Aim: How can we determine acceleration on a distance-time graph? Do Now: Determine the displacement of the following graph:

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Presentation transcript:

Aim: How can we determine acceleration on a distance-time graph? Do Now: Determine the displacement of the following graph:

d = bh = (5 s)(5 m/s) = 25 m d = ½bh = ½(2 s)(5 m/s) = 5 m d = ½bh = ½ (2 s)(-5 m/s) = -5 m d = bh = (2 s)(-5 m/s) = -10 m Total displacement = 15 m

Describe the motion on the following distance-time graph: A B C D Constant positive slope = constant velocity forward Curved line = changing slope = acceleration Positive slope = forward =accelerating foward Constant positive slope = constant velocity forward

Is the object speeding up or slowing down? Determine if the slope is increasing or decreasing A B C D Slope 1 Slope 2 Slope 2 is less steep than slope 1 This means that slope 2 is moving with a slower velocity In other words, the object is slowing down Since the slope is still positive, the object is mowing forward Slowing down forward

Slope 1 Slope 2 Slope 2 is steeper than slope 1 Both slopes are positive Speeding up forward Slope 1 Slope 2 Slope 2 is steeper than slope 1 Both slopes are negative Speeding up backward

Slope 1 Slope 2 Slope 2 is less steep than slope 1 Both slopes are negative Slowing down backward

Describe the motion on the following distance-time graph: distance time AB C D EF G H IJ

__ AB: At rest __ BC: Speeding up forward __ CD: Constant velocity forward __ DE: Slowing down forward __ EF: At rest __ FG: Speeding up backward __ GH: Constant velocity backward __ HI: Slowing down backward __ IJ: At rest

Instantaneous Velocity This is velocity at a specific moment in time On a distance-time graph: Find the slope of the line on the graph using points one second before and one second after the time indicated Find the instantaneous velocity at 14 seconds If you just went 100m/14s, you would get an incorrect answer!

On a velocity-time graph Just read the graph What is the instantaneous velocity at: 1 s 5 m/s 3 s 5 m/s 5 s 10 m/s