Kinematics Equations.

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Presentation transcript:

Kinematics Equations

IB Motion Graph Review

Distance/Position/Displacement Time Graphs Constant vel. Starting point Slope = Velocity Slower Velocity

Positive Negative Quadrants Where object is w/ref to starting point.

What is the object’s: a. displacement distance 10 30

Constant Velocity/Speed

Constant / Uniform Acceleration. On velocity time graph accl Constant / Uniform Acceleration. On velocity time graph accl. is slope of straight line. + or neg a shown?

What’s going on here physically?

Sign of velocity is direction of motion shown by the quadrant. What does this show?

What does -v mean?

What does the sign of slope mean?

Displacement = Area Under Curve v = d/t then, vt = d.

To find displacement, calc area of triangle + rectangle.

When is object back at start point? + area must = - area

Acceleration – time graphs Graph d-t, v-t, a-t tossed ball & caught at same height.

Kerr pg 39 #1 & pg 71 Topic 2.1 #1-4.