Objectives Review heating and cooling load calculation Practice the calculation of cooling load Learn about heating systems

Solar Gain TETD depends on: -orientation, -time of day, -wall properties -surface color -thermal capacity

Glazing Q = U·A·ΔT+A×SC×SHGF Calculate conduction normally Q = U·A·ΔT Use U-values from NFRC National Fenestration Rating Council ALREADY INCLUDES AIRFILMS Use the U-value for the actual window that you are going to use Only use default values if absolutely necessary Tao and Janis - no data Tables 4 and 15, Chapter 31 ASHRAE Fundamentals

Shading Coefficient - SC Ratio of how much sunlight passes through relative to a clean 1/8” thick piece of glass Depends on Window coatings Actually a spectral property Frame shading, dirt, etc. Use the SHGC value from NFRC for a particular window SC=SHGC/0.87 Lower it further for blinds, awnings, shading, dirt

More about Windows Spectral coatings (low-e) Allows visible energy to pass, but limits infrared radiation Particularly short wave Tints Polyester films Gas fills All improve (lower) the U-value

Low-  coatings

Internal gains What contributes to internal gains? How much? What about latent internal gains?

Internal gains ASHRAE Fundamentals ch. 29 or handouts Table 1 – people Table 2 – lighting, Table 3 – motors Table 5 – cooking appliances Table Medical, laboratory, office Tao and Janis - People only - Table 2.17

Summary: Heating and cooling loads Heating - Everything gets converted to a UA, UF, mc p Sum and multiply it by the design temperature difference Cooling loads have additional components Internal gains Solar gain Increased gain through opaque surfaces Also need to calculate latent cooling load

Example problem Calculate the cooling load for the building in Pittsburgh PA with the geometry shown on figure. On east north and west sides are buildings which create shade on the whole wall. Windows: Horizontal slider, Manufacturer: American Window Alliance, Inc, CDP number AMW-K Walls: 4” face brick + 2” insulation + 4” concrete block, Uvalue = 0.1, Dark color Roof: 2” internal insulation + 4” concrete, Uvalue = 0.120, Dark color Below the building is basement wit temperature of 75 F. Internal design parameters: air temperature 75 F Relative humidity 50% Find the amount of fresh air that needs to be supplied by ventilation system.

Example problem Internal loads: 10 occupants, who are there from 8:00 A.M. to 5:00 P.M.doing moderately active office work 1 W/ft2 heat gain from computers and other office equipment from 8:00 A.M. to 5:00 P.M. 0.2 W/ft2 heat gain from computers and other office equipment from 5:00 P.M. to 8:00 A.M. 1.5 W/ft2 heat gain from suspended fluorescent lights from 8:00 A.M. to 5:00 P.M. 0.3 W/ft2 heat gain from suspended fluorescent lights from 5:00 P.M. to 8:00 A.M. Infiltration: 0.5 ACH per hour

Example solution For which hour to do the calculation when you do manual calculation? Identify the major single contributor to the cooling load and do the calculation for the hour when the maximum cooling load for this contributor appear. For example problem major heat gains are through the roof or solar through windows! Roof: maximum TETD=61F at 6 pm (Table 2.12) South windows: max. SHGF=109 Btu/hft 2 at 12 am (July 21 st Table 2.15 A) If you are not sure, do the calculation for both hours: at 6 pm Roof gains = A x U x TETD = 900 ft2 x 0.12 Btu/hFft2 x 61 F = 6.6 kBtu/h Window solar gains = A x SC x SHGF =80 ft2 x 0.71 x 10 Btu/hft 2 = 0.6 kBtu/h total = 7.2 kBtu/h at 12 am Roof gains = A x U x TETD = 900 ft2 x 0.12 Btu/hFft2 x 30 F = 3.2 kBtu/h Window solar gains = A x SC x SHGF =80 ft2 x 0.71 x 109 Btu/hft 2 = 6.2 kBtu/h total= 9.4 kBtu/h For the example critical hour is July 12 AM.

Heating systems

Choosing a Heating System What is it going to burn? What is it going to heat? How much is it going to heat it? What type of equipment? Where are you going to put it? What else do you need to make it work?

Choosing a Fuel Type Availability Emergencies, back-up power, peak demand Storage Space requirements, aesthetic impacts, safety Cost Capital, operating, maintenance Code restrictions Safety, emissions

Selecting a Heat Transfer Medium Air Not very effective (will see later) Steam Necessary for steam loads, little/no pumping But: lower heat transfer, condensate return, bigger pipes Water Better heat transfer, smaller pipes, simpler But: requires pumps, lower velocities, can require complex systems

Choosing Water Temperature Low temperature water (180 °F – 240 °F) single buildings, simple Medium and high temperature (over 350 °F) Campuses where steam isn’t viable/needed Requires high temperature and pressure equipment Nitrogen system to prevent steam formation

Choosing Steam Pressure Low pressure (<15 psig) No pumping for steam Requires pumping/gravity for condensate Medium and high-pressure systems Often used for steam loads

Steam Systems Steam needs bigger pipes for same heat transfer Water is more dense and has better heat transfer properties You can use steam tables and water properties to calculate heat transfer Vary design parameters

What About Air? Really bad heat transfer medium Very low density and specific heat Requires electricity for fans to move air Excessive space requirements for ducts But ! Can be combined with cooling Lowest maintenance Very simple equipment Still need a heat exchanger

Furnace Load demand, load profile Amount and type of heat Response time Efficiency 80 – 85 % is typical Electricity is ~100 % Combustion air supply Flue gas discharge (stack height)

Choosing a Boiler Fuel source Transfer medium Operating temperatures/pressures Equipment Type Space requirements Auxiliary systems

Water Boilers Types Water Tube Boiler Water in tubes, hot combustion gasses in shell Quickly respond to changes in loads Fire Tube Boiler Hot combustion gasses in tubes, water in shell Slower to respond to changes in loads

Electric Types Resistance Resistor gets hot Typically slow response time (demand issues) Electrode Use water as heat conducting medium Bigger systems Cheap to buy, very expensive to run Clean, no local emissions

Auxiliary Burner type (atmospheric or power vented) Feedwater systems Returns steam condensate (including accumulator) Adds water to account for blowdown and leaks Preheats the water Removes dissolved gasses Blowdown system Periodically drain and cool water

Auxiliary Water treatment Dissolved minerals and gasses cause: Reduced heat transfer Reduced flow (increased pressure drop) Corrosion Treatment options Chemical (add bases, add ions, add inhibitor) Temperature (heat to remove oxygen)

Location Depends on type Aesthetics Stack height Integration with cooling systems

Reading Assignment Tao and Janis Chapter 5