The physics of parasailing

Slides:



Advertisements
Similar presentations
Work Done by a Constant Force
Advertisements

Dr. Steve Peterson Physics 1025F Mechanics NEWTON’S LAWS Dr. Steve Peterson
General Physics I: Day 9 Equilibrium & Dynamics
L-6 – Newton's Second Law Objects have a property called inertia which causes them to resist changes in their motion (Newton’s1st Law or Galileo’s law.
PHYS 218 sec Review Chap. 4 Newton’s laws of motion.
Do Now: 1. Draw a free body diagram (all the forces) acting on a water skier being pulled by a boat. 2. What is the net force acting on this object?
Lecture 14 Monday, September 29 Using Newton’s Laws.
Page 1 Dr. Gareth J. Bennett Trinity College Dublin Assignment 2 - Add Drag! Mangonel Dynamics Design Tool using Excel Up until now we have assumed constant.
Newton’s 2 nd Law Of Motion By Mr. Yum. Newton’s 2 nd Law Newton’s 2 nd Law is defined as: Newton’s 2 nd Law is defined as: F = m x a Where, F = force,
Dynamics Why and how an object moves? Newton’s Laws.
Circular Motion and Other Applications of Newton’s Laws
Forces. Forces Forces - LOs (a) Solve problems using the relationship: net force = mass x acceleration (F = ma) appreciating that acceleration and.
Paper Airplanes Rachael Lee (15). Why? Why are the airplanes able to fly after the initial thrust we gave them? How are they able to glide for so long.
Physics Chapter 4: Forces and the Laws of Motion
 Calculate the acceleration that this object experiences 30 kg 150 N.
Vectors This is one of the most important chapters in the course. PowerPoint presentations are compiled from Walker 3 rd Edition Instructor CD-ROM and.
MAE 242 Dynamics – Section I Dr. Kostas Sierros. Problem.
Today’s Objectives: Students will be able to:
Chapter 4 Dynamics: Newton’s Laws of Motion
Mathematical Modeling and Engineering Problem Solving
Chapter 6 Circular Motion and Other Applications of Newton’s Laws.
Equation of Motion for a Particle Sect nd Law (time independent mass): F = (dp/dt) = [d(mv)/dt] = m(dv/dt) = ma = m(d 2 r/dt 2 ) = m r (1) A 2.
 Extension of Circular Motion & Newton’s Laws Chapter 6 Mrs. Warren Kings High School.
L-6 – Newton's Second Law Objects have a property called inertia which causes them to resist changes in their motion (Newton’s1 st Law or Galileo’s law.
Fu = ma NOTES p.19 DYNAMICS Recall that mass (kg) acceleration (m/s2)
Topic 6: Fields and Forces 6.1 Gravitational force and field.
Topic 6: Fields and Forces 6.1 Gravitational force and field.
Wednesday, June 7, 2006PHYS , Summer 2006 Dr. Jaehoon Yu 1 PHYS 1443 – Section 001 Lecture #6 Wednesday, June 7, 2006 Dr. Jaehoon Yu Application.
Newton’s Second Law of Motion Force & Acceleration Larger the net force, greater the acceleration Double the Force Triple the Force Half the Force implies.
Terminal Velocity Predicting the rate an object will fall through air depending on mass, cross sectional area and other factors.
Monday, Oct. 8, 2007 PHYS , Fall 2007 Dr. Jaehoon Yu 1 PHYS 1443 – Section 002 Lecture #10 Monday, Oct. 8, 2007 Dr. Jaehoon Yu Uniform and Non-uniform.
Chapter 5 The Laws of Motion.
REVISION NEWTON’S LAW. Quantity with magnitude and direction. e.g. displacement, velocity, acceleration, force and weight.. VECTOR Quantity having only.
Speeding up and slowing down f = ma Terminal velocity.
Chapter 2 - Sections 3 & 4 Newton’s Laws of Motion and Momentum.
Newton’s Second Law of Motion. 2 nd Law of Motion  The net (total) force of an object is equal to the product of its acceleration and its mass.  Force.
Wednesday, Sept. 24, 2003PHYS , Fall 2003 Dr. Jaehoon Yu 1 PHYS 1443 – Section 003 Lecture #9 Forces of Friction Uniform and Non-uniform Circular.
Law of Gravitation. Law of Gravity  Gravitational Force  All objects have mass and therefore will attract all other objects.  The size of the gravitational.
Today: (Ch. 3) Tomorrow: (Ch. 4) Apparent weight Friction Free Fall Air Drag and Terminal Velocity Forces and Motion in Two and Three Dimensions.
1 The law of gravitation can be written in a vector notation (9.1) Although this law applies strictly to particles, it can be also used to real bodies.
Today: (Ch. 8)  Rotational Motion.
Forces and Newton’s Laws of Motion. 4N Sketch a labelled vector diagram to show the net force being applied to the box. 10N 2N 3N Box Starter.
Formula Momentum (p) = Mass x velocity Unit is kgm/s.
Objectives: Write the equation of motion for an accelerating body.
Key Areas covered Balanced and unbalanced forces. The effects of friction. Terminal velocity. Forces acting in one plane only. Analysis of motion using.
Chapter 5 Applications of Newton’s Law
By: Amanda Hui & Jessica Lu
Force & Acceleration Motion & Forces Newton’s Second Law Gravity
DAY 19 LETS GO! THE END OF THE QUARTER Topic 3 Forces continues
Work Done by a Constant Force
NEWTON’S LAWS OF MOTION, EQUATIONS OF MOTION, & EQUATIONS OF MOTION FOR A SYSTEM OF PARTICLES
Universal Gravitation
Universal Gravitation
Newton’s First and Second Laws
Forces and Free Body Diagrams (FBD)
PHYS 1443 – Section 501 Lecture #15
Kinetics of a particle.
Newton’s Second Law “ Forces do not cause motion. Forces cause accelerations”
Some definitions: Weight vs mass
Newton’s 2nd Law of Motion
Key Areas covered Balanced and unbalanced forces. The effects of friction. Terminal velocity. Forces acting in one plane only. Analysis of motion using.
Newton’s Second Law If all forces are in balance, object is at equilibrium and does accelerate Newton’s second law applies when forces are unbalanced;
Momentum Momentum (p) of an object = product of its mass (m) and its velocity (v) p = m × v The unit for momentum is kg·m/s.
Introduction to Aeronautical Engineering
PHYS 1443 – Section 002 Lecture #10
Newton’s Laws of Motion
Newton’s first and Second Laws
Devil physics The baddest class on campus IB Physics Pre-IB Physics
Bottle Rocket Calculations
Bottle Rocket Calculations
Presentation transcript:

The physics of parasailing Dr Andrew French. August 2013

What is parasailing? Parasailing (or parascending, parakiting) is an activity whereby a passenger is lofted into the air via a modified parachute (called a parasail wing) towed by a motorized vehicle. For safety reasons, recreational parasailing is typically offered as a watersport. History 1961 Pierre-Marcel Lemoigne develops the first ascending-gliding parachute as a training tool for parachutists. Cheaper than using an aeroplane! 1974 Mark McCulloh invents the basic parasail launch and recovery system (“Winchboat”) via a cable winch system. This setup is the basis of modern commercial operations. 1976 Brian Gaskin created the ‘16-gore’ waterproof canopy design (“Waterbird”) and passenger harness. 1990s+ Much larger canopies designed with higher lift : drag ratios. Multiple passenger rides are now possible. http://www.parasail.org/ http://en.wikipedia.org/wiki/Parasailing

A mathematical model of parasailing Once the tow cable has been deployed, the cable and parachute cord angles are observed to be constant for a given boat velocity. One shall therefore consider the entire system to be in dynamic equilibrium i.e. there is no net force or consequential acceleration. Physical parameters Lift experienced by parachute /N Gravitational field strength 9.81ms-2 Drag experienced by passenger /N Velocity of tow boat /ms-1 Overall tension in parachute cables /N Tension in tow cable /N Mass of parachute /kg Mass of passenger + harness /kg Drag experienced by parachute /N

Let us apply Newton’s second law in x and y directions to the passenger and the parachute Passenger x [1] y [2] Parachute This is the potentially dodgy bit of the analysis! The drag and lift forces will change with angle of attack. However, in the absence of a data sheet we have got to start somewhere! As a first approximation set drag and lift coefficients c2 and cL to be constants. i.e. independent of angle q + f x [3] y [4] Let us parameterize the lift and drag forces as follows. Drag coefficients Cross sectional area of passenger Radius of parachute Lift coefficient Density of air

Passenger x [1] y [2] [2]/[1] Parachute [3] x [4] y Hence or

Now [1] [4]/[3] [2] [3] [4] We can now work out the tensions

Now since q must be positive Also since v must be a real quantity Hence

v = 0 .... 5ms-1 (Note 1ms-1 = 1.944 knots) q = 30o ..... 70o In summary: Some typical values ..... v = 0 .... 5ms-1 (Note 1ms-1 = 1.944 knots) q = 30o ..... 70o r = 1kgm-3 R = 4m M = 80kg m = 10kg c1 = 1 c2 = 1 cL = 10 Very much a guess!

Reference data: Drag coefficient These results indicate I may have been too conservative in setting the parasail drag coefficient to be 1. Perhaps c2 = 0.4 and cL = 4 would be more appropriate (while keeping the lift : drag ratio as ten). Further information is needed! http://en.wikipedia.org/wiki/Drag_coefficient

Reference data: Lift to drag ratio http://en.wikipedia.org/wiki/Lift-to-drag_ratio