30S Applied Math Mr. Knight – Killarney School Slide 1 Unit: Systems of Linear Equations Lesson: SLE-L1 Intro to Systems of Linear Equations Find x 3(x.

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Presentation transcript:

30S Applied Math Mr. Knight – Killarney School Slide 1 Unit: Systems of Linear Equations Lesson: SLE-L1 Intro to Systems of Linear Equations Find x 3(x - 2) = 2x + 3(x + 5) - 1 Learning Outcome B-1 SLE-L1 Objectives: Review techniques used to solve simple equations

30S Applied Math Mr. Knight – Killarney School Slide 2 Unit: Systems of Linear Equations Lesson: SLE-L1 To solve an equation 2x - 4 = 8 means to find the value for the variable in the equation that will make both sides of the equation equal. In this case, x = 6 would make the left side and the right side of the equation balance, thus creating a true statement. Left SideRight Side 2(6) – 4 =8 12 – 4 =8 8 =8 (True) Theory – Solving an Equation

30S Applied Math Mr. Knight – Killarney School Slide 3 Unit: Systems of Linear Equations Lesson: SLE-L1 What’s the First Step? 3x + 4 = 7 Solve. Theory – Solving an Equation Algebraically

30S Applied Math Mr. Knight – Killarney School Slide 4 Unit: Systems of Linear Equations Lesson: SLE-L1 What’s the First Step? 2(5x – 4) = 7(x – 2) Solve. Theory – Solving an Equation Algebraically

30S Applied Math Mr. Knight – Killarney School Slide 5 Unit: Systems of Linear Equations Lesson: SLE-L1 What’s the First Step? Solve. Theory – Solving an Equation Algebraically

30S Applied Math Mr. Knight – Killarney School Slide 6 Unit: Systems of Linear Equations Lesson: SLE-L1 What’s the First Step? Solve. Theory – Solving an Equation Algebraically

30S Applied Math Mr. Knight – Killarney School Slide 7 Unit: Systems of Linear Equations Lesson: SLE-L1 What’s the First Step? 3(x - 2) = 2x + 3(x + 5) - 1 Solve. Theory – Solving an Equation Algebraically