phase is the maximum amount of the component that can be dissolved in it (e.g. alcohol has unlimited solubility in water, sugar has a limited solubility, oil is virtually insoluble). The same concepts apply to solid phases: Cu and Ni are mutually soluble in any amount (unlimited solid solubility), while C has a limited solubility in Fe. Whether the addition of impurities results in formation of solid solution or second phase depends on the nature of the impurities, their concentration and temperature, pressure…

Composition as a thermodynamic variable Real materials are almost always mixtures of different elements rather than pure substances: in addition to T and P, composition is also a variable. To understand conditions for equilibrium and phase diagrams (like the one in next slide) we have to understand how the Gibbs free energy of a given phase depends on composition, temperature and pressure. Since many real experiments are performed at fixed pressure of 1 atm, we will focus on G(T, composition).

Gibbs free energy of a binary solutions Let’s consider a binary solution of A and B atoms that have the same crystal structures in their pure states and can be mixed in any proportions - form a solid solution with the same crystal structure (unlimited solid solubility). Example: Cu and Ni. Consider 1 mol of homogeneous solid solution contains XA mol of A andXB mol of B. XA and XB are the mole fractions of A and B in the alloy. XA + XB =1

Let’s consider two steps of mixing: 1. Bring together XA mol of pure A and XB mol of pure B 2. Mix A and B to make a homogeneous solution After step 1 the free energy of the system is Gstep1 = XAGA + XBGB Before Mixing

Gibbs free energy per mole before mixing Variation of Gstep1 (free energy before mixing) with alloy composition (XA or XB)

After step 2 the free energy of the system is After mixing 1 mole of solid solution After step 2 the free energy of the system is G step2 = G step1 + ΔG mix ∆Gmix is the change of the Gibbs free energy caused by the mixing

∆Gmix =∆Hmix - T∆S mix ΔHmix = H step2 − H step1 - heat of mixing of the components (heat of formation of a solution) .It represent only the difference in internal energy (U) berfore and after mixing. ΔSmix= S step2− S step1 - difference in entropy between mixed and unmixed states (entropy of formation of a solution)

Ideal Solutions Let’s first consider an ideal solution – interactions between atoms A-A, B-B and A-B are identical, and ∆Hmix = 0. The free energy change upon mixing is only due to the change in configurational entropy:

ΔSmix = Sstep2 ΔGidmix = -TΔSmix ΔSmix = Sstep2 – Sstep1 Sstep1 = kB ln 1 = 0 there is only one way the atoms can be arranged before mixing Therefore ΔSmix = Sstep2

From statistical thermodynamics ΔSmix = -R[XAlnXA + XBlnXB] ΔGidmix = -TΔSmix = RT[XAlnXA + XBlnXB] For the total Gibbs free energy of an ideal solution: Gid = Gstep2 = G step1 + ΔGidmix ; Gstep1 = XAGA + XBGB Gid = XAGA + XBGB + RT[XAlnXA + XBlnXB]

Gibbs Free Energy of an ideal Solution For a nonideal solution we have to take into account heat of formation ΔHmix ΔGmix = ΔHmix - TΔSmix Gibbs Free Energy of an ideal Solution ΔGidmix = -TΔSmix =RT[XAlnXA + XBlnXB Gid = XAGA + XBGB + RT[XAlnXA + XBlnXB]

Free energy of mixing for an ideal solution (as a function of composition and temperature)

The actual free energy of the solution will depends on GA and GB as shown by the Fig. Decrease of GA and GB with T is due to the temperature dependence of the thermal entropy

Chemical potential of an ideal solution The chemical potential of the species i is given by Free energy change, when we add dni mol of i

For for a binary solution at constant P and T dG = μAdnA + μBdnB Addition of XA mol of atoms A and XB mol of atoms B ( i.e dnA/dnB = XA/XB) will increase the size of the system by 1 mol without changing composition and , therefore without changing μA and μB. The Gibbs free energy of an ideal solution will increase in this case by the molar Gibbs free energy G: G = μAXA + μBXB [J/mol]

Since XA + XB =1 , G = μA– (μB – μA)XB Therefore Also Gid = XAGA + XBGB + RT[XAlnXA + XBlnXB] Therefore , for an ideal solution μA = GA + RTlnXA μA and μB depend on the composition of the phase μB = GB + RTlnXB

hTI -RTlnXA

Regular solutions: Heat of formation of a solution (I) For a nonideal solution we have to take into account heat of formation ∆Hmix ≠ 0: ΔGmix =ΔHmix -TΔSmix ∆Hmix > 0 - mixing is endothermic (heat absorbed) ∆Hmix < 0 - mixing is exothermic (heat released)

Let’s account for the heat of formation ∆Hmix ≠ 0 using a simple model called statistical or quasi-chemical model. assumptions In this model the heat of mixing is only related to the bond energies between adjacent atoms. The assumption is that the interatomic distances and bond energies are independent of composition. 3 types of bonds: A – A bond (energy EAA) A – B bond (energy EAB) B – B bond (energy EBB)

If there are PAA, PBB, PAB bonds of each type, the internal energy of the solution is E = PAA.EAA + PBB.EBB + PAB.EAB Let’s calculate the internal energy of the solution: E = PAA.EAA + PBB.EBB + PAB.EAB If z is the coordination number of an atom in a crystal, then the number of atoms NA and NB are related to the number of bonds as:

NAz = 2PAA + PAB and NBz = 2PBB + PAB Using these expressions for PAA and PBB in the expression for energy, we have Energy of unmixed components

Therefore, the energy of mixing (heat of formation ∆Hmix) is The energy of mixing (heat of formation ∆Hmix) calculated within statistical or quasi-chemical model is

the solution is ideal: ∆Hmix = 0 ΔHmix >0 –atoms will tend to be surrounded by atoms of the same type ΔHmix < 0 –atoms will tend to be surrounded by atoms of the different type

But for small differences between EAB and (EAA+EBB)/2 (and for high T) we can still consider a random arrangement of atoms in a solution (such solutions are called regular solutions). Then PAB = zNtotXAXB And ∆Hmix = ΩXAXB

Regular solutions: Gibbs free energy ΔGmix = ΔHmix – TΔSmix = ΩXAXB + RT(XAlnXA + XBlnXB) For Ω < 0, ∆Hmix < 0 – exothermic solution – mixing is favorable at all T For high |Ω| and low T, PAB → max - an ordered alloy could be formed – the assumption of random mixing is not valid, solution is not regular, ∆Hmix ≠ ΩXAXB

For Ω > 0, ∆Hmix > 0 – mixing (formation of A-B pairs is avoided at low T. At high T entropy helps to mix. At low T clustering may occur – solution is not regular

Regular solutions: Gibbs free energy (II) ΔGmix = ΔHmix – TΔSmix = ΩXAXB + RT(XAlnXA + XBlnXB) Addition of a small amount of solute always leads to the decrease of ∆Gmix and G. Why?

G=XAGA +XBGB + ΩXAXB + RT[XAlnXA + XBlnXB] Or, using definition of chemical potential, G=μAXA + μBXB Where for regular solution μA = G A + Ω(1-XA)2 + RTlnXA μB = GB + Ω(1-XB)2 + RTlnXB Or we can introduce activities aA and aB of components A and B so that expressions for the chemical potentials would have the same form as for ideal solution: μA = G A + RTlnaA μB = G B + RTlnXB

For ideal solutions aA = XAand aB = XB. For regular solutions aA and aB are related to XA and XB by

Activity, Henry’s law, Raoult’s law For an ideal solution aA = XA and aB = XB. For a regular solution with ∆Hmix < 0 activity of the components is less than in an ideal solution, For ∆Hmix > 0 – higher than in an ideal solution.

The ratio aA/XA is called the activity coefficient γA of A. For a dilute solution of B in A (XB → 0) we have Henry;s Law Raoult’s Law Activity and chemical potential are measures of the tendency of an atom to leave a solution. If the activity or chemical potential is low, the atoms are reluctant to leave the solution.

Real solutions For regular solutions we assumed a random arrangement of atoms in a solution. For many real materials this is not a valid assumption. If Ω < 0 the internal energy is minimized by increasing the number of A-B bonds – can lead to ordered solution at low T if Ω > 0 the internal energy is minimized by increasing the number of A-A and B-B bonds – can lead to clustering at low T

The arrangement of atoms is a result of compromise between the lowest internal energy and highest entropy. Degree of clustering or ordering decreases with increasing T since the entropy contribution (-TS) to Gibbs free energy becomes more important.

If atoms A and B have different sizes, the statistical or quasichemical model will underestimate ∆Hmix. The energy of the elastic strain fields due to the mismatch in atomic sizes should be taken into account. If the size difference is large, the contribution of the strain energy term could as important as the chemical (bonding) term.

If the size difference between the atoms is very large, then interstitial solid solutions are energetically favorable. In systems with strong chemical bonding between the atoms there is a tendency for formation of intermediate phases. The intermediate phases can have a different crystal structure and may be highly ordered.

Substitutional Solid Solutions Max solute concentration = 50 at% e.g. Cu-Ni (unlimited solid solubility) Factors for high solubility: Atomic size factor - atoms need to “fit” ⇒ solute and solvent atomic radii should be within ~ 15% Crystal structures of solute and solvent should be the same Electronegativities of solute and solvent should be comparable (otherwise new intermediate phases are encouraged) Generally more solute goes into solution when it has higher valency than solvent

Interstitial Solid Solutions Normally, max. solute concentration ≤ 10% e.g. ≤ 0.1 at% of C in α-Fe (BCC). Factors for high solubility: For fcc, bcc, hcp structures the voids (or interstices) between the host atoms are relatively small ⇒ atomic radius of solute should be significantly less than solvent.

Intermediate phases The intermediate phases can have a crystal structure that is different from the one of the pure components, and an additional Gibbs free energy curve for the intermediate phase should be considered.

If an intermediate phase have a specific composition and small deviations from the ideal composition cause a rapid rise in G, the phase is called compound. Compounds typically have a stoichiometric composition (AnBm where n and m are integers). The structure of intermediate phases is determined by: Relative atomic size: RA/RB ~ 1.1-1.6 – Laves phases (e.g.MgZn2, MgNi2); RA >> RB – interstitial compounds, e.g. Fe3C Valency: stability of phases depends on the # of valence electrons per unit cell Electronegativity: different electronegativity of components leads charge transfer and formation of strong ionic bonding, e.g. Mg2+ + Sn4- = Mg2Sn

Equilibrium in Heterogeneous Systems Systems with two or more phases are heterogeneous systems. If pure components A and B have different equilibrium crystal structures, phase α and phase β, we have to consider two Gibbs free energy curves, one for each phase: Homogeneous α phase ? Homogeneous β phase

For compositions near cross-over of Gα and Gβ, the total Gibbs free energy can be minimized by separation into two phases. Let’s consider a systems with two phases α and β, that have compositions XαB and XβB and Gibbs free energies Gα and Gβ. If the average composition of the system is X0B, the molar free energy Gα+β is given by the point on a straight line that connects Gα and Gβ, and the relative number of moles of phases α and β can be found by the lever rule: Mα = (XβB – XoB)/(XβB – XαB) Mβ = (XoB – XαB)/(XβB – XαB)

L1 = Gα ; L4 = Gβ L3 = MαGα L2 = MβGβ Molar free energy of the phase mixture with molar fractions of phases α and β, Mα and Mβ L3 + L2 = MαGα + MβGβ = Gα+β

For composition XB 0 the lowest Gibbs free energy is Gα0 for a homogeneous system. The total Gibbs free energy can be additionally decreased by separation into two phases, for example with compositions and XBα1 and XBβ1.

The total Gibbs free energy is at minimum if phases α and β have compositions XBαeq and XBβeq These are the equilibrium compositions of the phases In equilibrium tangents to Gα and Gβ curves are the same (lie on a common line). Therefore, the condition for heterogeneous equilibrium is equity of the chemical potentials and activities of each component in the two phases.

μB = GB + RTlnaB μA = GA + RTlnaA