Calculations Involving Acids and Bases IB Chemistry Power Points Topic 18 Acids and Bases
K w : the ionic product constant of water 2 H 2 O H 3 O + + OH - H 2 O H + + OH - (simplified)
K w : depends on temperature T (°C)K w (mol 2 dm -6 )pH x x x x x x x x Pure water is always neutral i.e. [H + ] = [OH - ] This means the pH value that is “neutral” i.e. [H + ] = [OH - ] changes with temperature
The K w value for pure water at 60 o C is × Calculate the concentration of hydroxide ions and the pH of pure water at this temperature.
about pOH pOH = -log [OH - ] just like pH, pOH is a measure of concentration pH + pOH = pK w this means that at 25 o pH + pOH = 14 unless otherwise stated (or a temperature different than 25 o is given), this relationship applies to all pH problems For example: what is the [OH - ] for a solution with pH 8.2 measured at 25 o C?
Weak acids and weak bases – reactions with water summary ethanoic acid:CH 3 COOH + H 2 O CH 3 COO - + H 3 O + ammonia:NH 3 + H 2 O NH OH -
Practice Calculate the pH of a) a 0.75 M solution of ethanoic acid b)a 0.75 M solution of ammonia
Consider the following simplified equation for the reaction of ethanoic acid in water CH 3 COOH CH 3 COO - + H + Now write the equation for the reaction of the conjugate base with water: CH 3 COO - + H 2 O CH 3 COOH + OH - The equilibrium expression for the reaction of the acid is: The equilibrium expression for the reaction of the conjugate base is:
Now write an expression for K a x K b
ethanoic acid CH 3 COOH K a = × pK a = methanoic acid HCOOH K a = × pK a = Consider 2 weak acids and 2 weak bases ammonia NH 3 K b = × pK b = methylamine CH 3 NH 2 K b = × pK b = conclusions?
More neat stuff. CH 3 COO - is a weak base with a K b value of 5.75 × CH 3 COO - is the conjugate base of the weak acid CH 3 COOH (K a value × ). What do you notice about the pK values of this acid - conjugate base pair? for acid/conjugate base pairs & conjugate acid/base pairs pK a + pK b = pK w in addition, for a solution pH + pOH = pK w