Leontief Economic Models Section 10.8 Presented by Adam Diehl

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Presentation transcript:

Leontief Economic Models Section 10.8 Presented by Adam Diehl From Elementary Linear Algebra: Applications Version Tenth Edition Howard Anton and Chris Rorres

Wassilly Leontief Nobel Prize in Economics 1973. Taught economics at Harvard and New York University.

Economic Systems Closed or Input/Output Model Open or Production Model Closed system of industries Output of each industry is consumed by industries in the model Open or Production Model Incorporates outside demand Some of the output of each industry is used by other industries in the model and some is left over to satisfy outside demand

Input-Output Model Example 1 (Anton page 582) 2 1 6 4 5 3   Work Performed by Carpenter Electrician Plumber Days of Work in Home of Carpenter 2 1 6 Days of Work in Home of Electrician 4 5 Days of Work in Home of Plumber 3

Example 1 Continued p1 = daily wages of carpenter p2 = daily wages of electrician p3 = daily wages of plumber Each homeowner should receive that same value in labor that they provide.

Solution 𝑝 1 𝑝 2 𝑝 3 =𝑠 31 32 36

Matrices Exchange matrix 𝐸= .2 .1 .6 .4 .5 .1 .4 .4 .3 Price vector 𝐩= 𝑝 1 𝑝 2 𝑝 3 Find p such that 𝐸𝐩=𝐩

Conditions 𝑝 𝑖  0 for 𝑖=1,2,…,k 𝑒 𝑖𝑗  0 for 𝑖,𝑗=1,2,…,k 𝑖=1 𝑘 𝑒 𝑖𝑗 =1 for 𝑗=1,2,…,k Nonnegative entries and column sums of 1 for E.

Key Results 𝐸𝐩=𝐩 𝐼−𝐸 𝐩=𝟎 This equation has nontrivial solutions if det 𝐼−𝐸 =0 Shown to always be true in Exercise 7.

THEOREM 10.8.1 If E is an exchange matrix, then 𝐸𝐩=𝐩 always has a nontrivial solution p whose entries are nonnegative.

THEOREM 10.8.2 Let E be an exchange matrix such that for some positive integer m all the entries of Em are positive. Then there is exactly one linearly independent solution to 𝐼−𝐸 𝐩=𝟎, and it may be chosen so that all its entries are positive. For proof see Theorem 10.5.4 for Markov chains.

Production Model The output of each industry is not completely consumed by the industries in the model Some excess remains to meet outside demand

Matrices Production vector 𝐱= 𝑥 1 𝑥 2 ⋮ 𝑥 𝑛 Demand vector 𝐝= 𝑑 1 𝑑 2 ⋮ 𝑑 𝑛 Consumption matrix 𝐶= 𝑐 11 𝑐 12 ⋯ 𝑐 1𝑛 𝑐 21 𝑐 22 ⋯ 𝑐 2𝑛 ⋮ ⋮ ⋱ ⋮ 𝑐 𝑛1 𝑐 𝑛2 ⋯ 𝑐 𝑛𝑛

Conditions 𝑥 𝑖  0 for 𝑖=1,2,…,k 𝑑 𝑖  0 for 𝑖=1,2,…,k 𝑐 𝑖𝑗  0 for 𝑖,𝑗=1,2,…,k Nonnegative entries in all matrices.

Consumption 𝐶𝐱= 𝑐 11 𝑥 1 + 𝑐 12 𝑥 2 +…+ 𝑐 1𝑘 𝑥 𝑘 𝑐 21 𝑥 1 + 𝑐 22 𝑥 2 +…+ 𝑐 2𝑘 𝑥 𝑘 ⋮ 𝑐 𝑘1 𝑥 1 + 𝑐 𝑘2 𝑥 2 +…+ 𝑐 𝑘𝑘 𝑥 𝑘 Row i (i=1,2,…,k) is the amount of industry i’s output consumed in the production process.

Surplus Excess production available to satisfy demand is given by 𝐱−𝐶𝐱=𝐝 (I−𝐶)𝐱=𝐝 C and d are given and we must find x to satisfy the equation.

Example 5 (Anton page 586) Three Industries Coal-mining Power-generating Railroad x1 = $ output coal-mining x2 = $ output power-generating x3 = $ output railroad

Example 5 Continued 𝐶= 0 .65 .55 .25 .05 .10 .25 .05 0 𝐝= 50000 25000 0

Solution 𝐱= 102,087 56,163 28,330

Productive Consumption Matrix If (𝐼−𝐶) is invertible, 𝐱= (I−𝐶) −1 𝐝 If all entries of (I−𝐶) −1 are nonnegative there is a unique nonnegative solution x. Definition: A consumption matrix C is said to be productive if (I−𝐶) −1 exists and all entries of (I−𝐶) −1 are nonnegative.

THEOREM 10.8.3 A consumption matrix C is productive if and only if there is some production vector x  0 such that x  Cx. For proof see Exercise 9.

COROLLARY 10.8.4 A consumption matrix is productive if each of its row sums is less than 1.

COROLLARY 10.8.5 A consumption matrix is productive if each of its column sums is less than 1. (Profitable consumption matrix) For proof see Exercise 8.