Chapter 11 AC Steady-State Power

Slides:



Advertisements
Similar presentations
Since Therefore Since.
Advertisements

Each of the circuit elements will have a different ac current response to an applied ac voltage. We need to look at each of these elements. Resistor:
Chapter 12 RL Circuits.
We have been using voltage sources that send out a current in a single direction called direct current (dc). Current does not have to flow continuously.
Sinusoidal Steady-State Power Calculations
CH5 AC circuit power analysis 5.1 Instantaneous Power 5.2 Average Power 5.3 Effectives values of Current & Voltage 5.4 Apparent Power and Power Factor.
Alternating Current Circuits
AC Review Discussion D12.2. Passive Circuit Elements i i i + -
R,L, and C Elements and the Impedance Concept
Copyright © 2013 The McGraw-Hill Companies, Inc. Permission required for reproduction or display. 1 Chapter 11 AC Circuit Power Analysis.
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004 OHT 16.1 Power in AC Circuits  Introduction  Power in Resistive Components 
AC POWER ANALYSIS Tunku Muhammad Nizar Bin Tunku Mansur
Chapter 7 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
ECE 3183 – Chapter 5 – Part D CHAPTER 5 - D1 ECE 3183 – EE Systems Chapter 5 – Part D AC Power, Power Factor.
ENGR-43_Lec-09-2_Complex_Power.ppt 1 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Bruce Mayer, PE Registered Electrical.
Circuits II EE221 Unit 4 Instructor: Kevin D. Donohue Complex Power, Power Conservation, Power Factor Correction, and Applications.
AC POWER ANALYSIS Tunku Muhammad Nizar Bin Tunku Mansur
Alexander-Sadiku Fundamentals of Electric Circuits
Fundamentals of Electric Circuits Chapter 11
Lecture 27 Review Phasor voltage-current relations for circuit elements Impedance and admittance Steady-state sinusoidal analysis Examples Related educational.
Chapter 22 Alternating-Current Circuits and Machines.
Chapter 10 Sinusoidal Steady-State Analysis
ES250: Electrical Science
Chapter 11 AC Power Analysis
ARRDEKTA INSTITUTE OF TECHNOLOGY GUIDED BY GUIDED BY Prof. R.H.Chaudhary Prof. R.H.Chaudhary Asst.prof in electrical Asst.prof in electrical Department.
Alternating Current Circuits
Alternating Current Circuits
Fundamentals of Electric Circuits Chapter 11
Sinusoidal Steady-state Analysis Complex number reviews Phasors and ordinary differential equations Complete response and sinusoidal steady-state response.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc. Lecture 16 Phasor Circuits, AC.
1 Chapter 11 AC Power Analysis 電路學 ( 二 ). 2 AC Power Analysis Chapter Instantaneous and Average Power 11.2Maximum Average Power Transfer 11.3Effective.
EGR 2201 Unit 13 AC Power Analysis
Review Part 3 of Course. Passive Circuit Elements i i i + -
AC POWER ANALYSIS Instantaneous & Average Power
INC 111 Basic Circuit Analysis
Chapter 7 AC Power Analysis
Circuits II EE221 Unit 11 Instructor: Kevin D. Donohue Complex Power, Power Conservation, Power Factor Correction, and Applications.
1 Alternating Current Circuits Chapter Inductance CapacitorResistor.
The V  I Relationship for a Resistor Let the current through the resistor be a sinusoidal given as Is also sinusoidal with amplitude amplitudeAnd.
Chapter 11 AC Power Analysis
1 Lecture #9 EGR 272 – Circuit Theory II Read: Chapter 10 in Electric Circuits, 6 th Edition by Nilsson Chapter 10 - Power Calculations in AC Circuits.
1 ELECTRICAL TECHNOLOGY ET 201  Define series impedances and analyze series AC circuits using circuit techniques.
1 ELECTRICAL TECHNOLOGY EET 103/4  Define and explain sine wave, frequency, amplitude, phase angle, complex number  Define, analyze and calculate impedance,
Chapter 10 Sinusoidal Steady- State Power Calculations
Chapter 31 Lecture 33: Alternating Current Circuits: II HW 11 (problems): 30.58, 30.65, 30.76, 31.12, 31.26, 31.46, 31.56, Due Friday, Dec 11. Final.
Chapter 8 Alternating Current Circuits. AC Circuit An AC circuit consists of a combination of circuit elements and an AC generator or source An AC circuit.
AC POWER ANALYSIS. 2 Content Average Power Maximum Average Power Transfer Complex Power Power Factor Correction.
CHAPTER 2: DC Circuit Analysis and AC Circuit Analysis Motivation Sinusoids’ features Phasors Phasor relationships for circuit elements Impedance and admittance.
1 Eeng 224 Chapter 11 AC Power Analysis Huseyin Bilgekul Eeng224 Circuit Theory II Department of Electrical and Electronic Engineering Eastern Mediterranean.
FUNDAMENTAL OF ELECTRICAL POWER SYSTEMS (EE 270)
Chapter 10 RC Circuits.
RC Circuits (sine wave)
1 Chapter 3 AC Power Analysis. 2 AC Power Analysis Chapter 3 3.1Instantaneous and Average Power 3.2Maximum Average Power Transfer 3.3Effective or RMS.
Chapter 13 The Basic Elements and Phasors. Objectives Be able to add and subtract sinusoidal voltages or currents Use phasor format to add and subtract.
Chapter 12 RL Circuits.
Electric Circuits (EELE 2312)
Lecture 07 AC POWER & POWER FACTOR.
Sinusoidal Excitation of Circuits
Network Circuit Analysis
Islamic University of Gaza
STEADY-STATE POWER ANALYSIS
site.iugaza.edu.ps/ajasser
ELECTRIC CIRCUITS EIGHTH EDITION
2. 2 The V-I Relationship for a Resistor Let the current through the resistor be a sinusoidal given as Is also sinusoidal with amplitude amplitude.
ELL100: INTRODUCTION TO ELECTRICAL ENGG.
Chapter 11 – Power AC Circuits
EE202 – Circuit Theory II , Spring
The instantaneous power
Chapter 11 – Power AC Circuits
Engineering Circuit Analysis
Presentation transcript:

Chapter 11 AC Steady-State Power

Matching Network for Maximum Power Transfer Cellular Telephone Design the matching network to transfer maximum power to the load where the load is the model of an antenna of a wireless communication system.

The greatest engineer of his day, George Westinghouse modernized the railroad industry and established the electric power system. Nikola Tesla, 1856-1943 Tesla was responsible for many inventions, including the ac induction motor, and was a contributor to the selection of 60Hz as the standards ac frequency in the United States.

Instantaneous Power and Average Power A circuit element If v(t) is a periodic function Then for a linear circuit i(t) is also a periodic function

Instantaneous Power and Average Power(cont.) Arbitrary point in time If v(t) is a sinusoidal function For a linear circuit i(t) is also a sinusoidal function

average value of the cosine function over a complete period is zero

Example 11.3-1 P = ? Using the period from t = 0 to t = T i(t) through a resistor R The instantaneous power is The average power is

Example 11.3-2 PL = ? PR = ? The element voltages are The average power delivered by the voltage source is The average power delivered to the voltage source is

Example 11.3-2 (cont.) The average power delivered to the resistor is The average power delivered to the inductor is WHY the average power delivered to the inductor = 0 ? The angle of vL always be larger than the angle of iL and

Effective Value of a Periodic Waveform The goal is to find a dc voltage, Veff (or dc current, Ieff), for a specified vs(t) that will deliver the same average power to R as would be delivered by the ac source. The energy delivered in a period T is The average power delivered to the resistor by a periodic current is

Effective Value of a Periodic Waveform (cont.) The power delivered by a direct current is Solve for Ieff rms = root-mean-square The effective value of a current is the steady current (dc) that transfer the same average power as the given time varying current.

Example 11.4-1 Ieff = ? Express the waveform over the period of t = 0 to t = T i(t) = sawtooth waveform

Complex Power A linear circuit is excited by a sinusoidal input and the circuit has reached steady state. The element voltage and current can be represented in (a) the time domain or (b) the frequency domain

Complex Power (cont.) To calculate average power from frequency domain representation of voltage and current i.e. their phasors The complex power delivered to the element is defined to be Apparent power

Complex Power (cont.) The complex power in rectangular form is or real or average power reactive power Volt-Amp Volt-Amp Reactive

Complex Power (cont.) The impedance of the element can be expressed as In rectangular form or resistance reactance

Complex Power (cont.) The complex power can also be expressed in terms of the impedance

The complex power is conserved Complex Power (cont.) The impedance triangle The complex power triangle The complex power is conserved The sum of complex power absorbed by all elements of a circuit is zero.

Complex Power (cont.) The complex power is conserved implies that both average power and reactive power are conserved. or

Example 11.5-1 S is conserved ? Solving for the mesh current Use Ohm’s law to get the element voltage phasors

Example 11.5-1 (cont.) Consider the voltage source supplied by the source For the resistor absorbed by the resistor For the inductor delivered to the inductor

Example 11.5-1 (cont.) For the capacitor delivered to the capacitor The total power absorbed by all elements (except source) For all elements

Example 11.5-2 P is conserved ? The average power for the resistor, inductor, and capacitor is The average power supplied by the voltage source is

Power Factor The ratio of the average power to the apparent power is called the power factor(pf). average power apparent power Therefore the average power

Power Factor (cont.) The cosine is an even function Need additional information in order to find the angle Ex The transmission of electric power Time domain

Power Factor (cont.) Frequency domain We will adjust the power factor by adding compensating impedance to the load. The objective is to minimize the power loss (i.e. absorbed) in the transmission line. The line impedance

Power Factor (cont.) The average power absorbed by the line is The customer requires average power delivered to the load P at the load voltage Vm Solving for Im max pf =1

Power Factor (cont.) compensating impedance A compensating impedance has been attached across the terminals of the customer’s load. corrected The load impedance is and the compensating impedance is We want ZC to absorb no average power so

Power Factor (cont.) The impedance of the parallel combination ZP The power factor of the new combination Calculate for RP and XP

Power Factor (cont.) From Solving for XC Typically the customer’s load is inductive ZC = capacitive

Power Factor (cont.) Solving for Let where

Load = 50 kW of heating (resistive) and motor 0.86 lagging pf Example 11.6-1 I and pf = ? Load = 50 kW of heating (resistive) and motor 0.86 lagging pf Load 1 50 kW resistive load Load 2 motor 0.86 lagging pf P Q

Example 11.6-1 (cont.) To calculate the current

Example 11.6-2 pf ==> 0.95, 1 C = ? We wish to correct the pf to be pfc

Example 11.6-2 (cont.) Or use

The Power Superposition Principle

The Power Superposition Principle (cont.) Let the radian frequency of the 1st source = mw and the radian frequency of the 2nd source = nw integer

The Power Superposition Principle (cont.) For the case that m and n are not integer for example m = 1, n = 1.5

The Power Superposition Principle (cont.) The superposition of average power The average power delivered to a circuit by several sinusoidal sources, acting together, is equal to the sum of the average power delivered to the circuit by each source acting alone, if and only if, no two of the source have the same frequency. If two or more sources are operating at the same frequency the principle of power superposition is not valid but the principle of superposition remains valid. For N sources

Example 11.7-1 P = ?

Example 11.7-1(cont.) Case I These phasors correspond to different frequencies and cannot be added. Using the superposition The average power can be calculated as Since the two sinusoidal sources have different frequencies

Example 11.7-1(cont.) Case II Both phasors correspond to the same frequency and can be added. The sinusoidal current is The average power can be calculated as Power superposition cannot be used here because Both sources have same frequencies

The Maximum Power Transfer Theorem We wish to maximize P set

Coupled Inductors (b) one coil current enters the both coil currents enter the dotted ends of the coils (b) one coil current enters the dotted end of the coil, but the other coil current enters the undotted end

Summary Instantaneous Power and Average Power Effective Value of a Periodic Waveform Complex Power Power Factor The Power Superposition Principle The Maximum Power Transfer Theorem Coupled Inductor and Transformer