2-1 Thermodynamics and kinetics Thermodynamic laws Half-cell reactions Kinetics Acid-Base Equilibrium calculations §Speciation calculation from complexation.

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Presentation transcript:

2-1 Thermodynamics and kinetics Thermodynamic laws Half-cell reactions Kinetics Acid-Base Equilibrium calculations §Speciation calculation from complexation constants Provide review of concepts for applications to radiochemistry

2-2 Thermodynamic terms Heat Capacity (C p ) §Heat required to raise one gram of substance 1 °C §Al; C p = J/gK à1 cal = J §What is the heat needed to increase 40 g of Al by 10 K §(0.895 J/gK)(40g)(10K)= 358 J Exothermic §Reaction produces heat (at 25 °C) C(s) + O 2 (g) CO 2 (g) kJ

2-3 Thermodynamic terms Endothermic §Reaction requires energy (at 25 °C) 2 HgO kJ 2 Hg + O 2 Enthalpy (∆H) Energy of a system (heat content) §Internal energy, volume, pressure §Accounts for energy transferred to environment by expansion or heating ∆H = ∆H products - ∆H reactants Exothermic reactions, negative ∆H §Negative ∆H tend to be spontaneous

2-4 Enthalpy (∆H) Bond energies §Can be used to estimate ∆H §N H 2 2 NH 3 §6(351.5) (436.0) = kJ/2 mole =-72.3 kJ/mole (actual kJ/mol) Aqueous Ions (use ∆H values, databases available for different states) §∆H products - ∆H reactants à2 H + + CO 3 2- CO 2 + H 2 O à (-285.8)-( (0)) = -2.2 kJ/mol CO 2(g) H 2 O (l) CO 3 2- H+H+

2-5 ∆H determination  C p is the sum of the heat capacities Standard Solution Ag AgCl Ag(NH 3 ) Ag(S 2 O 3 ) Al Br BrO Ca Cd Cd(CN) Cd(NH 3 ) Ce Ce CH 3 COO CH 3 COOH CN CNS Cl ClO CO CO H+0 H 2 O I I IO K NH NH NO Na OH O SO Sn Sr Tl U UO Pure substance CaC 2 O 4 (c) CaF 2 (c) Ca 3 (PO 4 ) 2 (c) CaSO4(c,anhydrite) Cd(g) Cd 2+ (g) Cd(OH) 2 (c) CdS(c) Cl(g) Cl-(g) ClO 2 (g)102.5 Cu(g) Cu 2 O(c,cuprite) CuO(c,tenorite) Cu(OH) 2 (c) Cu2S(c,chalcocite)-79.5 CuS(c,covellite)-53.1 F(g)78.99 F-(g) Fe(g)416.3

2-6 Entropy (∆S) and Gibbs Free Energy (∆G) Randomness of a system §increase in ∆S tends to be spontaneous Enthalpy and Entropy can be used for evaluating the free energy of a system Gibbs Free Energy §∆G = ∆H -T∆S §∆G=-RTlnK àK is equilibrium constant àActivity at unity Compound∆G° (kJ/mol) at K H 2 O OH - (aq) H + (aq) 0 H 2 O  H + +OH - §What is the constant for the reaction? àProducts-reactants At K ∆G(rxn) = ( ) = 79.9 kJ/mol lnK= (79.9E3/(-8.314*298.15))=-32.2; K=1E-14, K w = [H + ][OH - ]

2-7 Thermodynamic Laws 1st law of thermodynamics §Energy is conserved in a system àCan be changed or transferred §Heat and work are energy transfer à∆E = q (heat absorbed) + w (work) 2nd law of thermodynamics §Reactions tend towards equilibrium àIncrease in entropy of a system §Spontaneous reaction for -∆G à∆G = 0, system at equilibrium 3rd law of thermodynamics §Entropies of pure crystalline solids are zero at 0 K §Defines absolute zero

2-8 Redox Reactions: Faraday Laws In 1834 Faraday demonstrated quantities of chemicals which react at electrodes are directly proportional to charge passed through the cell §96487 Coulomb (C) is the charge on 1 mole of electrons = 1F (faraday) Cu(II) is electrolyzed by a current of 10 A (C/s) for 1 hr between Cu electrode §How much Cu reacts anode: Cu Cu e - cathode: Cu e - Cu §Number of electrons à2 from redox reaction *(10A)(3600 sec)/(96487 C/mol) = F *0.373 mole e - (1 mole Cu/2 mole e - ) = mole Cu

2-9 Half-cell potentials Standard potential  Defined as  °=0.00 V for àH 2 (atm) 2 H + (1.000M) + 2e - Other reactions compared to H 2 Cell reaction for §Zn and Fe 3+/2+ at 1.0 M §Write as reduction potentials  Fe 3+ + e - Fe 2+  °=0.77 V  Zn e - Zn  °=-0.76 V *Reduction potentials are available e.htm e.htm Reduction potential for Fe 3+ is larger §Fe 3+ is reduced, Zn is oxidized in reaction

2-10 Half-Cell Potentials Overall balanced equation  2Fe 3+ +Zn 2Fe 2+ + Zn 2+  °= =1.53 V Use standard reduction potential Half cell potential values are not multiplied   ° is for a mole of electrons Application of Gibbs Free Energy If work is done by a system  ∆G = -  °nF (n= e - ) Find ∆G for Zn/Cu cell at 1.0 M  Cu 2+ + Zn Cu + Zn 2+   °=1.10 V §2 moles of electrons (n=2) à∆G =-2(96487C/mole e - )(1.10V) à∆G = -212 kJ/mol

2-11 Nernst Equation Compensated for non unit activity (not 1 M) Relationship between cell potential and activities aA + bB +ne - cC + dD At 298K 2.3RT/F = What is potential of an electrode of Zn(s) and 0.01 M Zn 2+ Zn 2+ +2e - Zn  °= V activity of metal is 1

2-12 Kinetics and Equilibrium Kinetics and equilibrium important concepts in examining and describing chemistry §Identify factors which determine rates of reactions àTemperature, pressure, reactants, mixing §Describe how to control reactions §Explain why reactions fail to go to completion §Identify conditions which prevail at equilibrium Rate of reaction §Can depend upon conditions Free energy does not dictate kinetics §Thermodynamics can be decoupled from kinetics Thermodynamics concerned with difference between initial and final state Kinetics account for reaction rates and describe the conditions and mechanisms of reactions §difficult to describe from first principles General factors effecting kinetics §Nature of reactants §Effective concentrations §Temperature §Presence of catalysts §Number of steps

2-13 Nature of Reactants Ions react rapidly §Ag + + Cl - AgCl(s) Very fast Reactions which involve bond breaking are slower §NH OCN - OC(NH 2 ) 2 Redox reactions in solutions are slow §Transfer of electrons are faster than those of atomic transfer Reactions between covalently bonded molecules are slow §2 HI(g) H 2 (g) + I 2 (g) Structure §Phosphorus (white and red) Surface area §larger surface area increases reaction Mixing increases interaction

2-14 Rate Law Concentration of reactant or product per unit time Effect of initial concentration on rate can be examined §rate = k[A] x [B] y §rate order = x + y §knowledge of order can help control reaction §rate must be experimentally determined Rate=k[A] n ; A=conc. at time t, A o =initial conc., X=product conc. Orderrate equationk 0[A 0 ]-[A]=kt, [X]=ktmole/L sec 1 ln[A 0 ]-ln[A]=kt, ln[A 0 ]-ln([A o ]-[X])=kt 1/sec 2L/mole sec 3 L 2 /mole 2 sec

2-15 Rate Law Temperature §Reactions tend to double for every 10 °C Catalysts §Accelerate reaction but are not used àPt surface §Thermodynamically drive, catalysts drive kinetics §If not thermodynamically favored, catalysts will not drive reaction Autocatalytic reactions form products which act as catalysts

2-16 Complexation Kinetics Uranium and cobalt with pyridine based ligands 111Py12111Py14 222Py14 Examine complexation by UV- Visible spectroscopy Absorbance sum from 250 nm to 325 nm for 111Py12 and uranium at pH 4

2-17 Kinetic Data Evaluation Evaluation of absorbance and kinetic data for 111Py12 and 111Py14 with uranium at pH 4. The concentration of ligand and uranium is 50x10 -6 mol/L. LigandAbs o ∆Abs eq k (min -1 )95% Equilibrium Time (min) 111Py127.86± ± ±0.47x ±0.65x Py144.82± ± ±0.80x ±1.33x10 4 Evaluation of change in absorbance

2-18 Acid-Base Equilibria Brønsted Theory of Acids and Bases §Acid àSubstance which donates a proton §Base àAccepts proton from another substance NH 3 + HCl NH Cl - H 2 O + HCl H 3 O + + Cl - NH 3 + H 2 O NH OH - Remainder of acid is base Complete reaction is proton exchange between sets Extent of exchange based on strength Water can act as solvent and reactant

2-19 Dissociation Constants Equilibrium expression for the behavior of acid HA + H 2 O A - + H 3 O + Water concentration is constant pK a =-logK a Can also be measured for base Constants are characteristic of the particular acid or base AcidFormulaK a AceticHC 2 H 3 O 2 1.8E-5 CarbonicH 2 CO 3 3.5E-7 HCO 3 - 5E-11 PhosphoricH 3 PO 4 7.5E-3 H 2 PO E-8 HPO E-13 OxalicH 2 C 2 O 4 5.9E-2 HC 2 O E-5

2-20 Calculations 1 L of 0.1 M acetic acid has pH = 2.87 What is the pK a for acetic acid CH 3 COOH + H 2 O CH 3 COO - + H 3 O + [CH 3 COO - ] = [H 3 O + ] = pK a =4.73

2-21 Buffers: Weak acids and bases Weak acid or weak base with conjugate salt Acetate as example §Acetic acid, CH 3 COONa §CH 3 COOH + H 2 O CH 3 COO - + H 3 O + §If acid is added àhydronium reacts with acetate ion, forming undissociated acetic acid §If base is added àHydroxide reacts with hydronium, acetic acid dissociates to replace reacted hydronium ion large quantityhuge quantitylarge quantitysmall quantity

2-22 Buffer Solutions Buffers can be made over a large pH range Can be useful in controlling reactions and separations §Buffer range àEffective range of buffer àDetermined by pK a of acid or pK b of base HA + H 2 O A - + H 3 O - Write as pH The best buffer is when [HA]=[A - ] §largest buffer range for the conditions §pH = pK a - log1 For a buffer the range is determined by [HA]/[A - ] §[HA]/[A - ] from 0.1 to 10 §Buffer pH range = pK a ± 1 §Higher buffer concentration increase durability

2-23 Hydrolysis Constants Reaction of water with metal ion §Common reaction §Environmentally important §Strength dependent upon metal ion oxidation state 2 H 2 O H 3 O + + OH - §Water concentration remains constant, so for water: §K w = [H 3 O + ][OH - ]= 1E-14 at 25°C Metal ions can form hydroxide complexes with water M z+ + H 2 O MOH z-1+ + H + Constants are listed for many metal ion with different hydroxide amounts §Database at: